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Mathematics FC

Discussion in 'General Fanclubs' started by AbnormallyNormal, Jun 6, 2007.

Do you like mathematics?

  1. Yes

    66.7%
  2. No

    33.3%
  1. AbnormallyNormal

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    This is a fan club for discussing mathematics, either specific statements/problems or just general ideas about math.

    Owner: LackingLack
    Co-owners: Creator, reksveks
    Members: gesy hyuga, Edo, xana, infinite, Fonz Kakashi, Calm, nejii
     
    Last edited: Oct 2, 2007
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  2. ~Gesy~

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    this may come in handy...i'll join
     
  3. Edo

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    I wanna join 2
     
  4. Creator

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    Co ownership. I call co ownership.
     
  5. Reksveks

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    I'm better at math then most of my year, Let me be co-owner
     
  6. AbnormallyNormal

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    ok you guys are all in. does anyone have anything about math they're curious about or want to share with us? I'll just put this one out here: 1 + 2 + 3 = 1 * 2 * 3. isnt that weird?
     
  7. J-max

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    Is that the best thing you can come up with? Why bother with this when there are much better math clubs on the internet for those seriously interested in mathematics.
     
  8. AbnormallyNormal

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    no its just one idea and i agree with you there probably are however i am too lazy so decided to make one on here too. do you have any interesting math ideas for us? please share.
     
  9. J-max

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    I can offer this advice: get a copy of Euclid's The Elements and keep solving problems, go as far as you can in math, get PhD, but never stop learning new ideas.
     
  10. ♠Mr.Nibbles♠

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    I'm wit you LackingLack. Right now I'm a psychology/math major in college.

    lol I'm a double major
    Maybe this math symbol could be the banner
     
    Last edited: Jun 12, 2007
  11. AbnormallyNormal

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    whoa dmoney thats an awesome banner thanks man
     
  12. J-max

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    whatever happened to math club? still in existence?
     
  13. Zaru Retired Staff

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    Mathematics stole a year of my life
     
  14. Xana

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    I love Math! Most likely, 105% of this FC knows more Math than I do, but I'll join anyways and listen quietly like a good boy girl :wtf
     
  15. AbnormallyNormal

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    whoa i totally forgot about this awesome FC! i cant believe someone else remembered it exists. great!!! if anyone wants to discuss any math ideas they have, or their favorite like theorem or something please go ahead.

    this is my website: "http://members.aol.com/rayeredcplinnir/Numbers.htm" and
    "http://members.aol.com/rayeredcplinnir/Numbers2.htm".

    its basically all the prime factors of consecutive integers in base two, up to like 5,000. its really fun to do! you might want to check out some of the patterns
     
  16. infinite

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    I wanna join

    I started studying math this year :amuse

    My first question, is 0! = 1 ?
    I know it's a rule, but it doesn't make any sense to me.
     
  17. AbnormallyNormal

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    yes 0! = 1. its because of the definition of factorial. (n + 1)! = n! * (n + 1). if n = 0, then we have 1! = 0! * 1. we know that anything multiplied by 1 is itself, so we have 1! = 0!. and we know that 1! = 1, so therefore we know 0! = 1 also. as for how to explain it "intuitiviely" i often think of the progression of factorials as the ideal set-up for a hierarchical organization such as a government or a corporation. imagine the "emperor" as 0!, the "king" as 1!, the "princes" as 2!, the "governors" as 3!, etc etc. see? it kinda makes sense to not just have 1 supreme leader, but to have another above them. maybe this sounds insane but thats how i make sense of it
     
  18. Fonz_Kakashi

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    I guess I might join.

    Today we had a test, and one question killed me (actually a lot of them killed me) that was essentially looking for a change in variables.
    It had two second-derivative operators (it wasn't actually taking the derivative of anything), each multiplied by a factor. These were set equal to a similar pair, but they were "with respect to" something different from before.

    I think it looked like this:
    Spoiler: to save space

    (1/m)((d^2)/dx^2) + (1/n)((d^2)/dy^2) = (1/v)((d^2)/dX^2) + (1/M)((d^2)/dL^2)

    It just said "Prove this", given the following:

    v = mn/(m+n)
    X = (mx+ny)/(m+n)
    M = m+n
    L = y-x

    So I was stumped. We never really covered any like this in my math classes before. I think you have to use the chain rule in here, but I'm not sure how to relate all these different "with respects". :(


    You can look through it if you're looking for something to pass the time.
     
  19. infinite

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    Thnx, that was a clear explanation :laugh
     
  20. AbnormallyNormal

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    cool guys thx for the extra posts, math FC owns all the other FCs
     
  21. Muk

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    ahhhhh crap i read 0!=1! as in 0 not equal 1 exclamation mark

    that's what i get for programming too much in c++ or java >_>;
     
  22. Fonz_Kakashi

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    lol I remember learning C++

    That is pretty funny.
     
  23. Calm

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    I'll like to join. PM me when im a member please!
     
  24. infinite

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    I just started to learn Java programming :amuse
     
  25. Muk

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    i learned one thing too

    java is used by companies not wanting to buy the fucking license for c++

    but all is good

    hey gimme a formular for the sum from 0 to 100

    without using calulator or factorials

    use series XD

    btw the answer should be 5050 i think can't remember; double check me on the answer :p

    this is coming of the top of my head :p

    so just giving me the answer is like WEAK!

    also give us/me a serie that is easy to calculate in your head

    btw i have a serie somewhere probably on my lifejournal.com or myspace or somewhere written down :p
     
  26. Xana

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    Some of the terms in here confuse me...damn English class for not teaching Math language too :doh
     
  27. AbnormallyNormal

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    isnt it (N(N + 1))/2 with N = 100?
     
  28. Muk

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    yeah it is XD

    you probably back tracked using my answer though XD
     
  29. AbnormallyNormal

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    i think that ((N(N + 1))/2)^2 = 1^3 + 2^3 + 3^3 + ... + n^3. is that right?
     
  30. infinite

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    ((N(N + 1))/2)^2 = (( N^2 + N)/2)^2 =
    N = 1 -> ((1 +1)/2)^2 = 1^2
    N = 2 -> ((4 +2)/2)^2 = 3^2

    That's what I thought, I don't understand why you think it goes to n^3
     
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