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Viewing blog entries in category: Eureka Seven
Half the Coralians and some of the humans who've joined with the Coralians leave the universe for the next one. As such, half the landmass of Earth floats away.
What the planet looks like afterwards.
Looking at my Malak Starforge calc and EMs Father calc for help.
R = (h/2) + c^2/(8h)
= (17/2) + 154^2/(8 X 17)
182.882353 pixels = 6378.1km
1 pixel = 6378.1km/182.882353 = 34.8754262km
34.8754262km X 456 = 15903.1943km (15903194.3m)
15903194.3m/2 = 7951597.15m
34.8754262km X 77 = 2685.40782km
34.8754262km X 3 = 104.626279km
104.626279km/2 = 52.3131395km (53313.1395m)
Diameter of the Earth is 12756.2km.
R = 2685.40782km - 104.626279km
= 2580.78154km + 12756.2km
= 15336.9815km (15336981.5m)
V = 4/3πr^3
= 4/3 X π X 7951597.15^3
V = 4/3πr^3
= 4/3 X π X 7668490.75^3
V = 2.10596776e21 - 1.88894061e21
Sand made of coral weighs 1576kg/m^3 (that's the closest I could find to coral). It says half the lifeforms, which would mean half the scub coral covering the planet.
M = 2.1702715e20 X 1576
Next for our KE.
104.626279km = 47 pixels
1 pixel = 104.626279km/47 = 2.22609104km
2.22609104km X 249 = 554.296669km
2.22609104km X 221 = 491.96612km
554.296669km - 491.96612km = 62.330549km
Timeframe is 5 seconds.
T = 62.330549km/5s
KE = (0.5) X 1.71017394e23 X 12466.1098^2
= 1.32883844e31 joules
Let's also get the GPE. We'll get the added GPE of the planet. Using this calculator, we'll add the radius of the planet (7951597.15m) and it's mass (3.42034788e23kg + 5.97219e24kg = 6314224790000000000000000kg) and we get a gravity acceleration of 6.664807598980779m/s^2.
E = 1.71017394e23 X 6.664807598980779 X 53313.1395
= 6.07662112e28 joules
At last for our total energy.
E = 1.32883844e31 + 6.07662112e28
= 1.33491506e31 joules
= 3.1973708174 zettatons
Coralians leave the Earth = 3.191 zettatons
Eureka Seven planet size = 15903.1943km
Well...that was a lot lower than I expected. Still satisfying though.
The most impressive part of this isn't the love-heart etched onto the Moon, but splitting the sphere itself, which is a colossal blackhole.
The Limit of Questions being reached would result in the universe ripping apart and the creation of a colossal blackhole that would consume everything, including the Earth. The E7 planet has a diameter of 15320.1174km.
623 pixels = 15320.1174km
1 pixel = 15320.1174km/623 = 24.5908787km
24.5908787km X 91 = 2237.76996km
733 pixels = 2237.76996km
1 pixel = 2237.76996km/733 = 3.05289217km
3.05289217km X 66 = 201.490883km
201.490883km/2 = 100.745441km
Entering that through the black hole schwartzchild radius calculator gets a mass of 0.6789895221129004 X 10^32kg, or 6.78989522e31kg. Finally, our energy.
E = mc^2
= 6.78989522e31 X 299792458^2
= 61.0245349 KILOFOE
Nirvash Spec 3 splits open event horizon = 61.023 KILOFOE
(Episode 42, 9:30)
The Ageha Projects Orange drops rockets from orbit which power into the ground to penetrate the coral as deeply as possible and awaken a kute-class and anti-bodies. The radius of the planet is 7660.05871km, and thus the diameter is 15320.1174km.
= 2.57619769 rad
= 147.60525482871816 degrees
Put that through the angscaler gets us a distance of 2225.1km. Let's get the timeframe.
T = 2225.1km/4s
= Mach 1634.70863
Keep in mind the Devilfish & Gekkostates missiles are fast enough in intercept the Orange rockets. Now let's get the energy. The first two knock big holes in the clouds, but we see the third land on the ground and make a hole there. Scaling from the Vodara Shrine...to start with, we'll go with the average height of someone (1.7m, as we are unable to determine their gender).
14 pixels = 1.7m
1 pixel = 1.7m/14 = 0.121428571m
0.121428571m X 122 = 14.8142857m
9 pixels = 14.8142857m
1 pixel = 14.8142857m/9 = 1.64603174m
1.64603174m X 850 = 1399.12698m
Timeframe is 4 frames.
T = 1s/24
= 41.6666667ms X 4
11 pixels = 1399.12698m
1 pixel = 1399.12698m/11 = 127.193362m
127.193362m X 39 = 4960.54112m
4960.54112m/2 = 2480.27056m
T = 4960.54112m/0.166666667s
Volume as a cone.
V = πr^2h^3
= π X 2480.27056^2 X 4960.54112^3
There's no dust, and these missiles were designed to penetrate as deeply as possible, so I'd say it's compression. Looking at TheBlueDash's Kung Fury calc for help. Compression of rock is 200 joules/cm^3.
E = 2.35903916999999999e+24 X 200
= 4.71807834e26 joules
= 112.764778681 petatons
Ageha Squad Orange warheads velocity = Mach 1634.709
Ageha Squads Orange warhead penetration energy = 112.765 petatons
(From episode 48)
Nirvash Type-THEEND makes its last stand, and it's not going out with a whimper.
1. The final charge
(10:55 to 11:35)
THEEND flies towards the coral control cluster, and Type-Zero flies up and meets them. The large round part of the scub control cluster is 271.881362km wide.
= 0.221154498 rad
= 12.6712193557658388 degrees
Putting that through the angscaler gets a distance of 1224.4km. Next we'll get the timeframe.
T = 1224.4km/27s
= Mach 133.26324
That's... a lot less than I thought it would be. Thankfully that's not the only speed feat it has here.
2. I will not forget these days
Type-Zero and the End fight in front of the Control Cluster. Keep in mind how huge it is.
Timeframe is 1 frame.
315 pixels = 97.8749051km
1 pixel = 97.8749051km/315 = 0.310713984km
0.310713984km X 18 = 5.59285171km
T = 1s/24
= Mach 394.453087
3. Surfs up!
THEEND unleashes its signature move, Bascude Crisis, and Dominic is caught in the blast. Note how he's right up near the entrance to the surface, which would mean it reached all the way up there. Volume of the explosion as a semi-sphere. The area inside the scub coral covering is 2580.78154km tall (2580781.54m).
V = 4/3πr^3
= 4/3 X π X 2580.78154^3
Water weighs 1000kg per m^3.
M = 3.6000816e19 X 1000
Let's get the timeframe.
T = 2580.78154km/6s
At last, we can get our glorious, glorious energy.
KE = (0.5) X 3.6000816e22 X 430130.257^2
= 3.33029217e33 joules
= 795.958931644 zettatons
Let's also go for a low end of mist (which would weigh the same as clouds do, 1.003kg/m^3)
M = 3.6000816e19 X 1.003
KE = (0.5) X 3.61088184e19 X 430130.257^2
= 3.34028304e30 joules
= 798.346806883 exatons
Finally for another low end using inverse square-law. We'll need to find the length of Dominics leg. Anemone is 5'1 tall (1.5494m).
82 pixels = 1.5494m
1 pixel = 1.5494m/82 = 0.018895122m
0.018895122m X 38 = 0.718014636m
Next for the timeframe & distance he was flung.
Timeframe is 0.77 seconds.
= 0.0594278931 rad
= 3.40496745999307 degrees
Enter that through the angscaler and we have a distance of 12.079m.
T = 12.079m/0.77s
Dominic is 20, and the average weight of a 20 year old man is 168 pounds (76.2035kg).
KE = (0.5) X 76.2035 X 15.687013^2
= 9376.1692 joules
Finally, we find our energy with inverse square law.
I = S/4pa
9376.1692 = S/(4 X π X 2580781.54^2)
S = 9376.1692 X (4 X π X 2580781.54^2)
S = 7.84761678e17 joules = 187.562542543 megatons
Nirvash Type-Zero intercepts THEEND = Mach 133.263
Nirvash Type-Zero & THEENDs final battle = Mach 394.453
Bascude Crisis (low end) = 187.563 megatons
Bascude Crisis (mid end) = 798.347 exatons
Bascude Crisis (high end) = 795.959 zettatons
20:00 to 21:23, and 22:06
Oratorio Number 8 unleashes a petafuck of energy that creates a huge hole in the ground down to the original surface of the Earth. Let's get down to it.
Spoiler:We get a width on the hole being 100km in diameter in the next episode.
The scub coral layer is 104.626279km (104626.279m) thick. Volume as a cylinder.
V = πr^2h
= π X 50000^2 X 104626.279
The closest we have to coral is calcium. The scub coral layer over the Earth was so big that all of Japan is clearly visible (episode 42). The atmosphere layer between the Earth and the Coralian planet is 2580.78154km wide.
617 pixels = 2580.78154km
1 pixel = 2580.78154km/617 = 4.18279018km
4.18279018km X 351 = 1468.15935km
1468.15935km/2 = 734.079675km
4.18279018km X 66 = 276.064152km
4.18279018km X 383 = 1602.00864km
4.18279018km X 978 = 4090.7688km
4090.7688km/2 = 2045.3844km
4.18279018km X 253 = 1058.24592km
4.18279018km X 178 = 744.536652km
744.536652km/2 = 372.268326km
4.18279018km X 65 = 271.881362km
Volume of the middle bit as a cylinder and the upper and lower parts as conical frustrums.
V = πr^2h
= π X 372.268326^2 X 276.064152
V = (1/3)π(r^2+rR+R^2)h
= (1/3) X π X (372.268326^2 + 372.268326 X 734.079675 + 734.079675^2) X 1058.24592
V = (1/3)π(r^2+rR+R^2)h
= (1/3) X π X (372.268326^2 + 372.268326 X 2045.3844 + 2045.3844^2) X 1602.00864
V = 1.20191031e+23 + 1.05359332e+24 + 8.52836822e+24 + 8.217328739999998e+20
Finally, we can get out energy. It melts, so let's get the energy of melting, using that of sand (sand is basically smashed up coral anyway). It takes 5158.7414 joules/cm^3 to melt sand to glass.
E = 9.7029743e24 X 5158.7414
= 5.00551352e28 joules
Let's also get the kinetic energy of that. In episode 49, the debris from the tower scatter all over the planet in a short period of time (directed by the scub corals to hit human towers).
At the start, a girl who had desperation disease (where her consiousness is inside the Scub Coral control tower) wakes up again, then debris starts to fall (1:55 to 2:40). We can get a timeframe from that.
20 seconds. The Eureka Seven planet is 15903.1943km wide.
C = 2πr
= 2 X π X 7951.59715
T = 24980.6792km/20s
The weight of coral is 1.58g/cm^3.
M = 9.7029743e24 X 1.58
Now we can get our energy.
E = (0.5) X .5330699400000001e+22 X 1249033.96^2
= 4.15817431e33 joules
E = 4.15817431e33 + 5.00551352e28
= 4.15822437e33 joules
= 993.839476577 zettatons
The full power blast overloaded and destroyed Oratorio Number 8, but he lesser blast didn't (episode 48 at 3:00).
Woz says the hole has a diameter of 10.
As we see one of the airforce planes in front of the beam, Dominics ship fit through the hole and we have references to kms throughout the series, I think it's safe to assume he means 10km.
Using the above depth (104626.279m) and a radius of 5km (5000m).
V = πr^2h
= π X 5000^2 X 104626.279
E = 8.21732874e+18 X 5158.7414
= 4.2391074e22 joules
Next is the KE.
M = 8.21732874e+18 X 1.58
We need the timeframe with which all the matter is pushed down and creates a tunnel.
T = 104626.279m/6s
E = (0.5) X 12983379400000000 X 17437.7132^2
= 1.97395303e24 joules
E = 1.97395303e24 + 4.2391074e22
= 2.0163441e24 joules
= 481.917805927 teratons
Oratorio Number 8 destroys the Coral Control Cluster = 993.839 zettatons
Oratorio Number 8 standard shot = 481.918 teratons
Yet another impressive speed feat from the third episode.
Nirvashs' torso is 7.13846155m tall.
= 0.0314105479 rad
= 1.799691826867975353 degrees
Put that through the angscaler gets a distance of 227.24m.
5 pixels = 7.13846155m
1 pixel = 7.13846155m/5 = 1.42769231m
1.42769231m X 107 = 152.763077m
= 0.0157410278 rad
= 0.9018944581403366412 degrees.
That gives 453.48m.
D = 453.48m - 227.24m
Putting both those through the arc calculator, we get a length of 441.55336m (screenshot below as the link usually buggers up).
The timeframe is 1 frame.
T = 1s/24
= Mach 31.9830733
Nirvash flies towards Bell Forest tower = Mach 31.983
The Gekko blows up an enemy plane. These planes are 522.122341m wide.
855 pixels = 522.122341m
1 pixel = 522.122341m/855 = 0.610669405m
0.610669405m X 734 = 448.231343m
448.231343m/2 = 224.115671m
0.610669405m X 979 = 597.845347m
597.845347m/2 = 298.922673m
Volume as an ellipsoid.
V = 4/3πabc
= 4/3 X π X 224.115671 X 298.922673 X 298.922673
The mass of a dust cloud is 1.225kg/m^3.
M = 83883887.4 X 1.225
Now for our timeframe.
T = 1s/24
= 41.6666667ms X 10
Thus we can get our energy.
KE = (0.5) X 102757762 X 717.414415^2
= 2.64438594e13 joules
= 6.32023408222 kilotons
The Gekko destroys an enemy plane = 6.320 kilotons
On top of Nirvash causing sonic booms, the lasers from the plane travel incredibly quickly, which Nirvash then reacts to and dodges. One of those planes is 522.122341m wide.
= 0.264761246 rad
= 15.1697019744625798 degrees
Put that through the angscaler and we get a distance of 1960.5m. Now for the timeframe of the attack.
T = 1s/24
= 41.6666667ms X 8
T = 1960.5m/0.333333334s
= Mach 17.2837873
Nirvash dodges beams = Mach 17.284
Charles' LFO (Spearhead SH-101) demonstrates some impressive speed. We'll start by scaling to Renton, who is 14 years old. The average height of a 14 year old boy is 163.8cm, or 1.638m.
At last we can really get started. At first I thought I had to scale the whole thing, but I only need to do two points of the zig-zag maneuver.
4 pixels = 15.35m
1 pixel = 15.35m/4 = 3.8375m
170 + 136 = 306
3.8375m X 306 = 1174.275m
The timeframe is 5 frames.
T = 1s/24
= 41.6666667ms X 5
T = 1174.275m/0.208333333s
= Mach 16.563872
Spearhead SH-101 attacks bandits = Mach 16.564
Both Nirvash and Charles' Spearhead cause sonic booms, so this is definately some degree of transonic. We can scale of the passing clouds. Nirvash's main body is 7.13846155m tall.
6 pixels = 7.13846155m
1 pixel = 7.13846155m/6 = 1.18974359m
396 - 234 = 162 pixels
1.18974359m X 162 = 192.738462m
The timeframe is 3 frames.
T = 1s/24
= 41.6666667ms X 3
= Mach 4.53115784
Spearhead chases Nirvash = Mach 4.531
Lot's of scaling here, so let's get down to it.
Spoiler:First we need to scale from the Gekko to the mine entrance. From the previous episode, we get a shot of the tip of the Gekko and we can scale from Woz (from episode 18). The average height of a man is 1.77m. Nivash coming up to the wing while fully erect also speaks for the size of the Gekko.
96 pixels = 1.77m
1 pixel = 1.77m/96 = 0.0184375m
0.0184375m X 651 = 12.0028125m
Next we scale to the Gekko (from episode 3). May as well get the airforce plane while we're at it for possible future reference.
12 pixels = 12.0028125m
1 pixel = 12.0028125m/12 = 1.00023437m
1.00023437m X 176 = 176.041249m
1.00023437m X 353 = 353.082733m
1.00023437m X 522 = 522.122341m
Those are some big planes (and it makes sense, as they contain several LFOs each, which are over a dozen metres tall, as well as a take off ramp). The lines on the ground in the mine take up half of the Gekko's width.
So we can scale from the tarmac, then to the mine entrance.
74 pixels = 176.041249m
1 pixel = 176.041249m/74 = 2.3789358m
2.3789358m X 405 = 963.468999m
963.468999m/2 = 481.7345m
91 pixels = 481.7345m
1 pixel = 481.7345m/98 = 4.91565816m
4.91565816m X 197 = 968.384658m
Now to scale the size of the mountain and the amount blown off the top.
48 pixels = 968.384658m
1 pixel = 968.384658m/48 = 20.1746804m
512 + 292 = 804 pixels
20.1746804m X 804 = 16220.443m
20.1746804 X 105 = 2118.34144m
20.1746804m X 723 = 14586.2939m
14586.2939m/2 = 7293.14695m
20.1746804m X 360 = 7262.88494m
20.1746804m X 265 = 5346.29031m
16220.443m - 7262.88494m = 8957.55806m
Volume as a cone.
V = πr^2h/3
= π X 7293.14695^2 X 7262.88494/3
This is clearly violent fragmentation, but we'll calc the KE later, so we'll go with fragmentation, or 8000000 joules/m^3.
E = 4.04545813e11 X 8000000
= 3.2363665e18 joules
I'll add everything together at the end. The above is rather a tall mountain, so I'll redo it with another shot from earlier in the episode for a low end.
44 pixels = 968.384658m
1 pixel = 968.384658m/44 = 22.0087422m
22.0087422m X 402 = 8847.51436m
22.0087422m X 980 = 21568.5674m
The shot of explosion itself is the only thing I have to scale the top getting blown off, so I'll use the above pixels with the lower values.
804 pixels = 8847.51436m
8847.51436m/804 = 11.0043711m
804 - 360 = 444 pixels
11.0043711m X 105 = 1155.45897m
11.0043711m X 723 = 7956.16031m
7956.16031m/2 = 3978.08016m
11.0043711m X 360 = 3961.5736m
11.0043711m X 444 = 4885.94077m
Once again, the volume as a cone.
V = πr^2h/3
= π X 3978.08016^2 X 3961.5736/3
E = 6.56513116e10 X 8000000
= 5.25210493e17 joules
We ain't done yet! Nirvash blew it up from under the mountain, at least 800m below.
We also see the top of the mountain, and the insides have been hollowed out.
554 pixels = 7956.16031m
1 pixel = 7956.16031m/554 = 14.3613002m
14.3613002m X 340 = 4882.84207m
4885.94077m + 800m = 5685.94077m
Volume as a cylinder.
V = πr^2h
= π X 3978.08016^2 X 5685.94077
Fragmentation once again.
E = 2.82682722e11 X 8000000
= 2.26146178e18 joules
8957.55806m + 800m = 9757.55806m
V = πr^2h
= π X 7293.14695^2 X 9757.55806
E = 1.63050053e12 X 8000000
= 1.30440042e19 joules
The hole is empty, so naturally we can conclude that all the rocks & dirt were pushed out of the top. We're gonna need a timeframe.
T = 9647.51436m/4s
Let's go with a low end of 2.2 tons/m^3 for sandstone (2200kg/m^3).
M = 2.82682722e11 X 2200
Now for the kinetic energy.
KE = (0.5) X 6.21901988e14 X 2411.87859^2
= 1.80885117e21 joules
T = 17020.443m/4s
M = 1.63050053e12 X 2200
KE = (0.5) X 3.58710117e15 X 4255.11075^2
= 3.24739686e22 joules
The last part we need to do is the clouds. Scaling from the valley the mountains are sitting in.
219 pixels = 21568.5674m
1 pixel = 21568.5674m/219 = 98.4866091m
98.4866091m X 979 = 96418.3903m
96418.3903m/2 = 48209.1951m
The timeframe is 5 seconds.
T = 96418.3903m/5s
Volume of the clouds as a cylinder, and thickness as nimbostratus (nimbostratus are dark clouds that usually have a thickness of 6500 to 10,000 feet, or 2000 to 3000m thick), and they don't seem like cumulonimbi, so we'll go with that.
V = πr^2h
= π X 48209.1951^2 X 2500
Density of a cloud is 1.003kg/m^3.
M = 1.82536468e13 X 1.003
KE = (0.5) X 1.83084077e13 X 19283.6781^2
= 3.40408445e21 joules
This is low end, but I'm just going to scale it to both.
Now for our final energy results!
E = 5.25210493e17 + 2.26146178e18 + 1.80885117e21 + 3.40408445e21
= 5.21572229e21 joules
= 1.24658754541 teratons
E = 3.2363665e18 + 1.30440042e19 + 3.24739686e22 + 3.40408445e21
= 3.58943334e22 joules
= 8.57895157744 teratons
Nirvash hollows out a mountain (low end) = 1.247 teratons
Nirvash hollows out a mountain (high end) = 8.579 teratons
Consistent with the collapse of the Coralian.
Coralians aren't afraid to unleash some cloud-based biggatons.
1. The Coralian says hi
A huge cumulo-nimbus has formed (so big it dwarves the nearby government tower), the ground is quaking and the airforce warns of great incoming destruction.
Everyone in a 100km radius was evacuated, and all the trapar waves are being pulled to the centre, where the Coralian is.
It's refering to the LFOs 606 & 808, but I can't find any closer reference, so let's go with Gekkostate as seen there.
Volume as a sphere.
= 1.40940166 rad
= 80.75276675693253 degrees
The angscaler gives us a diameter of 51.021km, and a radius of 25.5105km, or 25510.5m. Obviously, the volumes as a sphere.
V = 4/3πr^3
= 4/3 X π X 25510.5^3
Mass of a cloud per m^3 is 1.003kg.
M = 6.9541735e13 X 1.003
The energy to condense clouds is 2,500,000 joules per kg.
E = 6.97503602e13 X 2,500,000
= 1.74375901e20 joules
= 41.6768405832 gigatons
2. The Coralian says bye
The flash is pretty nice looking, but there's an easy way to get the energy from this, and that's from the shrinking of the cloud.
673 pixels = 51.021km (51021m)
1 pixel = 51021m/673 = 75.8112927m
57 X 75.8112927m = 4321.24368m
51021m - 4321.24368m = 46699.7563m
46699.7563m/2 = 23349.8782m
The timeframe is 2 seconds.
T = 23349.8782m/2s
Finally for our energy.
KE = (0.5) X 6.97503602e13 X 11674.9391^2
= 4.75363363e21 joules
= 1.13614570507 teratons
Kute-class Coralian manifests = 41.679 gigatons
Kute-class Coralian colapses = 1.136 teratons
Both Nirvash Type-Zero & THE-END survived the collapse at ground zero, so this scales to both of them.
Nirvash Type-Zero takes off at impressive speeds.
Spoiler:Let's find the length of the board for this. Nirvash Type-Zero's body is 7.13846155m tall.
66 pixels = 7.13846155m
1 pixel = 7.13846155m/66 = 0.108158508m
0.108158508m X 172 = 18.6032634m
Now to scale the take off...
23 pixels = 18.6032634m
1 pixel = 18.6032634m/23 = 0.808837539m
477 + 489 + 457 + 216 + 23 = 1662
0.808837539m X 1662 = 1344.28799m
= 0.0344558431 rad
= 1.974174389199856217 degrees
Putting that through the angscaler gets a distance of 539.86m. On top of that, we can also add the distance it took off with, as it was much closer to the "camera" a moment before. Eureka is 14 at the start of the series, and the average height of a 14 year old girl is 156.7cm (1.567m).
513 pixels = 1.567m
1 pixel = 1.567m/513 = 0.0030545809m
0.0030545809m X 306 = 0.934701755m
Now to scale her to the hubcap.
416 pixels = 0.934701755m
1 pixel = 0.934701755m/416 = 0.00224687922m
0.00224687922m X 302 = 0.678557524m
Then we scale the hubcap to the windsail, or whatever it is.
64 pixels = 0.678557524m
1 pixel = 0.678557524m/64 = 0.0106024613m
0.0106024613m X 169 = 1.79181596m
Now we sail whatever that to the rest of the windsail thing.
62 pixels = 1.79181596m
1 pixel = 1.79181596m/62 = 0.0289002574m
0.0289002574m X 188 = 5.43324839m
5.43324839m/2 = 2.7166242m
Now we can angscale the distance.
= 0.0184256067 rad
= 1.055709498880591068 degrees
That's a distance of 147.43m.
D = 539.86m - 147.43m
Putting those values through the arc calculator gets our results.
L = 3915.20004m/2
Now for the timeframe. I couldn't find any version of this on Youtube, and I'm not sure how to get less than a second outside that, so I'll have to go with a rounded off version.
T = 1957.60002m/1s
= Mach 5.75274037
Nirvash Type-Zero takes off = Mach 5.753
And this is still in its first form in the 3rd episode.
Even in the firt episode, Eureka Seven has some great feats.
A KLF blows the top of a hill off during training/testing. There's a lot here, so I better get it all organised.
Spoiler:We can see the hill earlier in the episode without the dust cloud and a van nearby (5:03). Dimensions of a van are here, the smallest having an external height of 1.80m, and the largest having an external height of 3.30m. That gets an average of 2.55m tall.
12 pixels = 2.55m
1 pixel = 2.55m/12 = 0.2125m
0.2125m X 17 = 3.6125m
49 pixels = 3.6125m
1 pixel = 3.6125m/49 = 0.0737244898m
0.0737244898m X 99 = 7.29872449m
0.0737244898m X 76 = 5.60306122m
0.0737244898m X 565 = 41.6543367m
41.6543367m/2 = 20.8271684m
0.0737244898m X 171 = 12.6068878m
Oblate dome dimensions calculator is here, and we get a volume of 1272.57m^3. Violent fragmentation of rock is 69000000 joules per m^3.
E = 1272.57 X 69000000
= 87807330000 joules
= 20.9864555449 tons of TNT
Not bad, but we can get even more. Let's also get the energy of the dust cloud.
1 pixel = 0.0737244901m
0.0737244901m X 323 = 23.8130103m
23.8130103m/2 = 11.9065051m
0.0737244901m X 402 = 29.637245m
0.0737244901m X 437 = 32.2176022m
32.2176022m/2 = 16.1088011m
0.0737244901m X 533 = 39.2951532m
39.2951532m/2 = 19.6475766m
0.0737244901m X 711 = 52.4181125m
52.4181125m/2 = 26.2090562m
0.0737244901m X 478 = 35.2403063m
35.2403063m/2 = 17.6201532m
0.0737244901m X 429 = 31.6278063m
The middle one as a cylinder, the other two as ellipsoids.
V = πr^2h
= π X 11.9065051^2 X 29.637245
V = 4/3πabc
= 4/3 X π X 26.2090562 X 17.6201532 X 17.6201532
V = 4/3πabc
= 4/3 X π X 16.1088011 X 16.1088011 X 19.6475766
V = 13199.4644 + 34084.6902 + 21356.2029
Weight of a dust cloud per m^3 is 1.225kg.
M = 68640.3575 X 1.225kg
Now for the time frame.
T = 31.6278063m/0.36s
E = (0.5) X 84084.4379 X 87.8550175^2
= 324503039 joules
= 0.0775580877151 tons of TNT
Not much in comparison, but we ain't done yet! Several massive chunks of earth were flung into the air.
1 pixel = 0.0737244901m
0.0737244901m X 136 = 10.0265307m
0.0737244901m X 83 = 6.11913268m
0.0737244901m X 90 = 6.63520411m
It appears rectangular, so volume of a rectangular prism.
V = lhw
= 10.0265307 X 6.11913268 X 6.11913268
Loose moist dirt weighs 1250kg per m^3.
M = 375.431257 X 1250kg
We're going to need the timeframe again.
T = 6.63520411m/0.24s
Putting that through the kinetic energy calculator and we get 179347998.98229057 joules, or 0.042865200521579965853 tons of TNT. Finally, we add everything together.
E = 20.9864555449 + 0.0775580877151 + 0.042865200521579965853
= 21.1068788 tons of TNT
KLF destroys a hilltop = 21.107 tons of TNT
Not as much as I thought it would be, but it's just the first episode, and these are just canon fodder who get wreaked by all the Nirvash types. So still I'm satisfied.
Nirvash Type-Zero flies towards Bell Forest Tower at this speed. Too simple. A knot is equal to 0.514444444m/s.
T = 0.514444444 X 135
Nirvash Type-Zero's travel speed = 69.45m/s
It's capable of moving much faster in combat. Expect more calcs of this series in the future.
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