# Viewing blog entries in category: Fairy Tail calcs

• ### Tartarus cube scaling (Fairy Tail)

Every goddamn time.

That image is fine. I think. Whatever, I don't give a shit.

(60.7/.9)118 = 1.75m

This is where he fucked up. His lines were drawn fat, and his pixel values were therefore inaccurate. I'm using the thinnest lines available to me. I'm changing nothing about his method of scaling, I'm simply using thinner lines. I think we can all agree that that yellow line is within the boundaries of that window.

(1.75/3)232.2=135.45m

(135.45/9.85)179.3=2465.6m

Welp, there you go. Alternate scaling of the Tartarus Cube achieved.

Note how all of my Fairy Tail calculations have been to either spite RH or to correct him.
• ### Jellal's meteor... (Fairy Tail)

...doesn't deserve a good title.

No, not teratons

I'll be calculating the KE of the thing.

Angsizing using an altitude of 2km...

2atan(tan(70/2)*(755/405))=105.089080502558

2atan(126/(755/tan(105.089080502558/2)))=24.578895932076

d=871.37m

So the diameter of the hole thing in which Jellal forms his meteor is 871.37m.

The ring looks like dispersal of whatever energy or light crap Jellal used to form the thing, and the sphere was the same diameter as the hole I scaled. If not, fuck if I know how to scale this shit

Anyway,

(871.37/228)77=294.28m

(4/3)pi*(294.28/2)^3=13343841.184m^3

A quick Google search tells me that 3000kg/m^3 is a low-end for meteor density.

13343841.184*3000=40031523552kg

Now I'm gonna calc the KE two ways. The first will use final velocity of free-fall. The height we used was 2000m.

h=.5gt^2
2000=.5(9.8)t^2
4000=9.8t^2
408.163=t^2
t=20.2s

vfinal=a*t
v=9.8*20.2
v=197.96m/s

KE=.5mv^2
KE=.5(40031523552)197.96^2
KE=784380907024991.0016J

Now, there's also the fact that the thing ablated. In one of Alpha's blogs, it was established that this occurs in an Earth-like atmosphere between 2-4km/s. I'll use 2km/s.

KE=.5(40031523552)2000^2
KE=80063047104000000J

Given the nature of the feat, I don't think ablation would be so preposterous, but I would also understand concerns of inflation.

Whichever is acceptable is up to you fucks. Now go give RH an ulcer
• ### Gajeel and the hare (Fairy Tail)

I'll challenge that.

Spoiler:

Natsu should be around average dude height, maybe a little smaller (this is a height comparison chart by Mashima, btw).

(1.7/291)80=0.467354m

I know perspective fucks with things, but I'll take a low-end in this scan.

(0.467354/216.53)264.2=0.57m

I'll be generous and scale from the arrow itself rather than its apparent trajectory or Gajeel himself, because actually fuck low-ends.

(0.467354/19.647)21=.5m

.57-.5=.07m

Now to angsize for a distance.

2atan(tan(70/2)*(469/440))=73.472197981908

2atan(19.647/(440/tan(73.472197981908/2)))=3.817529816452

d=7.0117

http://www.fieldandstream.com/articles/hunting/2013/08/fs-crowns-best-flagship-compound-bow-2013

Some of these compound bows (obviously around the same grade as Sagittarius's) have firing velocities of 300fps, or 91.44m/s.

7.0117/91.44=0.07668

.07/0.07668=0.918m/s

There you go, Gajeel is only a little slower than normal humans tend to walk. Not too shabby, if I do say so myself.

Granted, it could be negative distance just based on the wonky scaling, but I don't think this is too outlandish.
• ### Motherglare's Roar (Fairy Tail)

RH likes his trip gigatons so I'm gonna organize this. Plus, accepted calcs don't like RH's blog

http://www.narutoforums.com/blog.php?b=21137

I don't really mind using his radius of 14km.

2*atan(tan(70/2)*(770/189) = 141.364237292408

Ignore his 47px value and look at my 17px value.

2*atan(17/(770/tan(141.364237292408/2)))=7.207643128082

Plug those numbers into the Angsize calculator and we get...

1763.5m

Use these measurements to scale the last panel in the next scan, rather than the scaling that's already there. Ignore all lines but the red one.

Dunno if I really agree with scaling from two different panels, but whatever.

(446/55.9464)*1763.5=14058.474m

Height of rock mass
(97.94/55.9464)*1763.5=3087.19m

Length of rock
(13.03/55.9464)*1763.5=410.722m

Width of rock
(6/55.9464)*1763.5=189.13m

vellipsoid4/3)pi*r1*r2*r3
v4/3)pi*(410.722/2)*(189.13/2)^2
v=7692498.736 m^3

For density (rho) I'll use 2700kg/m^3.

m=v*rho
m=7692498.736*2700
m=20769746587.2 kg

PE=mgh
PE=20769746587.2*9.8*6773.223
PE=1378645627828226.54688 J

Now we calc the area of the cross section, which is an ellipse.

Aellipse=pi*r1*r2
A=pi*(410.722/2)*(189.13/2)
A=61009.613 m^2

Now the surface area of the blast.

SAsphere=4*pi*r^2
SA=4pi*(14058.474/2)^2
SA=620906543.5516 m^2

(1378645627828226.54688/61009.613)620906543.5516=
14030741213804284767 J