# Viewing blog entries in category: Feats/Respect

• ### Borderlands - Troy phaselocks Elpis

Troy phaselocks Elpis. Note that Elpis gets progressively closer in later shots. This is Elpis before Troy phaselocked it...

...and this is after...

...and this is during the battle with Troy.

The map markers also note the moon is falling.

So yes, Elpis is definately getting closer. Unfortunately, we don't have a usable timeframe. Fortunately, we don't need one. Using the method I used previously in my Mom, Please Don't Come Adventuring With Me! calcs (and the method used in the calc here), where I calced the energy to move a planet out of orbit.
Although here, we'll replace the Sun's mass and orbital distance with those of the planet, given it's a moon being moved in a planets orbit, not a planet being moved in a stars orbit. Although the same logic should apply. Assuming Pandora is Earth-sized, Earth has a weight 5.9736e24kg. Now, for Elpis, given the Pre-Sequel shows Elpis to be similar in gravity to Earth's moon Luna, I think it's a safe bet to use the values for the Moon here. The Moon has a mass of 7.35e22kg and a diameter of 3475km. The gravitational constant of the Earth in ngs is 6.674×10^−8 (6.67400e-8). Now to find the distance from Pandora to Elpis.

204 pixels = 3475km
1 pixel = 3475km/204 = 17.0343137km
17.0343137km X 1494 = 25449.2647km (25449264.7m)

Now let's get our velocity.

V = (GM(2/r - 1/a))^(1/2)
= ((6.674×10^−8) X (5.9736e24)/(25449264.7))^(1/2)
= 125162.305m/s

So that's Elpis's initial velocity. Now we need to calculate the change in velocity needed to bring it closer to Pandora. To do that, we need Elpis's new distance to Pandora.

= 2*atan(551/(1080/tan(70/2)))
= 27.1791912877833255 degrees

We put this through the angscaler, and we can determine that Elpis is now 7187.7km (or 7187700m) away. To calculate the velocity of a similar satellite in an orbit of this distance...

V = (GM(2/r - 1/a))^(1/2)
= ((6.674×10^−8) X (5.9736e24)/(7187700))^(1/2)
= 235513.713m/s

All that's left now is to calculate the kinetic energy of both.

KE = (0.5)mv^2
= (0.5) X 7.35e22 X 125162.305^2
= 5.75710895e32 joules

KE = (0.5)mv^2
= (0.5) X 7.35e22 X 235513.713^2
= 2.03840156e33 joules

Lastly? We just subtract the energy, and that's the energy required to move the

E = 2.03840156e33 - 5.75710895e32
= 1.46269067e33 joules
= 349.59146032504781942 zettaons

Final Results
Troy phaselocks Elpis = 349.591 zettatons

Well, calcing moving planets is way harder than I remembered. Anyway, even when cut off from his Eridium supply, Troy uses Tyreen's power, and the Vault Hunters defeat him.
• ### Rick and Morty - Heistotron's ship size

Spoiler:

Heistotron ship grows big enough to contain the Earth and many other planets, several of which are much bigger than the Earth. The diameter of the Earth is 12756.2km.

125 pixels = 12756.2km
1 pixel = 12756.2km/125 = 102.0496km
102.0496km X 2871 = 292984.402km

Now to the very next frame, there are two potential points we can scale from, so we'll go for a low end and a high end.

Next onto the size of the ship.

(Low end)
326 pixels = 292984.402km
1 pixel = 292984.402km/326 = 898.72516km
898.72516km X 903 = 811548.819km
898.72516km X 1320 = 1186317.21km

(High end)
192 pixels = 292984.402km
1 pixel = 292984.402km/192 = 1525.96043km
1525.96043km X 903 = 1377942.27km
1525.96043km X 1320 = 2014267.77km

Final Results
Heistotrons ships width (low end) = 811548.819km
Heistotrons ships width (high end) = 1377942.27km
Heistotrons ships height (low end) = 1186317.21km
Heistotrons ships height (high end) = 2014267.77km
• ### Rick and Morty - Son of a bitch, I'm in!

Ricks spaceship tows the Earth away from Heistotrons collapsing ship. The diameter of the Earth is 12756.2km.

= 2*atan(438/(493/tan(70/2)))
= 45.6578114468321345 degrees

If we enter these values into the trusty anscaler, then we can determine that the Earth is currently 15151km away.

The timeframe is 3 seconds and 1 frame.

T = 1s/24
= 41.6666667ms + 3s
= 3.04166667s

= 2*atan(621/(493/tan(70/2)))
= 61.660339948634871 degrees

The Earth is now 10687km away. Next we determine how far the Earth moved in the timeframe given.

D = 15151km - 10687km
= 4464km

T = 4464km/3.04166667s
= 1467616.44m/s

The Earth has a mass of 5.9736 X 10^24kg (or 5.9736e24kg).

KE = (0.5)mv^2
= (0.5) X 5.9736e24 X 1467616.44 ^2
= 6.43326259e36 joules
= 1.5375866610898663112 ninatons

Final Results
Rick's spaceship tows the Earth = 1.538 ninatons
• ### Borderlands - Skywell 27s power

Skywell-27, a satalite laser powered by a fragment of the Vault Key, fires upon Promethia, causing a colossal explosion. Assuming Promethia is Earth-like is size. Earth has a diameter of 12,742km.

866 pixels = 12,742km
1 pixel = 12,742km/866 = 14.7136259km
14.7136259km X 80 = 1177.09007km
1177.09007km/2 = 588.545035km

Now, entering those values into the nuke calculator and messing around, we get our match with the radius for widespread destruction at 616500 megatons, or 616.5 gigatons. This is with one fragment of the Vault Key too, which in total is comprised of three parts.

E = 616500 X 3
= 1849500 megatons
= 1.8495 teratons

Now let's get the speed of the laser.
= 2*atan(866/(1080/tan(70/2)))
= 41.6064935697393921 degrees

Enter that through the angscaler and we have a distance of 16,769km. Next we get our timeframe.

Spoiler:

Timeframe is 5 frames.
T = 1s/24
= 41.6666667ms
= 0.208333333s

T = 16769km/0.208333333s
= 80491200.1/299792458 X 100
= 26.8489743% C

Final Results
Skywell-27s firepower = 616.5 gigatons
Vault Key's power = 1.85 teratons
Skywell-27 laser speed = 26.849% C

Though no one reacts to the laser, this backs up that lasers in Borderlands are legitimately lasers, and other showings of reacting to lasers are relativistic to lightspeed. On top of Skywell-27 being very explicitly weaker than the Helios, the creatures of the Vault are the power of the Vault, this would scale to the Rampager and back to the Vault Hunters and Maya, which is consistent with other feats in previous installments.
• ### Demon Slayer: Kimetsu no Yaiba - Tanjiro splits a boulder

Calc request for a friend elsewhere.

Tanjiro splits a boulder in half with his sword. This calc is also on VBW, but given my friend wants me to try again with different scaling as the VBW calc has the boulder too small, so I may as well do so. Tanjiro is 165cm tall.

407 + 251 = 658 pixels
658 pixels = 165cm
1 pixel = 165cm/658 = 0.250759878cm
0.250759878cm X 116 = 29.0881458cm

100 pixels = 29.0881458cm
1 pixel = 29.0881458cm/100 = 0.290881458cm
0.290881458cm X 883 = 256.848327cm (2.56848327m)
256.848327cm/2 = 128.424163cm

Next we need the area cut.

A = πr^2
= π X 128.424163^2
= 51813.5514cm^2 (5.18135514m^2)

Next for the MPa. The MPa of medium strength rock is between 40 MPa to 80 MPa, or an average of 60 MPa (or 60000000 N/m^2).

Now the energy to change that from tensile force to sheer force;
https://en.wikipedia.org/wiki/Shear_force
F = 60000000 X 5.18135514 X 0.6
= 186528785 N

To change that from newtons to joules, we times that by our diameter.

E = 186528785 X 2.56848327
= 479096064 joules
= 0.114506707457 tons of TNT

Final Results
Tanjiro cuts a boulder in half = 0.115 tons of TNT
• ### Symphogear XV - Yggdrasil increases the Earths orbital speed

Yggdrasil's propulsion power forcibly increased the Earth's orbital speed. The gauge constantly gets higher, but the highest speed we get is 3122m/s. This will be more or less straightforward. The Earth weighs The Earth has a mass of 5.9736e24kg.

KE = (0.5)mv^2
= (0.5) X 5.9736e24 X 3122^2
= 2.91119931e31 joules
= 6.9579333413001904773 zettatons

Final Results
Yggdrasil's core increases the Earth's orbital speed = 6.958 zettaons
• ### Animorphs - Spaceship speed calcs

Saw an Animorphs debate that had some surprisingly impressive feats for Animorphs. Note that I don't really know the complete context, I just feel like calcing the feats. Because why not?

1. Andolite fighter reaches one-tenth the speed of light.
This one does itself; 10% C.

2. Skrit Na in-atmosphere speed
A Skrit Na ship escapes some Yeerk ships by flying through the atmosphere of a planet, where one has to deal more with atmospheric drag. The highest speed reached is three thousand five hundred miles an hour, or 1564.64m/s.

T = 1564.64/340.29
= Mach 4.59796056

3. Blade ship flies several thousand miles in seconds
The Blade ship flies a few thousand miles in seconds. For our estimates, a few is more than a couple, so we'll use 3000 miles (or 4828.032km) and 3 seconds as our low end, and 9000 miles (14484.096km) and 9 seconds as our high end .

(Low low end)
T = 4828.032km/9s
= 536448/340.29
= Mach 1576.44362

(High low end)
T = 4828.032km/3s
= 1609344/340.29
= Mach 4729.33086

(Low high end)
T = 14484.096km/9s
= 1609344/340.29
= Mach 4729.33086

Which is exactly the same as the one before it.

T = 14484.096km/3s
= 4828032/340.29
= Mach 14187.9926

Final Results
Andolite fighter accelerates to one-tenth the speed of light = 10% C
Skrit Na in-atmosphere speed = Mach 4.598
The Blade ship traverses thousands of miles in seconds (low end) = Mach 1576.444
The Blade ship traverses thousands of miles in seconds (mid end) = Mach 4729.331
The Blade ship traverses thousands of miles in seconds (high end) = Mach 14187.993
• ### Madoka Magica Side Story - Momoko Togame jumps into space

Momoko Togame jumps into space in seconds. The closest distance to space from the surface is 62 miles (or 99.779328km).
Spoiler:

Timeframe is 1.23 seconds.

T = 99.779328km/1.23s
= 81121.4049/340.29
= Mach 238.389036

Let's also get kinetic energy. She is 16 years old, and the average mass of a 16 year old Japanese girl is 52.6kg.

KE = (0.5)mv^2
= (0.5) X 52.6 X 81121.4049^2
= 1.73071945e11 joules
= 41.3651876195029 tons of TNT

Final Results
Momoko Togami jumps into space (speed) = Mach 238.389
Momoko Togami jumps into space (energy) = 41.365 tons of TNT

And that's not even opening the can of worms that is the attacks name; Edge of Universe. • ### Childhood's End - The Overlords ship speed

An excrusiatingly agonizing calc. The Overlords ships can reach speeds exceeding 99% the speed of light.

Final Results
Overlord's ships speed = 99% C
• ### The Reckoners - Regalia floods Manhattan

The High Epic Regalia uses her water powers to flood Manhattan, raising the water around Manhattan around 100 feet, which she also sustains. 100 feet is 30.48m (half of which is 15.24m), and Manhattan has a surface area of 59.1km^2, or 5.91e+7m.

V = 5.91e+7 X 30.48
= 1801368000m^3

Weight of water is 1000kg/m^3.

M = 1801368000 X 1000
= 1801368000000kg

We'll get our energy with GPE.

E = 15.24 X 9.807 X 1801368000000
= 2.69230083e14 joules
= 64.3475341778202647 kilotons

Final Results
Regalia floods Manhattan = 64.348 kilotons
• ### DC - Green Lanterns survive a supernova

Calc request for @Veggie and @Claudio Swiss .

A bunch of novice Green Lanterns survive a supernova. In order to go supernova, a star needs to have at least 8 solar masses. Red Giants at their highest weigh 8 solar masses, and have a diameter of at least 100,000,000.

= 2*atan(184/(666/tan(70/2)))
= 14.9156553528899174 degrees

Enter this into the angscaler, and we have a distance from the Sun to the Green Lanterns as 381960000km (or 381960000000m) away. Looking at ChaosTheory123's Ood Bnar calc for reference. The average surface area of a man is 1.9m^2.

A = 4πr^2
= 4 Xπ X 381960000000^2
= 1.83335106e24m^2

A = 1.9/1.83335106e24
= 1.03635362e-24m^2

The energy of a supernova is 10^44 joules.

E = 10^44 X 1.03635362e-24
= 1.03635362e20 joules
= 24.769445984703629904 gigatons

Final Results
Green Lanterns survive a supernova = 24.769 gigatons

Not as impressive as the supernova itself, I'm afraid.
• ### She-Ra calcs, part 2

In season the season 3 the scope really goes up, namely with the introduction of Horde Prime and his fleets. So let's get us some calcs. Also because this is on Netflix and I couldn't find any other versions of this scene, I couldn't really make any gifs I'm afraid, though still images should work.
Spoiler:

1. First planetary bombardment
Horde Primes fleets bombs a planet and creates some considerable explosions with super fast lasers.
Spoiler:

Timeframe is 1 second (though in actuality it would be even less, at it travels across the screen in only part of a second). First off, to find the radius of the planet, assuming it's Earth-sized (which has a radius of 6378.1km, or a diameter of 12,742km).

R = (h/2) + c^2/(8h)
= (292/2) + 1506^2/(8 X 292)
= 1116.90582

6378.1km = 1116.90582 pixels
1 pixel = 6378.1km/1116.90582 = 5.71050834km
5.71050834km X 2100 = 11992.0675km

T = 11992.0675km/1s
= 11992067.5/340.29
= Mach 35240.7285

And keep in mind that would be a low end, and I was unable to calculate or pause from fractions of a second.

5.71050834km X 474 = 2706.78095km
2706.78095km/2 = 1353.39047km

Enter that through the nuke calculator using the above radius of 1353.39047km and playing around and find that for the widespread destruction airburst we get a result of 7710100 megatons, or 7.710100 teratons. Going for a high end of fireball radius, we get 548490000 megatons, or 548.490000 teratons.

2. Second planetary bombardment and giant ships
Similar to the first, but this time we have a much, much bigger ship. Once again assuming an Earth-like size for the planet...
Spoiler:

542 pixels = 12,742km
1 pixel = 12,742km/542 = 23.5092251km
23.5092251km X 90 = 2115.83026km
23.5092251km X 51 = 1198.97048km
2115.83026km - 1198.97048km = 916.85978km
23.5092251km X 710 = 16691.5498km
23.5092251km X 100 = 2350.92251km
2350.92251km/2 = 1175.46125km
23.5092251km X 2613 = 61429.6052km
23.5092251km X 2013 = 47324.0701km
23.5092251km X 1086 = 25531.0185km
23.5092251km X 726 = 17067.6974km

First off for the explosion. Once again messing around with the nuke calculator for a radius of 1175.46125km, we get a low end of 5029000 megatons and a high end of 385290000 megatons, or 5.029000 teratons and 385.290000 teratons respectively.

Next for the speed of the lasers (remember again that this was a low end, and the lasers flew this distance in a fraction of a second.

T = 16691.5498km/1s
= 16691549.8/340.29
= >Mach 49050.9559

Let's also get the cruising speed of the ship.

T = 916.85978km/1s
= 916859.78/340.29
= Mach 2694.34829

Final Results
Ships shoots planet = >Mach 35240.726
Bombardment explosion on first planet (low end) = 7.710 teratons
Bombardment explosion on first planet (low end) = 548.49 teratons
Giant ship length = 61429.605km
Bombardment explosion on second planet (low end) = 5.029 teratons
Bombardment explosion on second planet (high end) = 385.29 teratons
Giant ship shoots second planet = >Mach 49050.956
Giant ship cruising speed = Mach 2694.348

There's also the kinetic energy the giant ship would generate, but unfortunately we can't see the other side of the ship, and thus can't scale its full dimensions.
• ### American Gods - Shadow thinks of snow

Mr Wednesday tells Shadow to think of snow, which he does, and this creates snow. Shadow imagines that the snow will cover Chicargo, and that there will be 12 inches of it, so this should be relatively straight forward. Chicargo covers an area of 606.1km^2, or 6.061e+8m^2. 12 inches is 30.48cm, or 0.3048m.

V = 6.061e+8 X 0.3048
= 184739280m^3

Newly fallen snow weighs between 70kg to 150kg per m^3 (or an average of 110kg), while snowpacks range from 200kg to 300kg per m^3 (or an average of 250kg).
https://www.islandnet.com/~see/weather/almanac/arc2007/alm07feb.htm
(Low end)

M = 184739280 X 110
= 20321320800kg

(High end)

M = 184739280 X 250
= 46184820000kg

This scene if I recall correctly took place before Christas and Winter, so is likely at some point in Autumn, the temperatures of Autumn being variable, and an average will be gathered below (from the temperatures in celcius).

T = −18 + 21 + 21 + 22 + 24 + 32 + 34 + 37 + 38
= 211/9
= 23.4444444

Specific heat of air between 0 and 40 degrees celsius is 1.005 kilojoules. We can also add the heat fusion of oxygen, which is is 13800 joules/kg.

(Low end)
E = 23.4444444 X 1.005 X 20321320800
= 4.78804186e11 kilojoules
= 4.78804186e14 joules

E = 20321320800 X 13800
= 2.80434227e14 joules

E = 4.78804186e14 + 2.80434227e14
= 7.59238413e14 joules
= 181.462335803059261 kilotons

(High end)
E = 23.4444444 X 1.005 X 46184820000
= 1.08819133e12 kilojoules
= 1.08819133e15 joules

E = 46184820000 X 13800
= 6.37350516e14 joules

E = 1.08819133e15 + 6.37350516e14
= 1.72554185e15 joules
= 412.4144000956022751 kilotons

Final Results
Shadow thinks of snow (low end) = 181.462 kilotons
Shadow thinks of snow (high end) = 412.414 kilotons
• ### The Simpsons - Nuclear test inspection

2:07
Spoiler:

Homer Simpson accidentally causes a test simulation to melt into the ground, which he quite literally shakes off a few seconds later. Also of note...
https://www.simpsonsarchive.com/episodes/1F02.html
There wasn't anything nuclear at all in the truck, so it's possible that Homer himself caused this, somehow. Homer Simpson is 5'11" feet tall, or 180.34cm.

1586 pixels = 180.34cm
1 pixel = 180.34cm/1586 = 0.11370744cm
0.11370744cm X 492 = 55.9440605cm

230 pixels = 55.9440605cm
1 pixel = 55.9440605cm/230 = 0.243235046cm
0.243235046cm X 184 = 44.7552485cm

63 pixels = 44.7552485cm
1 pixel = 44.7552485cm/63 = 0.71040077cm
0.71040077cm X 464 = 329.625957cm
0.71040077cm X 1317 = 935.597814cm

1077 pixels = 935.597814cm
1 pixel = 935.597814cm/1077 = 0.868707348cm
0.868707348cm X 258 = 224.126496m
0.868707348cm X 335 = 291.016962cm

And on top of that, given we can no longer see the inspection van, we can add its height too as it would have sunk below that.

H = 329.625957 + 224.126496m
= 553.752453cm

Volume of the area as a rectangular prism.

V = lhw
= 935.597814 X 291.016962 X 553.752453
= 150772857cm^3

Energy to melt rock is 4350 joules per cm^3.

E = 150772857 X 4350
= 655861927950 joules
= 156.754762894359 tons of TNT

Final Results
Homer fails inspection = 156.755 tons of TNT
• ### Little Shop of Horrors - Mean Green Mother From Outer Space

First off, I'll like to note that I'm not entirely sure of the background of this feat, how it was done or if it would scale entirely to Audrey II, but it's worth bringing up in anycase.

1:03

https://littleshop.fandom.com/wiki/Da-Doo

Audrey II arrives during a mysterious Solar Eclipse (that's clearly noted as being sudden), and visibly zaps down to Earth during it. All we need here is the diameter of the Moon (3474.8km) and its mass (7.34767309e22kg), and we have both, so let's get down to it!
Spoiler:

Timeframe is 0.92 seconds.

69 pixels = 3474.8km
1 pixel = 3474.8km/69 = 50.3594203km
50.3594203km X 10 = 503.594203km

T = 503.594203km/0.92s
= 547385.003m/s

Now we just need our kinetic energy.

T = (0.5)mv^2
= (0.5) X 7.34767309e22 X 547385.003^2
= 1.1007929e34 joules
= 2.6309581739961762636 yottatons

As well as that, what about the speed at which Audrey II arrived on Earth. In Mean Green Mother From Outer Space, Twoey confirms it came from "past the stars and beyond the Moon," and given it arrives the a Solar Eclipse, I think it's safe to calculate the distance from the Earth to the Moon (that being 384,400km).
Spoiler:

3.12 seconds.

T = 384,400km/3.12s
= 123205128/299792458 X 100
= 41.096807% C

Final Results
Solar Eclipse = 2.631 yottatons
Audrey II arrives on Earth = 41.097%C

No idea if this scales to Audrey alone or it's entire race, but it's definately worth looking into.