# Viewing blog entries in category: Star Wars

• ### Star Wars - TIE Fighter destroys an asteroid

0:49

A TIE Fighter blows up a huge asteroid. The Millennium Falcon is 34.75m long.

83 pixels = 34.75m
1 pixel = 34.75m/83 = 0.418674699m
0.418674699m X 238 = 99.6445784m
99.6445784m/2 = 49.8222892m
0.418674699m X 170 = 71.1746988m
71.1746988m/2 = 35.5873494m

Volume as an ellipsoid.

V = 4/3πabc
= 4/3 X π X 49.8222892 X 35.5873494 X 35.5873494
= 264303.9m^3

Violent fragmentation of rock is 69000000 joules.m^3.

E = 264303.9 X 69000000
= 1.82369691e13 joules
= 4.3587402246653919 kilotons

Final Results

TIE Fighter destroys asteroid = 4.359 kilotons
• ### Re: Infant of Shaa's power (Star Wars)

Calc request for @Kaaant , and another high end of a calc that ChaosTheory123 did.

The high end has the destruction of Coruscant light up the galaxy, and is visible from the Outer Rim. The Star Wars galaxy is 100,000 lightyears (9.46073e+20m) in diameter.

877 pixels = 9.46073e+20m
1 pixel = 9.46073e+20m/877 = 1.07876055e18m
1.07876055e18m X 351 = 3.78644953e20m

It's noted to be very bright and a beacon, so let's assume it has a lux comparable to the full Moon (0.3 lux).

L = -2.5 log I - 14.2
= -2.5 log 0.3 - 14.2
= -12.8928031

-12.8928031 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(3.78644953e20))^2)

Going through that formula step by step...

(146000000000/(3.78644953e20))^2) = 1.48676171e-19
-12.8928031 - -26.73 = 1.48676171e-19/((L/3.846*10^26)
13.8371969 = -2.5Log(1.48676171e-19/((L/3.846*10^26))
13.8371969/-2.5 = (1.48676171e-19/((L/3.846*10^26))
10^(-5.53487876) = (1.48676171e-19/((L/3.846*10^26))
2.91824157e-6 = (1.48676171e-19/((L/3.846*10^26))
2.91824157e-6 X (3.864*10e26) = 1.48676171e-19
1.12760854e22/1.48676171e-19 = 7.58432594e40 joules = 18.126974044 tenatons

Final Results
Infant of Shaa's power = 18.126 tenatons
• ### Star Wars - Republic gunship power

The Republic Gunship packs a Hell of a punch. Thankfully we have the exact joulage for each. The anti-personal turret is 5000000000 joules or 1.195028680688 tons of TNT, the pinpoint laser turrets are 300000000000 joules or 71.701720841300186748 tons of TNT and the light air-to-air rockets are 600000000000 joules or 143.4034416826003735 tons of TNT.

Also...
Elsewhere on the page...
Final Results
Republic gunship anti-personal turret = 1.195 tons of TNT
Republic gunship pinpoint laser turrets = 71.702 tons of TNT
Republic gunship light air-to-air rockets = 143.403 tons of TNT
Republic gunship missiles = 100 kilotons
Republic gunship mass driver barrels = Mach 5
• ### Re:Malak charges the Star Forge (Star Wars)

Redoing Chaos's Star Forge calc with a high end. I'm just going to use his scans again if he doesn't mind.

The diameter of the Sun is 1391000km.

117 pixels = 1391000km
1 pixel = 1391000km/117 = 11888.8889km
11888.8889km X 56 = 665777.778km
665777.778km/2 = 332888.889km
11888.8889km X 130 = 1545555.56km

V = πr^2h/3
= π X 332888.889^2 X 1545555.56/3
= 1.79354319e17km^3
= 1.79354318999999945e+32cm^3

The density of the Corona (outermost layer of the Sun) is 1x10^-15g/cm^3.

M = 1.79354318999999945e+32 X 1 x 10^-15
= 1.79354319e17g
= 179354319000000kg

Next for the speed. Well use planet curvature scaling (looking at Endless Mike calc request of Father for help).
Spoiler:

R = (h/2) + c^2/(8h)
= (48/2) + 1248^2/(8 X 48)
= 4080

4080 pixels = 695500km
1 pixel = 695500km/4080 = 170.465686km
170.465686km X 47 = 8011.88724km

T = 8011.88724km/1s
= 8011887.24/340.29
= Mach 23544.2923

Let's get our energy.

E = (0.5) X 179354319000000 X 8011887.24^2
= 5.7564071e27 joules
= 1.37581431644 exatons

Final Results

Malak charges the Star Forges production power = 1.376 exatons
Star Forge drains Abo = Mach 23544.292
• ### Star Wars - The tragedy of Darth Plagueis the wise

Darth Plaguies's death causes a tremour that rocks multiple nearby star systems. They flared, so we can apply solar flares to them, as solar flares unleash the equivilent of seizemic energy upon a star (refering to this for help).
http://soi.stanford.edu/press/agu05-98/press-rel.html
The average power of solar flares is massive.
https://en.wikipedia.org/wiki/Solar_flare
Now for the surface area of the Sun in meters (the radius of the Sun is 695500km, or 695500000m), and the surface area of the quakes.

A = 4πr^2
= 4 X π X 695500000^2
= 6.07860794e18m^2

It says the nearby stars, so it's not limited to the nearest. The top 26 stars closest to the Earth are within 11.7 lightyears of Earth (1.1069e+14km, or 110690000000000000m).

A = 4πr^2
= 4 X π X 110690000000000000^2
= 1.53966642e35m^2

Now for the inverse square law, plus the amount of stars it affected (let's go with 26 for now as a low end).

I = 1.0e20/6.07860794e18
= 16.451135 X 1.53966642e35
= 2.53292601e36 X 26
= 6.58560763e37 joules
= 15.7399799952 ninatons

Next is the high end.

I = 1.0e25/6.07860794e18
= 1645113.5 X 1.53966642e35
= 2.53292601e41 X 26
= 6.58560763e42 joules
= 1.57399799952 tenakilotons

The stars flare, so we can also get luminousity (which are also assumably pretty bright too given the description). Looking at Agent9149s Sailor Moon, Endless Mikes revisions, Bernkastels Madoka calcs and Tacocats Percy Jackson constellation calc for help. The apparent magnitude of Sirius (the brightest star seen from Earth sans the Sun) is -1.46. The apparent magnitude of the Sun is -26.74. The closest star to the Sun is Barnards Star, which is 5.9630 lightyears away (5.64143e+16m), or 1.8282641 parsecs. The distance from the Sun to the Earth is 0.000004731537734207877 parsecs.

A = 4πr^2
= 4 X π X 5.64143e+16^2
= 3.99933949e34m^2
= 3.99933948999999979e+38cm^2

1.46 lux equals 2.1316e-7 watts per cm^3 (0.00000021316).

E = 3.99933948999999979e+38 X 0.00000021316
= 8.52499206e31 joules

On top of that, let's find the amount of time they shined for (keep in mind a distant constellation was affected).
Dawn is soon on it's way. Though the stars would probably continue to shine like so, it's a good enough place to start. There's a constellation low in the sky that would vanish soon. Palpatine also sends a good bit of time evilly musing. It would be at least 10 minutes.

(Low end)
E = 60 X 10
= 600 X 8.52499206e31
= 5.11499524e34 X 26
= 1.32989876e36 + 6.58560763e37
= 6.71859751e37 joules
= 16.0578334369 ninatons

(High end)

E = 60 X 10
= 600 X 8.52499206e31
= 5.11499524e34 X 26
= 1.32989876e36 + 6.58560763e42
= 6.58560896e42 joules
= 408.852019598 tenatons

Final Results
Darth Plagueis dies (low end) = 16.059 ninatons
Darth Plagueis dies (high end) = 1.574 tenakilotons
• ### Star Wars - The power to destroy a planet is insignificant next to the power of the Force

An out of control comet once destroyed at least one planet (possibly several) and continued with enough velocity to still be a threat. The Jedi teamed up to stop it. It's unknown how many Jedi did this, but at a low end we can go with all of them. I couldn't find a definitive answer to how many Jedi there are in the galaxy, but this is a good enough answer.
http://scifi.stackexchange.com/questions/40252/how-many-jedi-were-there-at-the-time-of-the-purge
While we can't find the speed of Kinro, it had enough velocity to destroy several planets, so we can use the GBE of the Earth (2.24e32 joules).

E = 2.24e32/10000
= 2.24e28 joules
= 5.35372848948 exatons

Final Results
Minimum energy needed by individual Jedis to stop Kinro = 5.354 exatons

And there's other factors to take into account; the weaker Jedi were killed or lost their minds so it's actually a smaller number of Jedi who stood together to do this. That though should be the minimum amount of energy needed by everyone to stop it. Also, this is Disney Canon, so would scale to high tiers.
• ### Star Wars - Good, our first catch of the day

2:20 - 2:50

The first ships escape and the ION Cannon destroys a Star Destroyer. Let's get the timeframe first.
Spoiler:

16 seconds. Hoth is 7,200km in diameter, or 3600km in radius.

= 2*atan(499/(363/tan(70/2)))
= 1.15462217 rad
= 66.15497727340076 degrees

The angscaler gives us 5527.1km, but we'll need to subtract the radius of Hoth for our final distance (1927.1km).

T = 1927.1km/16s
= 120443.75/340.29
= Mach 353.94443

Pretty impressive. Even though energy/particle beams in Star Wars are explicitly light speed, having calcs is always good to counter subsonic claims.
Spoiler:

1.71 seconds.

T = 1927.1km/1.71s
= 1126959.06/340.29
= Mach 3311.76073

Final Results
Rebel Ships escape Hoth = Mach 353.944
ION Cannon blasts Star Destroyer = Mach 3311.761
• ### Star Wars - Jar Jar's the key to all this

1:50

The Naboo Royal Starship flies towards Coruscant and enters its atmosphere (on the daylight side of the planet, which is further away). This should be simple enough. Coruscant is 12,240km in diameter.

= 2*atan(268/(698/tan(70/2)))
= 0.359910176 rad
= 20.6213340886618077 degrees

Put that through the angscaler and we have us 33641km.

= 2*atan(543/(166/tan(70/2)))
= 1.99559448 rad
= 114.3391413238878 degrees

Coruscant is is 3948.7km away from the starship, which means it travelled 29692.3km. Next for the timeframe.
Spoiler:

3.8 seconds.

T = 29692.3km/3.8s
= 7813763.16/340.29
= Mach 22962.0711

Final Results
Naboo Starship flies to Coruscant = Mach 22,962.0711
• ### Star Wars - It's a trap!

1:05-1:25
Spoiler:

The Rebel Fleet approaches the Second Death Star. Note in both gifs you can visibly see Endor and the Death Star getting closer. The Second Death Star is over 160km in diameter, and Endor is 4900km in diameter.

= 2*atan(10/(766/tan(70/2)))
= 0.0123709838 rad
= 0.7088051601664716594 degrees

Entering that through the angscaler gets a distance of 12933km.

= 2*atan(13/(766/tan(70/2)))
= 0.0160821374 rad
= 0.921438598571780898 degrees

The Second Death Star is now 9948.7km away, and the fleet has moved 2984.3km. Now for a timeframe.
Spoiler:

4 seconds.

T = 2984.3km/4s
= 746075/340.29
= Mach 2192.46819

Niiice! Now let's go to the next shot.

= 2*atan(84/(765/tan(70/2)))
= 0.103959698 rad
= 5.95645193486940094 degrees

The Second Death Star is 1537.7km away, and the fleet has traveled 8411km. Again we get a timeframe.

12 seconds.

T = 8411km/12s
= 700916.667/340.29
= Mach 2059.76275

This is surprisingly consistent. For the last one, the full view of the Death Star is obscured, so we'll get the dish and scale from that.

967 pixels = 160km
1 pixel = 160km/967 = 0.165460186km
0.165460186km X 297 = 49.1416752km

Next to scaling the distance (in the above video at 1:43).

= 2*atan(157/(767/tan(70/2)))
= 0.193368901 rad
= 11.0792219164105283 degrees

That's 824.85km away, and now the Rebel Fleet has come a further 7586.15km. Once again we get the timeframe.

20 seconds.

T = 7586.15km/20s
= 379307.5/340.29
= Mach 1114.65956

Not as great as the first two times, but still pretty consistant with them, and much greater than others would say Star Wars ships are capable of.

Final Results
The Rebel Fleet approaches the Second Death Star (low end) = Mach 1114.66
The Rebel Fleet approaches the Second Death Star (mid end) = Mach 2059.763
The Rebel Fleet approaches the Second Death Star (high end) = Mach 2192.468
• ### Star Wars - Burning through the sky!

It's about time I did this.

At 1:53, the ship leaves hyperspace, so this is all outside hyperspace. 2:34 to 2:46, the spaceship leaves the stars orbit and crashes towards the planet.
Spoiler:

The planet has grass, so it would be in the habitable zone. The closest distance for a habitable zone is 0.725 AU (
108458000km).
https://en.wikipedia.org/wiki/Circumstellar_habitable_zone
Now we need the timeframe.
Spoiler:

3.46 seconds.

T = 108458000km/3.46s
= 3.13462428e10/299792458
= 104.559811 C

Final Results
Akosha flies starship around a star = 104.56 C

I'm pretty sure spaceships in SW enter hyperspace at FTL speeds, so I'll need to check up with Chaos and Fang. We still have our results though.
• ### Star Wars - X-Wings in hyperspace

4:30

An X-wing jumps through hyperspace towards the galaxy. According to Wookiepedia, Star Wars Battlefront is canon, so I guess it's fine? The Star Wars Galaxy is over 100,000 lightyears in diameter.

= 2*atan(673/(673/tan(70/2)))
= 0.884961621 rad
= 50.704565914481698 degrees

With the angscaler, we can determine that the galaxy is 105530 lightyears away. How long did it take to fly there?
Spoiler:

8.22 seconds.

T = 105530 lightyears/8.22 seconds
= 1.21456151e20/299792458
= 405134111000C

Final Results
X-wings fly into the galaxy = 405134111000 C
• ### Star Wars - Death Star run

An iconic scene, in which the Rebels blow up the Death Star and save the day.
1. First Death Star Run

13:22 - 12:35
At 13:22, the torpedoes go down the chute, at 13:26 the Death Star starts messing up and finally at 13:33 it explodes.
13:26 seems to be when the chain reaction starts, which is 4 seconds later. The first Death Star was 160km in diameter, or 80km in radius.

T = 80km/4s
= 20000/340.29
= Mach 58.7733992

Not bad. Now let's see how the second Death Star run goes.
2. Second Death Star run

The escape goes from 7:33 to 8:09.
Spoiler:

36 seconds. The Second Death Star is between 160km wide (80km in radius) to 900km wide (450km in radius).

T = 80km/36s
= 2222.22222/340.29
= Mach 6.53037768

T = 450km/36s
= 12500/340.29
= Mach 36.7333745

Not as high as other feats that I've seen, but keep in mind Lando had to navigate winding paths when he did this, so this is pretty damn impressive.
3. Getting the Hell outta there
Something else impressive I noticed; let's go back to the First Death Star exploding.

Luke is in the trench, he fires the torpedos, the Death Star starts its chain reaction, Luke and his friends fly away, Tarkin has some second thoughts and it explodes. Here's a hint; Luke is in the trench, then flying away from the Death Star 8 seconds later. Ok that's not really a hint but I'm sure you've got it now.

= 2*atan(148/(765/tan(70/2)))
= 0.182821311 rad
= 10.4748895253746355 degrees

Fire this info into the angscaler! 872.73km Jackson!

T = 872.73km/8s
= 109091.25/340.29
= Mach 320.583179

Final Results

X-wing torpedos blow up Death Star = Mach 58.773
The Millennium Falcon escapes the Second Death Star exploding (low end) = >Mach 6.530
The Millennium Falcon escapes the Second Death Star exploding (high end) = >Mach 36.733
Luke flies away from the Death Star = Mach 320.583
• ### Star Wars - Playing catch

Spoiler:

Jedi Padawan Rivi-Anu temporarily halts the fall of a Venator-Class Star Destroyer. We have all the dimensions for a Venator-Class Star Destroyer below).

Volume as a triangular prism (it's not exactly that shape, but as we have the upper control room and the missing bits, it's close enough), then multiply by the hollowness value .of 0.15

V = 1/2blh
= 1/2 X 548 X 1137 X 268
= 83492184 X 0.15
= 12523827.6m^3

From what I know, Star Destroyers are made of durasteel (steel weighs 7850kg/m^3).

M = 12523827.6 X 7850
= 98312046660kg

Let's star by getting the GPE.

Centre of gravity = 1137m/3 = 379m X 2 = 758m
Earths Gravity Pull = 9.807m/s²
Mass = 98312046660kg

E = 758 X 9.807 X 98312046660
= 7.30822851e14 joules
= 174.670853489 kilotons

Now let's get the velocity. This is the formula that we'll be using.

Vi is the velocity, g is the acceleration due to gravity and d is the distance.

= 2*atan(214/(394/tan(70/2)))
= 0.503770658 rad
= 28.8639325460000009 degrees

Put that through the angscaler and we get 2209m. Gravitational pull of the Earth is 9.807m/s.

Vi = sqrt(2gd)
= sqrt(2 X 9.807 X 2209)
= 208.15217m/s

Entering the mass and speed into the kinetic energy calculator we get 2.130E+15 joules, or 509.082217973 kilotons. Now we add the upper GBE to this to get our final results.

E = 177.4360913 kilotons + 509.082217973 kilotons
= 686.518309 kilotons

Final Results
Rivi-Anu halts Star Destroyer = 686.518 kilotons
• ### Star Wars - Star Destroyer chase

My second Star Wars calc, this time for the movies.

2:38

This may not look like much, but keep in mind these things are huge.
Spoiler:

3.96 seconds. A quick search reveals that Star Destroyers are 1015m wide.

= 2*atan(42/(634/tan(70/2)))
= 0.0627561094 rad
= 3.595660207290192201 degrees

That a distance of 16168m.

= 2*atan(85/(638/tan(70/2)))
= 0.126084273 rad
= 7.22409670589319841 degrees

Which gets us 8039.5m.

T = 16168 - 8039.5
= 8128.5m/3.96s
= 2052.65152m/s
= Mach 5.984406763848395983

I guess these are those local slugs. There are better speed feats in the movies, but we're not done yet! An Imperial Star Destroyer weighs 892,000 megatons (892,000,000,000,000kg).

Entering that into the kinetic energy calculator, we get 1.8791667051010064e+21 joules, or 449.131621678 gigatons. A Star Destroyers deadweight is 359,000 megatons (359,000,000,000,000kg), which gives us a total mass of 1.25100e15kg, and an engine output of 629.89199408 gigatons.

Final Results
Imperial Star Destroyers chase the Millenium Falcon = Mach 5.984
Star Destroyer engine output = 449.132 gigatons
Star Destroyer engine output = 629.892 gigatons

I'm pretty sure there are much higher calcs for Star Destroyers around here, but there you go.
• ### Star Wars - Belsavis's power core

The World Razor is one of the most powerful beings in Star Wars (though still below the Ones & the Bedlam Spirits). It destroyed 100 stars and 1000 planets, took the full might of the Infinite Empire to enprison and is said to be a threat to the entire galaxy. The technology needed to enprison it within Belsavis is immensly powerful, as shown below...

14:00
Also at about the 10:30 mark or so refers to the planet being ripped apart, so it's indeed an explosion.

It refers to the nearby systems, so lets go with the second closest to the Sun, Barnards Star, 5.9630 lightyears away, or 56414300000000km (5.64143e+16m). Now we need the GBE of Barnards Star, and the radius of Barnards Star is 136,400km. In order to find the GBE, we'll need to know the size (272,800km in diameter, or 136,400km in radius, or 136400000m) and mass (2.86400e29kg) of Barnards Star.

U = 3GM^2/5R
= (3 X 6.67408e-11 X 2.86400e29^2)/(5 X 136400000)
= 2.40809888e40 joules

Next for the surface area of Barnards Star.

V = 4πr^2
= 4 X π X 136400000^3
= 3.18898866e25m^3

Now for the cross-sectional surface area of Barnards Star.

A = πr^2
= π X 136400000^2
= 5.84492057e16m^2

Then the surface area of the explosion.

A = 4πr^2
= 4 X π X 5.64143e+16^2
= 3.99933949e34m^2

Next we divide the total surface area of the explosion by the cross-sectional surface area of Barnards Star, then time sit by the GBE of Barnards Star before finally dividing by FOE (inverse square-law basically).

I = 3.99933949e34/5.84492057e16
= 6.84241889e17 X 2.40809888e40
= 1.64772213e58/10^44
= 164.772213000000 TERAFOE

Final Results
Belsavis's Power Core = 164.772 TERAFOE