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Viewing blog entries in category: Trigger-verse

  • TTGL




    The detonation of the Klaxosaur Bomb causes an explosion seen all the way back on Earth. Strelizia True Apus is noted to be so far from Earth that there are no recognisable stars, and the sky and perspective is completely different (there are also noticably more stars in the sky than in space in the Solar System).
    Spoiler:


    The light is clearly visible in the middle of the day and from across the Universe, which would mean if'd have to be at least comparable to the luminousity of the Sun, with the apparent magnitude of the Sun being -26.74. The furthest star visible to the naked eye is Casopiea, 16,308 lightyears away (or 1.54282297e20m).
    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(1.54282297e20))^2)
    (146000000000/(1.54282297e20))^2) = 8.9551635e-19
    -26.74 - -26.73 = 8.9551635e-19/((L/3.846*10^26)
    -0.01 = -2.5Log(8.9551635e-19/((L/3.846*10^26))
    -0.01/-2.5 = (8.9551635e-19/((L/3.846*10^26))
    10^(0.004) = (8.9551635e-19/((L/3.846*10^26))
    1.00925289 = (8.9551635e-19/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 9.46317256e-10
    3.89975317e27/8.9551635e-19 = 4.12097861e36 joules

    The light lasts three days.

    T = 60 X 60 X 24 X 3
    = 259200s

    The light lasts 3 days.

    E = 4.35475374e45 X 259200
    = 1.12875217e51/10^44
    = 11.2875217 MEGAFOE

    Final Results
    Klaxosaur Bomb = 11.288 MEGAFOE
  • TTGL
    (Episode 23)

    Strelizia True Apus spams a ton of beams real fast. More or less straight forward. Previously I calced Strelizia Apus' arm protectors to be 85840.8839m long.

    144 pixels = 85840.8839m
    1 pixel = 85840.8839m/144 = 596.117249m
    596.117249m X 1732 = 1032475.08m
    Spoiler:



    Timeframe is 1 frame.

    T = 1s/24
    = 41.6666667ms
    = 1032475.08m/41.6666667ms
    = 24779401.9/340.29
    = Mach 72818.4839

    Final Results
    Strelizia True Apus' beam spam = Mach 72818.484
  • TTGL
    (Episode 21)

    Chlorophytum blasts open the way, melting a heap of rubble in the way. However, this leaves her depowered and even turns Ikuno's hair white, so this should be the absolute maximum output of Chlorophytum and most other non-Strelizia mechs (outside the Nine Models and the Space Franxx). Previously I calced Strelizia to be 54.969m tall.

    550 pixels = 54.969m
    1 pixel = 54.969m/550 = 0.0999436364m
    0.0999436364m X 50 = 4.99718182m

    Scaling from Strelizia to Delpinium to the corridor.

    364 pixels = 4.99718182m
    1 pixel = 4.99718182m/364 = 0.0137285215m
    0.0137285215m X 564 = 7.74288613m

    173 pixels = 7.74288613m
    1 pixel = 7.74288613m/173 = 0.0447565672m
    0.0447565672m X 2662 = 119.141982m

    Now to scaling the dimensions of the attack.

    1199 pixels = 119.141982m
    1 pixel = 119.141982m/1199 = 0.0993677915m
    0.0993677915m X 941 = 93.5050918m
    93.5050918m/2 = 46.7525459m

    = 2*atan(941/(1612/tan(70/2)))
    = 0.539683688 rad
    = 30.9215975945318178 degrees

    Enter that through the angscaler and the closer end of the melted rubble is 169.03m away.

    = 2*atan(430/(1612/tan(70/2)))
    = 0.251446322 rad
    = 14.4068130247232382 degrees

    The hole at the further end of the tunnel is 369.91m away. Now we can get the total length of the melted metal.

    L = 369.91m - 169.03m
    = 200.88m

    Volume of the tunnel as a cylinder (obviously).

    V = πr^2h
    = π X 46.7525459^2 X 200.88
    = 1379421.86m^3
    = 1379421860000cm^3

    Energy to melt steel is 7309.87 joules/cm^3.

    E = 1379421860000 X 7309.87
    = 1.00833945e16 joules
    = 2.4099891252390057694 megatons

    Final Results
    Chlorophytum blasts opens a path = 2.41 megatons
  • TTGL
    (Episode 24)

    Stelitzia rams Hringhorni through the VIRM fleets and into the VIRM home planet at incredible speeds. Thankfully, we already have the dimensions for Strelizia Apus sorted, but now we need Hringhorni's dimensions. This should be much easier than Strelizia Apus's dimensions. Strelizia Apus' arm protectors are 85840.8839m long, and those on Strelizia True Apus should be a similar length.

    505 pixels = 85840.8839m
    1 pixel = 85840.8839m/505 = 169.981948m
    169.981948m X 2166 = 368180.899m
    169.981948m X 123 = 20907.7796m

    36 pixels = 20907.7796m
    1 pixel = 20907.7796m/36 = 580.771656m
    580.771656m X 1096 = 636525.735m
    580.771656m X 276 = 160292.977m

    It's not a perfect triangle, but given there's also other pyramidal parts sticking out, I figures it'd even out.

    503 pixels = 160292.977m
    1 pixel = 160292.977m/503 = 318.673911m
    318.673911m X 92 = 29317.9998m

    With all that done, let's get our volume by adding all three triangular parts together as triangular pyramids. To get that though, we need the area of the triangle first.

    A = hbb/2
    = 636525.735 X 160292.977/2
    = 5.10153025e10m^2

    V = 1/3AH
    = 1/3 X 5.10153025e10 X 29317.9998
    = 4.98555543e14 X 3
    = 1.49566663e15m^3

    Now for the shaft.

    812 pixels = 636525.735
    1 pixel = 636525.735/812 = 783.898688m
    783.898688m X 319 = 250063.681m
    783.898688m X 32 = 25084.758m
    25084.758m/2 = 12542.379m

    Volume as a cylinder.

    V = πr^2h
    = π X 12542.379^2 X 250063.681
    = 1.23583455e14m^3

    There are other bits too, but...eh. Let's get our total volume.

    V = 1.49566663e15 + 1.23583455e14
    = 1.61925008e15m^3

    Hringhorni is made out of Klaxosaur cores, which are composed of some form of weird goo, so we'll go with the mass of water, that being 1000kg/m^3.

    M = 1.61925008e15 X 1000
    = 1.61925008e18kg

    As previously caclulated, Strelizia Apus weighs 7.2176079e18kg, and Strelizia True Apus should weigh the same.

    M = 7.2176079e18 + 1.61925008e18
    = 8.83685798e18kg

    Now all that's left is the easy, fun part!

    43 pixels = 368180.899m
    1 pixel = 368180.899m/43 = 8562.34649m
    8562.34649m X 1349 = 11550605.4m
    Spoiler:


    Timeframe is 3 seconds.

    852 pixels = 11550605.4m
    1 pixel = 11550605.4m/852 = 13557.0486m
    13557.0486m X 695 = 9422148.78m

    T = 9422148.78m/3s
    = 3140716.26/340.29
    = Mach 9229.52852

    At these velocities, we can just start to apply relativistic kinetic energy, so we enter the above values into the relativistic kinetic energy calculator and get a result of 4.359E+31 joules, or 10.418260038240916288 zettatons.

    Final Results
    Strelizia True Apus rams the VIRM planet (speed) = Mach 9229.529
    Strelizia True Apus rams the VIRM planet (energy) = 10.418 zettatons
  • TTGL
    Strelizia Apus is one absolutely colossal mecha, and given there are a few calcs I have in mind for it, I'll scale it's size and mass here. Machine scaling is never easy, and in the case of Strelizia Apus & True Apus this is very much so.
    Spoiler:
    Strelizia Apus was formed from Star Entity, which we can scale from Plantation 13. Plantations have a height of 1200m.

    Star Entity's crushes Plantation 13 between its index and middle finger.

    181 pixels = 1200m
    1 pixel = 1200m/181 = 6.62983425m
    6.62983425m X 358 = 2373.48066m

    That's the easy part done, now to scale the dimensions of Strelizia Apus, starting with all the pointy armour...

    6 pixels = 2373.48066m
    1 pixel = 2373.48066m/6 = 395.58011m
    395.58011m X 74 = 29272.9281m
    395.58011m X 126 = 49843.0939m
    395.58011m X 135 = 53403.3148m
    395.58011m X 91 = 35997.79m
    35997.79m/2 = 17998.895m
    395.58011m X 147 = 58150.2762m
    395.58011m X 70 =
    58150.2762m + 27690.6077m = 85840.8839m

    395.58011m X 9 = 3560.22099m
    395.58011m X 154 = 60919.3369m
    395.58011m X 119 = 47074.0331m
    395.58011m X 371 = 146760.221m
    395.58011m X 207 = 81885.0828m
    81885.0828m/2 = 40942.5414m
    395.58011m X 667 = 263851.933m
    395.58011m X 102 = 40349.1712m
    395.58011m X 117 = 46282.8729m
    46282.8729m/2 = 23141.4365m

    395.58011m X 201 = 79511.6021m
    395.58011m X 74 = 29272.9281m
    29272.9281m/2 = 14636.4641m
    395.58011m X 130 = 51425.4143m
    51425.4143m/2 = 25712.7071m
    395.58011m X 198 = 78324.8618m
    395.58011m X 169 = 66853.0386m
    66853.0386m/2 = 33426.5193m
    395.58011m X 352 = 139244.199m

    Shall we begin? Volume of her knee protectors and leg protectors as triangles added together.

    A = hbb/2
    = 29272.9281 X 49843.0939/2
    = 729526652m^2

    Then we times that by the depth to get the volume, and times it by two for both knees.

    V = 729526652 X 3560.22099
    = 2.5972761e12 X 2
    = 5.1945522e12m^3

    A = hbb/2
    = 29272.9281m^2

    V = 29272.9281 X 53403.3148/2
    = 781635697 X 3560.22099
    = 2.78279581e12 X 2
    = 5.56559162e12m^3

    Next, for the interior parts, as two pyramids, with the above volumes subtracted.

    V = 1/3AH
    = 1/3 X 729526652 X 29272.9281
    = 7.11846041e12 X 2
    = 1.42369208e13 - 5.1945522e12
    = 9.0423686e12m^3

    V = 1/3AH
    = 1/3 X 781635697 X 29272.9281
    = 7.62692185e12 X 2
    = 1.52538437e13 - 5.56559162e12
    = 9.68825208e12m^3

    V = 9.0423686e12 + 9.68825208e12
    = 1.87306207e13m^3

    In order to get the surface area of a cone I entered the values (17998.895m in radius and 58150.2762m high) into a calculator and got 4460000000m^2.

    V = 4460000000 X 3560.22099
    = 1.58785856e13 X 2
    = 3.17571712e13m^3

    Interior part as a cone (with the above subtracted, and again times by two for both of them).

    V = πr^2h/3
    = π X 17998.895^2 X 58150.2762/3
    = 1.97275016e13 X 2
    = 3.94550032e13 - 3.17571712e13
    = 7.697832e12m^3

    Volume of her leg protectors as triangles. Note of the upper two triangles she has two on each leg, which gives us a total of four.

    A = hbb/2
    = 60919.3369 X 47074.0331/2
    = 1.43385944e9 X 4
    = 5735437760m^2

    V = 5735437760 X 3560.22099
    = 2.04194259e13m^3

    Now for the lower leg triangles.

    A = hbb/2
    = 146760.221 X 60919.3369
    = 8.94053535e9 X 4
    = 35762141400m^2

    V = 35762141400 X 3560.22099
    = 1.27321126e14m^3

    The interior parts as triangular pyramids.

    V = 1/3AH
    = 1/3 X 8.94053535e9 X 60919.3369
    = 1.81550495e14 X 2
    = 3.6310099e14 - 1.27321126e14
    = 2.35779864e14m^3

    For the huge thing on the back we'll use a cone for the back end, which for the surface area we'll once again enter the values (a radius of 40942.5414m and 263851.933m long) through a calcuator, which reveals a surface area of 39600000000m^2.

    V = 39600000000 X 3560.22099
    = 1.40984751e14m^3

    For the interior parts, we'll use a cone (subtracting the above, of course).

    V = πr^2h/3
    = π X 40942.5414^2 X 263851.933/3
    = 4.63167942e14 - 1.40984751e14
    = 3.22183191e14m^3

    For the front end, we'll use a frustrated conical frustrum. Using this calculator here, we can determine it has a total surface area of 15827400000m^2.

    V = 15827400000 X 3560.22099
    = 5.63490417e13m^3

    Next, of course, its interior dimensions.

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (23141.4365^2 + 23141.4365 X 40942.5414 + 40942.5414^2) X 40349.1712
    = 1.33491102e14 - 5.63490417e13
    = 7.71420603e13m^3

    Now for the volume of the back legs as two cylinders and a cone. First segment...

    A = 2πrh + 2πr^2
    = 2 X π X 14636.4641 X 79511.6021 + 2 X π X 14636.4641^2
    = 8.65819662e9m^2

    V = 8.65819662e9 X 3560.22099
    = 3.08250933e13m^3

    V = πr^2h
    = π X 14636.4641^2 X 79511.6021
    = 5.35121895e13 - 3.08250933e13
    = 2.26870962e13m^3

    Second segment...

    A = 2πrh + 2πr^2
    = 2 X π X 25712.7071 X 78324.8618 + 2 X π X 25712.7071^2
    = 1.68080707e10m^2

    V = 1.68080707e10 X 3560.22099
    = 5.98404461e13m^3

    V = πr^2h
    = π X 25712.7071^2 X 78324.8618
    = 1.62684102e14m^3

    V = 1.62684102e14 - 5.98404461e13
    = 1.02843656e14m^3

    Third segment, as a cone. Once again using the calculator (for a radius of 33426.5193m and a length of 139244.199m) we get a surface of area 18500000000m^2.

    V = 18500000000 X 3560.22099
    = 6.58640883e13m^3

    V = πr^2h/3
    = π X 33426.5193^2 X 139244.199/3
    = 1.62925117e14m^3

    V = 1.62925117e14 - 6.58640883e13
    = 9.70610287e13m^3

    Now to add the exterior and interior parts together.

    V = 3.08250933e13 + 5.98404461e13 + 6.58640883e13
    = 1.56529628e14m^3

    V = 2.26870962e13 + 1.02843656e14 + 9.70610287e13
    = 2.22591781e14 X 2
    = 4.45183562e14m^3

    Last but not least, we need the values of the humanoid part of Stelitzia Apus.

    315 + 195 + 329 = 839
    395.58011m X 839 = 331891.712m = 331.891712km

    To find the surface area of her body, we'll scale up from a female body using square-law. Zero-Two is 170cm (or 1.7m) and the average mass of a 16 year old girl is 53.5kg.

    M2 = (H2/H1)^3*M1
    = (331891.712/1.7)^3*53.5
    = 3.98103724e17kg

    Entering the heigh and mass into this calculator, we get a variable number of surface areas, so let's get an average (ignoring the Biyd and Schlich formula's, as both are outliers on both end of the scale).

    A = 16217846544.78 + 17874819076.91 + 18581529949.17 + 18728961353.28 + 22526536559.03 + 27694900835.94
    = 1.21624594e11/8
    = 15203074250m^2

    V = 15203074250 X 3560.22099
    = 5.41263041e13m^3

    For our volume for the interior, we'll be using this forumla...
    The average density of the human body (from the above link) is 1010 kg/m^3.

    V = 3.98103724e17/1010
    = 3.94162103e14m^3

    V = 1.43796025e15 - 5.41263041e13
    = 1.38383395e15m^3

    At last, we can add everything together for our mass. First for the exterior...

    V = 5.1945522e12 + 5.56559162e12 + 3.17571712e13 + 2.04194259e13 + 1.27321126e14 + 1.40984751e14 + 5.63490417e13 + 4.45183562e14 + 5.41263041e13
    = 886901525720000m^3

    ...then for the interior.

    V = 1.87306207e13 + 7.697832e12 + 2.35779864e14 + 3.22183191e14 + 7.71420603e13 + 4.45183562e14 + 1.38383395e15
    = 2490551080000000m^3

    For our exterior armour, we'll steel, which weighs 7850kg/m^3 (usually I go with titanium, but given the interior part below seems a lot lighter than it should I think steel is a good choice).

    M = 886901525720000 X 7850
    = 6.96217698e18kg

    Now for the mechanical unseen interior, which is somewhat harder. The light ship mass of container vessel 2700TEU is 102.56kg/m^3 (or 0.10256g/cm^3). I've a feeling this is a colossal low end, but it's the best I've got for now, so I'll take it.

    M = 2490551080000000 X 102.56
    = 2.55430919e17kg

    Finally, to add both together for our final mass.

    M = 6.96217698e18 + 2.55430919e17
    = 7.2176079e18kg
    = 7217607900000000 tons


    Final Results
    Strelizia Apus' size = 331.891712km
    Strelizia Apus' mass = 7217607900000000 tons

    I'm not sure if the scaling is entirely accurate, but given there'd be a lot more unseen machinery (such as under the back part where we can see some engines) it would be even greater in mass, though that's the best I can do with what I've got. Strelizia True Apus would be equal in size and mass.
  • TTGL
    (Episode 22)


    Spoiler:





    Zero-Two's mind's connected to Strelitzia Apus, which is in Mars orbit, and cuts on her appear whenever she's attacked by VIRM ships. Lot's of scaling, so let's get to calcing!
    Spoiler:
    The distance from Earth to Mars at their closest is 54600000km, or 54600000000m. Mars at it's furtherst is 401000000km away, or 401000000000m. The average distance to Mars from Earth is 225000000km, or 225000000000m, so we'll use those as our low end, mid end and high end.
    https://www.space.com/24701-how-long-does-it-take-to-get-to-mars.html
    Given the light is bright enough to visibly light up the Earth even through dark clouds during the day, then the apparent magnitude should be comparable to that of the Sun, that being −26.74 (though really it's likely even higher given it shone through the clouds easier than the sunlight did).
    (Low end)
    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(54600000000))^2)

    Breaking this down bit by bit...

    (146000000000/(54600000000))^2) = 7.15023682
    -26.74 - -26.73 = 7.15023682/((L/3.846*10^26)
    -0.01 = -2.5Log(7.15023682/((L/3.846*10^26))
    -0.01/-2.5 = (7.15023682/((L/3.846*10^26))
    10^(0.004) = (7.15023682/((L/3.846*10^26))
    1.00925289 = (7.15023682/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 7.15023682
    3.89975317e27/7.15023682 = 5.45401959e26 joules

    We'll hold onto that for now, let's do our mid and high ends.

    (Mid end)

    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(225000000000))^2)

    (146000000000/(225000000000))^2) = 0.42105679
    -26.74 - -26.73 = 0.42105679/((L/3.846*10^26)
    -0.01 = -2.5Log(0.42105679/((L/3.846*10^26))
    -0.01/-2.5 = (0.42105679/((L/3.846*10^26))
    10^(0.004) = (0.42105679/((L/3.846*10^26))
    1.00925289 = (0.42105679/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 0.42105679
    3.89975317e27/0.42105679 = 9.26182231e27 joules

    (High end)

    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(401000000000))^2)

    (146000000000/(401000000000))^2) = 0.132561365
    -26.74 - -26.73 = 0.132561365/((L/3.846*10^26)
    -0.01 = -2.5Log(0.132561365/((L/3.846*10^26))
    -0.01/-2.5 = (0.132561365/((L/3.846*10^26))
    10^(0.004) = (0.132561365/((L/3.846*10^26))
    1.00925289 = (0.132561365/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 0.132561365
    3.89975317e27/0.132561365 = 2.94184748e28 joules

    For our final step, we'll get the timeframe to determine how long the light shone for.
    Spoiler:



    3 seconds.

    (Low end)
    E = 5.45401959e26 X 3
    = 1.63620588e27 joules
    = 391.0625908221797431 petatons

    (Mid end)
    E = 9.26182231e27 X 3
    = 2.77854669e28 joules
    = 6.6408859703632888341 exotons

    (High end)
    E = 2.94184748e28 X 3
    = 8.82554244e28 joules
    = 21.093552676864244859 exotons

    And on another note, given that Hiro doesn't wait around for minutes for the flashes to appear in the sky and they appear instantly, the VIRM explosions/attacks would be FTL.
    Spoiler:


    4 seconds.

    (Low end)
    T = 54600000000m/4s
    = 13650000000/299792458
    = 45.531499 C

    (Mid end)
    T = 225000000000m/4s
    = 56250000000/299792458
    = 187.629804 C

    (High end)
    T = 4s
    = 401000000000/299792458
    = 1337.59202 C


    Final Results
    VIRM ships attack Strelitzia Apus (low end) = 391.063 petatons
    VIRM ships attack Strelitzia Apus (mid end) = 6.641 exotons
    VIRM ships attack Strelitzia Apus (high end) = 21.094 exotons
    VIRM explosions (low end) = 45.531 C
    VIRM explosions (mid end) = 187.63 C
    VIRM explosions (high end) = 1337.592 C
  • TTGL

    2:54

    Streliztia gets rammed by a Gutenburg class Klaxosaur with enough force to create a colossal dust cloud that dwarves the nearby plantations. Plantations have a height of 1200m.

    That makes our job a lot easier. Now, to scaling!

    509 pixels = 1200m
    1 pixel = 1200m/509 = 2.35756385m
    2.35756385m X 639 = 1506.4833m
    1506.4833m/2 = 753.24165m
    2.35756385m X 1459 = 3439.68566m
    3439.68566m/2 = 1719.84283m
    2.35756385m X 1590 = 3748.52652m
    3748.52652m/2 = 1874.26326m
    2.35756385m X 375 = 884.086444m
    884.086444m/2 = 442.043222m

    Volume of both parts as ellipsoids.

    V = 4/3πabc
    = 4/3 X π X 753.24165 X 1719.84283 X 753.24165
    = 4.08738947e9m^3

    V = 4/3πabc
    = 4/3 X π X 1874.26326 X 442.043222 X 442.043222
    = 1.53408235e9m^3

    V = 4.08738947e9 + 1.53408235e9
    = 5621471820m^3

    Weight of a dust cloud/air is 1.003kg/m^3.

    M = 5621471820 X 1.003
    = 5.63833624e9kg

    Next for our timeframe.
    Spoiler:


    2 seconds and 17 frames.

    T = 1s/24
    = 41.6666667ms X 17
    = 0.708333334s + 2s
    = 2.70833333s

    T = 3748.52652m/2.70833333s
    = 1384.07133m/s

    Now for the final step, to get our kinetic energy.

    KE = (0.5)mv^2
    = (0.5) X 5.63833624e9 X 1384.07133^2
    = 5.40054913e15 joules
    = 1.290762220363288693 megatons

    Final Results
    Gutenburg-class Klaxosaur rams Strelitzia = 1.291 megatons
  • TTGL

    0:49

    Strelizia flies away and covers an area greater than the plantation, which has a diameter of 6km and a height of 1.2km (or 1200m).

    Straight forward enough. Let's find the distance and timeframe in which Strelizia flew.
    Spoiler:


    Timeframe is 2 seconds and 20 frames.

    T = 1s/24
    = 41.6666667ms X 20
    = 0.833333334s + 2s
    = 2.83333333s

    230 pixels = 1200m
    1 pixel = 1200m/230 = 5.2173913m
    5.2173913m X 641 = 3344.34782m

    T = 3344.34782/340.29
    = Mach 9.82793447

    Final Results
    Strelizia flies away = Mach 9.828
  • TTGL

    15:20
    Spoiler:





    Spoiler:





    Spoiler:


    The Primordial Life Fiber begins absorbing all other life fibers across space and time throughout the multiverse. Although many of these life fibers would be from across time and dimensions, others would be across space, and therefore quantifiable. The closest star to Earth, Alpha Centuri, is 4.22 lightyears away (or 3.99234299e16m).
    Spoiler:



    25 seconds.

    T = 3.99234299e16m/25s
    = 1.5969372e15/299792458
    = 5326809.12 C

    And that's just a low end of the nearest star. For a high end we'll go with the radius of the observable universe, that being 46,500,000,000 lightyears (or 4.39914571e26m).

    T = 4.39914571e26m/25s
    = 1.75965828e25/299792458
    = 58695882200000000 C

    Final Results
    Ryuko absorbs life fibers (low end) = 5326809.12 C
    Ryuko absorbs life fibers (high end) = 58695882200000000 C
  • TTGL
    (Episode 24)

    Yoko and Darry shoot some giant missiles, and knock them off their paths before they explode. I calced the dimensions of Super Galaxy Dai-Gurren previously in my Spiral Abyss calc, though unfortunately the images are gone after the PostImage crash of '18. Thankfully though it won't be hard to rescale. The Moon is 3472.8km in radius.

    207 pixels = 3472.8km
    1 pixel = 3472.8km/207 = 16.7768116km
    16.7768116km X 56 = 939.50145km

    323 pixels = 939.50145km
    1 pixel = 939.50145km/323 = 2.90867322km
    2.90867322km X 180 = 523.56118km
    2.90867322km X 483 = 1404.88917km (1404889.17m)

    Looking up different warheads, the one I found that was closest in shape to the Anti-Spiral missile was the V-2, which weighed 12500kg and was 14m long.

    M2 = (H2/H1)^3*M1
    = (1404889.17/14)^3 X 12500
    = 1.26314178e19kg

    Now that we have the mass of each missile we can find the speed at which they were knocked. Let's also get the speed for Yoko's bullets. Arc Gurren Lagann is described as being "several tens of kilometers" tall...

    (The relevant part)

    (Crappy translation)
    ...and the Space Grapearls aren't that far behind, it would be a fair assumption that Darry's Space Grapearl is at least 30km tall.
    Spoiler:


    = 2*atan(47/(596/tan(70/2)))
    = 0.0746944197 rad
    = 4.279675001999448725 degrees

    Enter those values through the angscaler and Yoko & Darry are 401.45km away.
    Spoiler:


    The timeframe between Yoko firing and hitting the missile is 8 frames, and the timeframe for the missile getting knocked to the side is 1 frame. There are 24 frames in a second.

    T = 1s/24
    = 41.6666667ms X 8
    = 401.45km/0.333333334s
    = 1204350/340.29
    = Mach 3539.18716

    172 pixels = 523.56118km
    1 pixel = 523.56118km/172 = 3.04396035km
    3.04396035km X 154 = 468.769894km

    T = 468.769894km/41.6666667ms
    = 11250477.4m/s

    Now for our energy, for which we enter those values through the reletavistic kinetic energy calculator, which yields a result of 8.002E+32 joules, or 191.25239005736136733 zettatons. Now for Darry shooting the other missile.
    Spoiler:



    Timeframe is 14 frames.

    T = 1s/24
    = 41.6666667ms X 14
    = 0.583333334s

    211 pixels = 523.56118km
    1 pixel = 523.56118km/211 = 2.48133261km
    2.48133261km X 164 = 406.938548km

    T = 406.938548km/0.583333334s
    = 697608.939m/s

    KE = (0.5)mv^2
    = (0.5) X 1.26314178e19 X 697608.939^2
    = 3.07359173e30 joules
    = 734.60605401529639494 exotons

    Final Results
    Anti-Spiral missile size = 1404.88917km
    Yoko shoots missile (speed) = Mach 3539.18716
    Yoko shoots missile (energy) = 191.253 zettatons
    Darry shoots missile = 734.606 exotons

    Consistent with Arc Gurren Lagann sending the giant mugann flying and Arc Gurren Laganns Giga Drill.
  • TTGL
    I feel like I've used that as a title before for a blog, but it's good enough to use again.


    Kittan sacrifices himself to destroy the Spiral Death Machine, which creates a huge light that shakes the entire galaxy.

    (The important part in particular)

    (Crappy translation of the relevant part)
    Looking back at my old Noo shake the Universe calc for help. First, the energy to shake one planet noticably enough to be felt, or at least magnitude 2.5, though the highest I could get by playing around with the impact calculator was magnitude 2.3, which results in 3.72 X 10^12 Joules. Next we need the area that get's shook. Divid that by 10,000 and you have 372000000 joules The radius of the Milky Way is 52,850 lightyears, or 3720000000000 joules of seismic energy.

    I = S/4pa
    372000000 = S/(4 X π X 4.99988926e20^2)
    S = 372000000 X (4 X π X 4.99988926e20^2)
    = 1.1686207e51/10^44
    = 11.686207 MEGAFOE

    Final Results

    Kittan destroys the Spiral Death Machine = 11.686 MEGAFOE


    Not bad, not bad at all...
  • TTGL
    (Episode 21)

    Mako and Senketsu purge Ryuko of Junketsu's influence, and this causes a huge water explosion. Scaling from the S. S. Naked Sun. The standard height of a door is 6 feet 8 inches (or 2.03200m)

    161 pixels = 2.03200m
    1 pixel = 2.03200m/161 = 0.012621118m
    0.012621118m X 735 = 9.27652173m

    18 pixels = 9.27652173m
    1 pixel = 9.27652173m/18 = 0.515362318m

    0.515362318m X 224 = 115.441159m
    0.515362318m X 999 = 514.846956m
    0.515362318m X 1900 = 979.188404m
    979.188404m/2 = 489.594202m
    0.515362318m X 1489 = 767.374492m
    767.374492m/2 = 383.687246m
    0.515362318m X 1387 = 714.807535m

    Volume as the bottom parts and top parts as cylinders.

    V = πr^2h
    = π X 489.594202^2 X 115.441159
    = 86932682.9m^3

    V = πr^2h
    = π X 383.687246^2 X 514.846956
    = 238112804m^3

    V = 86932682.9 + 238112804
    = 325045487m^3

    Weight of water is 1000kg/m^3.

    M = 325045487 X 1000
    = 325045487000kg
    Now for the timeframe.
    Spoiler:


    0.6 seconds.

    T = 714.807535m/0.6s
    = 1191.34589m/s

    Finally, for our energy.

    KE = (0.5)mv^2
    = (0.5) X 325045487000 X 1191.34589^2
    = 2.30669347e17 joules
    = 55.131297084130018504 megatons

    Final Results
    Ryuko gets purged = 55.131 megatons
  • TTGL
    Kill La Kill has an insane speed feat in the second episode alone.

    1:37

    Ryuko cuts many tennis balls into string. There's gonna be a ton of scaling here, so let's get started.
    Spoiler:
    The diameter of a tennis ball is between 6.54cm to 6.86cm, or an average of 6.7cm (or 0.067m), and the average height of a 17 year old Japanese girl is 157.9cm (or 1.579m).

    445 + 574 = 1019 pixels
    1019 pixels = 1.579m
    1 pixel = 1.579m/1019 = 0.00154955839m
    0.00154955839m X 222 = 0.344001963m
    0.00154955839m X 1025 = 1.58829735m
    1.58829735m + 0.344001963m = 1.93229931m
    = 2*atan(22/(1438/tan(70/2)))
    = 0.0144975539 rad
    = 0.8306486517354871868 degrees

    Enter these values through the angscaler, and we have a distance of 4.6214m to the furthest ball.
    = 2*atan(1019/(1438/tan(70/2)))
    = 0.647858825 rad
    = 37.1195763928966684 degrees

    Caclulating as above, Ryuko is 2.3514m away, which means the distance from the furthest ball to Ryuko is 2.27m. The fastest tennis ball serve is by Tilden, and was clocked at going 73.14 m/s. Given Hakodate is embued with a 2 Star Goku Uniform that grants her superhuman powers and her tennis ball attacks can shatter rock and metal, I think it's safe to assume her serves are at least this fast.

    T = 2.27/73.14
    = 0.0310363686s

    The balls are cut so many times they're turned to string. by getting the thickness of these strings, we can determine how thinly the balls were cut, and by proxy, how many times they were cut.
    Spoiler:


    985 pixels = 0.067m
    0.067m/2 = 0.0335m
    1 pixel = 0.067m/985 = 6.80203046e-5m
    6.80203046e-5m X 8 = 0.000544162437m

    Now for the number of times the ball was cut, longways and acrossways.

    0.067/0.000544162437 = 123.12500

    That's the number of times each individual ball was cut. Cutting 123.125 times vertically and 123.125 times horizontally means that each ball was cut 246.25 times. Next we need the distance Ryuko swings her arms with the Scissor Blade, which given how the tennis balls are coming at her would be at a 180 angle at least, so we'll find the distance slashed as half the circumference of a circle.

    C = 2πr
    = 2 X π X 1.93229931
    = 12.1409946/2
    = 6.0704973m

    Now we just need to count the balls. All of them. Iwandesu already counted and got 220, but it's best to be safe, so let's recount them. (Inhales)

    214 balls, which is pretty close to Iwan's count. All that's left is to find out the distance cut, and we can get our speed.

    D = 6.0704973m X 246.25
    = 1494.85996m X 214
    = 319900.031m/0.0310363686s
    = 10307263.6/340.29
    = Mach 30289.6459

    That's ridiculously fast! However, I've seen another way of scaling this feat, based on how far the balls flew from Hakodate before they got cut apart, so I'm going to try that out too.

    535 pixels = 1.579m
    1 pixel = 1.579m/535 = 0.00295140187m
    0.00295140187m X 113 = 0.333508411m

    89 pixels = 0.333508411m
    1 pixel = 0.333508411m/89 = 0.00374728552m
    0.00374728552m X 1512 = 5.66589571m

    = 2*atan(48/(1433/tan(70/2)))
    = 0.0317392844 rad
    = 1.81852704088992434 degrees

    Going through the scaling process above once more, and the distance to the largest tennis ball is 2.1108m away.
    128 + 158 = 286 pixels
    = 2*atan(286/(1433/tan(70/2)))
    = 0.18856836 rad
    = 10.804171177730332 degrees

    That gets us a distance of 8.3488m to Ryuko.

    D = 8.3488m - 2.1108m
    = 6.23800m

    D = 6.23800m - 5.66589571m
    = 0.57210429m

    T = 0.57210429/73.14
    = 0.00782204389s

    T = 319900.031m/0.00782204389s
    = 40897243.2/299792458 X 100
    = 13.6418519% C

    Last but absolutely not least, let's go by the number of tennis balls given in the show itself...
    Spoiler:



    110 Million (110,000,000).

    (Low end)
    T = 6.0704973m X 246.25
    = 1494.85996m X 110000000
    = 164434595600m/0.0310363686s
    = 5.29812613e12/299792458
    = 17672.6465 C

    (High end)
    T = 6.0704973m X 246.25
    = 1494.85996m X 110000000
    = 164434595600m/0.00782204389s
    = 2.10219474e13/299792458
    = 70121.6686 C


    Final Results
    Ryuko cuts up tennis balls (low end - 214 balls) = Mach 30289.646
    Ryuko cuts up tennis balls (high end - 214 balls) = 13.642% C
    Ryuko cuts up tennis balls (low end - 111000000 balls) = 17672.647 C
    Ryuko cuts up tennis balls (high end - 111000000 balls) = 70121.669 C
  • TTGL

    2:20

    Strelizia rips a huge worm Klaxosaur out of the ground. Zero Two is said to be around 170cm (1.7m tall).

    438 pixels = 1.7m
    1 pixel = 1.7m/438 = 0.00388127854m
    0.00388127854m X 79 = 0.306621005m

    37 pixels = 0.306621005m
    1 pixel = 0.306621005m/37 = 0.00828705419m
    0.00828705419m X 1001 = 8.29534124m

    83 pixels = 8.29534124m
    1 pixel = 8.29534124m/83 = 0.0999438704m
    0.0999438704m X 71 = 7.0960148m
    0.0999438704m X 550 = 54.9691287m

    21 pixels = 7.0960148m
    1 pixel = 7.0960148m/21 = 0.337905467m
    0.337905467m X 109 = 36.8316959m

    17 pixels = 36.8316959m
    1 pixel = 36.8316959m/17 = 2.16657035m
    2.16657035m X 1975 = 4278.97644m

    Volume as a rectangle, the hold was deep enough to completely bury Strelizia.

    V = lhw
    = 4278.97644 X 36.8316959 X 54.9691287
    = 8663242.37m^3

    Now for the energy to rip up the ground like so. Violent fragmentation of rock is 69000000 joules/m^3.

    E = 8663242.37 X 69000000
    = 5.97763724e14 joules
    = 142.868958891013392 kilotons

    Strelizia also destroys the klaxosaur by plowing through its entire body from the inside (above video at 3:45).

    Spoiler:


    5 seconds.

    T = 4278.97644m/5s
    = 855.795288/340.29
    = Mach 2.5148999

    Final Results
    Strelizia's height = 54.969m
    Strelizia rips up worm klaxosaur = 142.869 kilotons
    Strelizia destroys worm klaxosaur = Mach 2.515
  • TTGL


    Violence goes berserk, and destroys the planet SVM-Z. Luluco seems to be walking around on SVM-Z fine, so it seems safe enough to assume it has an Earth-like size. The Earth has a diameter of 12,742km and a mass of 5.9722 X 10^24kg (5.9722e24kg).
    Spoiler:


    Timeframe is 2 seconds.

    1180 pixels = 12,742km
    1 pixel = 12,742km/1180 = 10.7983051km
    10.7983051km X 1954 = 21099.8882km

    T = 21099.8882km/2s
    = 10549944.1m/s

    KE = (0.5)mv^2
    = (0.5) X 5.9722e24 X 10549944.1^2
    = 79.435199091778194997 ninatons

    Only scales to Violence, and it's unclear if he survives in anycase, but there's also a nice speed feat of Alpha Omega Nova saving Luluco.
    Spoiler:



    Timeframe is 2 seconds.
    = 2*atan(2439/(1608/tan(70/2)))
    = 1.24630361 rad
    = 71.407936845095676 degrees

    Enter those values through the anscaler, and we get a distance of 8864.9km to SVM-Z.
    = 2*atan(1414/(1608/tan(70/2)))
    = 0.7895547 rad
    = 45.23815200483008 degrees

    That's a distance of 15291km.

    L = 15291km - 8864.9km
    = 6426.1km

    T = 6426.1km/2s
    = 3213050/340.29
    = Mach 9442.09351

    Let's also find the kinetic energy for this. According to this link, average weight of a 13 year old boy is between 75 and 145 pounds and the average weight of a 13 year old girl is between 76 and 148 pounds. At a low end, that's 34.0194kg & 34.473kg.

    M = 34.0194kg + 34.473kg
    = 68.4924kg

    KE = (0.5)mv^2
    = (0.5) X 68.4924 X 3213050^2
    = 3.53547163e14 joules
    = 84.4997999521988561 kilotons

    Final results
    Violence destroys SVM-Z = 79.435 ninatons
    Alpha Omega Nova flies Luluco into space (speed) = Mach 9442.094
    Alpha Omega Nova flies Luluco into space (energy) = 84.5 kilotons
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