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Marvel comic :: Grey Hulk Destroys an Asteroid
Feat happens in "Marvel Comics Presents #52". I think the Calc was done over on OBD but I can't find it. I know theirs a YouTube calc of it but they don't explain their steps so I figured I'd re-do it for here. [Image1][Image2]
According to the YouTube calc, it traveled a distance of 2.2 AU, and by narration, it'll reach the Earth in 3 hours.
2.2 AU / 3 hours = 30,473,640.3 m/s (0.10c)
The Asteroid was said to be twice the size of the Earth by the professor. That would mean the 392 Pixels Equal roughly 25,484 km. But lets cut that in half because Radius.
392 / 98 = 4
25,484 / 4 = 6,371 km
6,371 / 2 = 3185.5 km
398 / 44 = 9
25,484 / 9 = 2831.5 km
2831.5 / 2 = 1415.75 km
Going to use an Ellipsoid.
Volume = 4/3 * π * ra * rb * rc
4/3*pi*(12742) * (3185.5) * (1415.75)= 240707925368.76 km^3 or 2.4070792536876e+20 m^3
Low end density of Asteroids tend to be about 3.0 g/cm^3 or 3,000 kg/m^3
M= 2.4070792536876e+20*3000= 722123776106280000000000 kg
using the KE relativistac formula.
KE = (0.5*m*v2)/(1-(v2/c2))^0.5
m: the mass of the object
v: velocity (speed)
c: speed of light
KE= (0.5*722123776106280000000000 *30473640.3^2)/(1-(30473640.3^2/299792458^2))^0.5 = 3.37043284368286848371504e38 Joules or 80.5 ninatons
Grey Hulk Destroys an Asteroid= KE: 3.37043284368286848371504e38 Joules or 80.5 ninatons
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