I created a circular shape for know the real size of the explosion.

2atan(tan(70/2)*(232/504) ) = 35°

Now for the distance, i chose two End, first the Hypotetical Planet nemesis's distance to earth (which is 1.5 lightyears) and the distance to the border of the solar system (a guy claim that nemesis is the 10th planet of the solar system so the distance of Eris to earth is good)

High End = 1.5 LY

Low End = 96.4 AU

Sooo we have angle and distance we can found the size of this fucking explosion:

High End = 8.9482e+15 Meters

Low End = 8.1978e+11 Meters

Finally we can applies the Formula for destroying a celestial Body:

The surface area of a sphere with 8.9482e+15m divided by 2 in radius = 2.4328493509399E+32 m^2

Surface area of Nemesis = 3.9369182497726E+19 m2 (Using nemesis's radius)

2.4328493509399E+32/3.9369182497726E+19 = 6.237948718E+12 Times the GBE of Nemesis

E = 6.237948718E+12 x (GBE of Nemesis, or 4.6E+51 Joules) = 2.86902E+64 Joules or 149 Exafoe.

For the Low end, i found 9,8E+56 J or 2 Terafoe]]>4