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  1. There's a couple of space calcs I've been meaning to recalc, so now's as good a time as any to go over them once more.

    1. Arc Gurren Lagann's Giga Drill Break


    Arc Gurren Lagann attacks an Ashtanga with a Giga Drill, to absolutely no effect at all. Arc Gurren Lagann is officially stated to be between 5km to 10km tall.

    612 + 936 = 1548 pixels
    1548 pixels = 5km
    1 pixel = 5km/1548 = 0.00322997416km
    0.00322997416km X 280 = 0.904392765km (904.392765m)
    1548 = 10km
    1 pixel = 10km/1548 = 0.00645994832km
    0.00645994832km X 280 = 1.80878553km (1808.78553m)

    While we're on it, we'll find the volume and mass of the giga drill.

    44 pixels = 904.392765m
    1 pixel = 904.392765m/44 = 20.554381m
    20.554381m X 376 = 7728.44726m
    7728.44726m/2 = 3864.22363m
    20.554381m X 1190 = 24459.7134m
    44 pixels = 1808.78553m
    1 pixel = 1808.78553m/44 = 41.108762m
    41.108762m X 376 = 15456.8945m
    15456.8945m/2 = 7728.44725m
    41.108762m X 1190 = 48919.4268m

    Volume as a cone.

    (Low end)
    V = πr^2h/3
    = π X 3864.22363^2 X 24459.7134/3
    = 3.82476262e11m^3

    (High end)
    V = πr^2h/3
    = π X 7728.44725^2 X 48919.4268/3
    = 3.05981008e12m^3

    For our mass, we'll go with a low end of titanium and a high end of steel, which respectively weigh 4500kg/m^3 and 7850kg/m^3.

    (Low low end)
    M = 3.82476262e11 X 4500kg
    = 1.72114318e15kg

    (Low high end)
    M = 3.82476262e11 X 7850kg
    = 3.00243866e15kg

    (High low end)
    M = 3.05981008e12 X 4500kg
    = 1.37691454e16kg

    (High high end)
    M = 3.05981008e12 X 7850kg
    = 2.40195091e16kg

    Next, to scale the distance from the Ashtanga. A single Ashtanga is 76067.0105km long.

    1388 pixels = 76067.0105km
    1 pixel = 76067.0105km/1388 = 54.8033217km
    54.8033217km X 85 = 4658.28234km

    = 2*atan(509/(1617/tan(70/2)))
    = 0.296112429 rad
    = 16.9659924431093323 degrees

    Enter those values into the angscaler, and we can determine that the Ashtanga is 15616km away. Let's get our timeframe.
    Spoiler:


    Timeframe is 10 seconds and 13 frames.

    T = 1s/24
    = 41.6666667ms X 13
    = 0.541666667s + 10s
    = 15616km/10.5416667s
    = 1481359.68/340.29
    = Mach 4353.22719

    At last, we come to our kinetic energy

    (Low low end)
    KE = (0.5)mv^2
    = (0.5) X 1.72114318e15 X 1481359.68^2
    = 1.8884611e27 joules
    = 451.35303537284897857 petatons

    (Low high end)
    KE = (0.5)mv^2
    = (0.5) X 3.00243866e15 X 1481359.68^2
    = 3.29431548e27 joules
    = 787.36029636711282365 petatons

    (High low end)
    KE = (0.5)mv^2
    = (0.5) X 1.37691454e16 X 1481359.68^2
    = 1.51076888e28 joules
    = 3.6108242829827918285 exotons

    (High high end)
    KE = (0.5)mv^2
    = (0.5) X 2.40195091e16 X 1481359.68^2
    = 2.63545237e28 joules
    = 6.2988823374760995648 exotons

    Now the hard parts out of the way, time for the easy bit; getting the mass energy to form said giga drill.

    (Low low end)
    E = mc^2
    = 1.72114318e15 X 299792458^2
    = 1.54688635e32 joules
    = 36.971471080305931878 zettatons

    (Low high end)
    E = mc^2
    = 3.00243866e15 X 299792458^2
    = 2.69845729e32 joules
    = 64.494677103250481309 zettatons

    (High low end)
    E = mc^2
    = 1.37691454e16 X 299792458^2
    = 1.23750907e33 joules
    = 295.7717662523900799 zettatons

    (High high end)
    E = mc^2
    = 2.40195091e16 X 299792458^2
    = 2.15876582e33 joules
    = 515.9574139579350458 zettatons

    2. King Kittan's final flight

    Space King Kittan flies fast. Might not look fast, but remember Super Galaxy Dai-Gurren is the size of the Moon. The diameter of the Moon is 3474.2km.

    260 pixels = 3474.2km
    1 pixel = 3474.2km/260 = 13.3623077km
    13.3623077km X 153 = 2044.43308km
    13.3623077km X 484 = 6467.35693km
    13.3623077km X 51 = 681.477693km

    973 pixels = 681.477693km
    1 pixel = 681.477693km/973 = 0.700388174km
    0.700388174km X 1216 = 851.67202km

    All we need next is the timeframe.
    Spoiler:


    Timeframe is 19 frames.

    T = 1s/24
    = 41.6666667ms X 19
    = 0.791666667s
    = 851.67202km/0.791666667s
    = 1075796.24/340.29
    = Mach 3161.41009

    3. Super Galaxy Dai-Gurren drags the Moon

    Super Galaxy Dai-Gurren drags the Moon back into realspace. Straightforward enough. The Moon weighs 7.353 X 10^22kg (or 7.35300e22kg) and as said above, has a diameter of 3474.2km. From when the Moon is first dragged out to when the shining around the Moon stops.
    Spoiler:


    Timeframe is 10 seconds and 5 frames.

    T = 1s/24
    = 41.6666667ms X 5
    = 0.208333333s + 10s
    = 10.2083333s
    = 3474.2km/10.2083333s
    = 340329.797m/s

    KE = (0.5)mv^2
    = (0.5) X 7.35300e22 X 340329.797^2
    = 4.25828299e33 joules
    = 1.0177540607074568868 yottatons

    Final Results
    Arc Gurren Lagann rushes the Ashtanga = Mach 4353.227
    Arc Gurren Lagann's Giga Drill kinetic energy (low low end) = 451.353 petatons
    Arc Gurren Lagann's Giga Drill kinetic energy (low high end) = 787.360 petatons
    Arc Gurren Lagann's Giga Drill kinetic energy (high low end) = 3.611 exotons
    Arc Gurren Lagann's Giga Drill kinetic energy (high high end) = 6.299 exotons
    Arc Gurren Lagann's Giga Drill mass energy (low low end) = 36.971 zettatons
    Arc Gurren Lagann's Giga Drill mass energy (low high end) = 64.495 zettatons
    Arc Gurren Lagann's Giga Drill mass energy (high low end) = 295.772 zettatons
    Arc Gurren Lagann's Giga Drill mass energy (high high end) = 515.957 zettatons
    Super Galaxy Dai-Gurren length = 6467.357 kilometers
    Space King Kittan's final flight = Mach 3161.410
    Super Galaxy Dai-Gurren tows the Moon = 1.018 yottatons
  2. An overlooked but super impressive feat. Well no more!

    Enki slams Gurren Lagann into the ground and shatters it considerably. This will be more or less straightforward. Gurren Lagann's main body is 10.5446154m tall.

    13 pixels = 10.5446154m
    1 pixel = 10.5446154m/13 = 0.811124262m
    0.811124262m X 2876 = 2332.79338m
    2332.79338m/2 = 1166.39669m

    Now for the thickness of the part shattered.

    0.811124262m X 122 = 98.95716m

    Volume as a cylinder.
    V = πr^2h
    = π X 1166.39669^2 X 98.95716
    = 422950607m^3

    Violent fragmentation of rock is 69000000 joules/m^3.

    E = 422950607 X 69000000
    = 2.91835919e16 joules
    = 6.9750458652007649718 megatons

    Final Results
    Enki slams Gurren Lagann into the ground = 6.975 megatons


  3. Troy phaselocks Elpis. Note that Elpis gets progressively closer in later shots. This is Elpis before Troy phaselocked it...


    ...and this is after...

    ...and this is during the battle with Troy.

    The map markers also note the moon is falling.

    So yes, Elpis is definately getting closer. Unfortunately, we don't have a usable timeframe. Fortunately, we don't need one. Using the method I used previously in my Mom, Please Don't Come Adventuring With Me! calcs (and the method used in the calc here), where I calced the energy to move a planet out of orbit.
    Although here, we'll replace the Sun's mass and orbital distance with those of the planet, given it's a moon being moved in a planets orbit, not a planet being moved in a stars orbit. Although the same logic should apply. Assuming Pandora is Earth-sized, Earth has a weight 5.9736e24kg. Now, for Elpis, given the Pre-Sequel shows Elpis to be similar in gravity to Earth's moon Luna, I think it's a safe bet to use the values for the Moon here. The Moon has a mass of 7.35e22kg and a diameter of 3475km. The gravitational constant of the Earth in ngs is 6.674×10^−8 (6.67400e-8). Now to find the distance from Pandora to Elpis.

    204 pixels = 3475km
    1 pixel = 3475km/204 = 17.0343137km
    17.0343137km X 1494 = 25449.2647km (25449264.7m)

    Now let's get our velocity.

    V = (GM(2/r - 1/a))^(1/2)
    = ((6.674×10^−8) X (5.9736e24)/(25449264.7))^(1/2)
    = 125162.305m/s

    So that's Elpis's initial velocity. Now we need to calculate the change in velocity needed to bring it closer to Pandora. To do that, we need Elpis's new distance to Pandora.

    = 2*atan(551/(1080/tan(70/2)))
    = 0.474366376 rad
    = 27.1791912877833255 degrees

    We put this through the angscaler, and we can determine that Elpis is now 7187.7km (or 7187700m) away. To calculate the velocity of a similar satellite in an orbit of this distance...

    V = (GM(2/r - 1/a))^(1/2)
    = ((6.674×10^−8) X (5.9736e24)/(7187700))^(1/2)
    = 235513.713m/s

    All that's left now is to calculate the kinetic energy of both.

    KE = (0.5)mv^2
    = (0.5) X 7.35e22 X 125162.305^2
    = 5.75710895e32 joules

    KE = (0.5)mv^2
    = (0.5) X 7.35e22 X 235513.713^2
    = 2.03840156e33 joules

    Lastly? We just subtract the energy, and that's the energy required to move the

    E = 2.03840156e33 - 5.75710895e32
    = 1.46269067e33 joules
    = 349.59146032504781942 zettaons

    Final Results
    Troy phaselocks Elpis = 349.591 zettatons


    Well, calcing moving planets is way harder than I remembered. :defeat Anyway, even when cut off from his Eridium supply, Troy uses Tyreen's power, and the Vault Hunters defeat him.
  4. Having gotten the values for size and mass for the Giant Muganns again (or Kyo Muganns) previously, now we're just left with the easy part.

    1. Gurren Lagann blasts a giant mugann

    Gurren Lagann blasts the blue giant mugann, pushing it away from Arc Gurren noticably The bottom of the Mugann's end segments are 3960.39604m wide.
    Spoiler:

    [/SPOLER]
    = 2*atan(125/(570/tan(70/2)))
    = 0.207070388 rad
    = 11.8642592945658372 degrees

    Put that through the angscaler, and the Kyo Mugann is currently 19057m away.
    [SPOLER]

    Timeframe is 3 seconds and 5 frames.

    T = 1s/24
    = 41.6666667ms X 5
    = 0.208333333s + 3s
    = 3.20833333s

    = 2*atan(89/(570/tan(70/2)))
    = 0.147694129 rad
    = 8.46225025058173053 degrees

    Now the Blue Kyo Mugann is 26766m away.

    L = 26766m - 19057m
    = 7709m

    T = 7709m/3.20833333s
    = 2402.8052m/s

    The Blue Kyo Mugann has a low end mass of 3.28380969e15kg and a high end mass of 9.91457924e15kg.

    (Low end)
    KE = (0.5)mv^2
    = (0.5) X 3.28380969e15 X 2402.8052^2
    = 9.47949301e21 joules
    = 2.2656532050669220268 teratons

    (High end)
    KE = (0.5)mv^2
    = (0.5) X 9.91457924e15 X 2402.8052^2
    = 2.86207769e22 joules
    = 6.840529851816444129 teratons

    2. Gurren Lagann drags Giant Mugann

    Gurren Lagann is trapped by the Giant Purple Mugann, but just drags it behind it and crashes into Arc Gurren, igniting their combination into Arc Gurren Lagann. The Giant Blue Mugann's lower segments are 28316.8317m long.
    Spoiler:


    Timeframe is 16 frames.

    T = 1s/24
    = 41.6666667ms X 16
    = 0.666666667s

    56 pixels = 28316.8317m
    1 pixel = 28316.8317m/56 = 505.657709m
    505.657709m X 49 = 24777.2277m

    Let's get the speed.

    T = 24777.2277m/0.666666667s
    = 37165.8415/340.29
    = Mach 109.218142

    Now for the kinetic energy. The Giant Purple Mugann has a low end mass of 8.00410598e15kg and a high end mass of 2.41662431e16kg.

    (Low end)
    KE = (0.5)mv^2
    = (0.5) X 8.00410598e15 X 37165.8415^2
    = 5.52803489e24 joules
    = 1.321232048279158855 petatons

    (High end)
    KE = (0.5)mv^2
    = (0.5) X 2.41662431e16 X 37165.8415^2
    = 1.66904131e25 joules
    = 3.9891044694072657073 petatons

    3. Final Mugann flies towards Arc Gurren Lagann

    The Final Mugann flies towards Arc Gurren Lagann, who halts it and matches it's power for several seconds. Though it doesn't look like much, keep in mind just how massive the Final Mugann is. Given it moves in a straight line, this is more or less straightforward. The Final Mugann is 55105.6106m.
    Spoiler:


    The timeframe is 2 seconds and 20 frames.

    T = 1s/24
    = 41.6666667ms X 20
    = 0.833333334s + 2s
    = 2.83333333s

    Next to find the distance it travelled in the timespan.

    65 pixels = 55105.6106m
    1 pixel = 55105.6106m/65 = 847.778625m
    324 - 184 = 140
    847.778625m X 140 = 118689.008m

    T = 118689.008m/2.83333333s
    = 41890.2382/340.29
    = Mach 123.101585

    Then we get out kinetic energy. The Final Mugann has a low end mass of 1.12879157e16kg and a high end mass of 3.40808223e16kg.

    (Low end)
    KE = (0.5)mv^2
    = (0.5) X 1.12879157e16 X 41890.2382^2
    = 9.9039724e24 joules
    = 2.3671062141491399089 petatons

    (High end)
    KE = (0.5)mv^2
    = (0.5) X 3.40808223e16 X 41890.2382^2
    = 2.99023781e25 joules
    = 7.1468398900573610888 petatons

    4. Final Mugann's mass energy
    This is the greatest, yet easiest one. As noted by Leeron and Rossiu, when defeated, mugann's turn into energy and explode.
    Spoiler:




    And something as big and heavy as the Final Mugann would create an immense amount of energy.

    (Low end)
    E = mc^2
    = 1.12879157e16 X 299792458^2
    = 1.01450727e33 joules
    = 242.47305688336521712 zettatons

    (High end)
    E = mc^2
    = 3.40808223e16 X 299792458^2
    = 3.06303155e33 joules
    = 732.08211042065011043 zettatons

    Final Results
    Gurren Lagann blasts Giant Mugann (low end) = 2.266 teratons
    Gurren Lagann blasts Giant Mugann (high end) = 6.841 teratons
    Gurren Lagann slams into Arc Gurren = Mach 109.218
    Gurren Lagann drags Giant Mugann (low end) = 1.321 petatons
    Gurren Lagann drags Giant Mugann (high end) = 3.989 petatons
    Final Mugann flight speed = Mach 123.102
    Final Mugann's kinetic energy (low end) = 2.367 petatons
    Final Mugann's kinetic energy (high end) = 7.147 petatons
    Final Muganns mass energy (low end) = 242.473 zettatons
    Final Mugann's mass energy (high end) = 732.082 zettatons
  5. Because the website that hosted the images in the old calc crashed, unfortunately, and there are a few calcs I want up again for future use, which relate to just how enormous the final muganns are. Arc Gurren is roughly 5km long, or 5000m.


    (Rough translation)
    We'll start with the blue one...

    101 pixels = 5000m
    1 pixel = 5000m/101 = 49.5049505m
    49.5049505m X 16 = 792.079208m

    8 pixels = 792.079208m
    1 pixel = 792.079208m/8 = 99.009901m
    99.009901m X 7 = 693.069307m
    99.009901m X 78 = 7722.77228m
    99.009901m X 4 = 396.039604m
    99.009901m X 286 = 28316.8317m
    99.009901m X 12 = 1188.11881m
    99.009901m X 40 = 3960.39604m
    99.009901m X 21 = 2079.20792m

    Volume of the top segments as trapezoidal prisms.

    V = LH(A + B)/2
    = 7722.77228 X 1188.11881 (396.039604 + 792.079208)/2
    = 5.45083426e9m^3

    Volume of the lower ones also, as trapezoidal prisms.

    V = LH(A + B)/2
    = 28316.8317 X 693.069307 (2079.20792 + 3960.39604)/2
    = 5.92652051e10m^3

    = 8.6607698e11m^3

    Next for the purple one.

    99.009901m X 99 = 9801.9802m
    99.009901m X 13 = 1287.12871m
    99.009901m X 16 = 1584.15842m
    99.009901m X 200 = 19801.9802m
    99.009901m X 14 = 1386.13861m
    99.009901m X 9 = 891.089109m

    Once again, volumes of the top parts are trapezoidal prisms, but given it's a trapezoidal prism on both sides, times by two.

    V = LH(A + B)/2
    = 9801.9802 X 891.089109 (1287.12871 + 1584.15842)/2
    = 1.25395394e10m^3

    Volume of the bottom segments as rectangles, assuming they're as thick as the ones the blue mugann is comprised of.

    V = lhw
    = 1386.13861 X 19801.9802 X 693.069307
    = 1.90235669e10 X 2
    = 38047133800m^3
    Because the website that hosted the images in the old calc crashed, unfortunately, and there are a few calcs I want up again for future use, which relate to just how enormous the final muganns are. Arc Gurren is roughly 5km long, or 5000m.


    (Rough translation)
    We'll start with the blue one...

    101 pixels = 5000m
    1 pixel = 5000m/101 = 49.5049505m
    49.5049505m X 16 = 792.079208m

    8 pixels = 792.079208m
    1 pixel = 792.079208m/8 = 99.009901m
    99.009901m X 7 = 693.069307m
    99.009901m X 78 = 7722.77228m
    99.009901m X 4 = 396.039604m
    99.009901m X 286 = 28316.8317m
    99.009901m X 12 = 1188.11881m
    99.009901m X 40 = 3960.39604m

    Volume of the top segments as trapezoidal prisms.

    V = LH(A + B)/2
    = 7722.77228 X 1188.11881 (396.039604 + 792.079208)/2
    = 5.45083426e9m^3

    Volume of the lower ones as rectangular prisms.

    V = lhw
    = 3960.39604 X 28316.831 X 7722.77228
    = 8.6607698e11m^3

    Next for the purple one.

    99.009901m X 99 = 9801.9802m
    99.009901m X 13 = 1287.12871m
    99.009901m X 16 = 1584.15842m
    99.009901m X 200 = 19801.9802m
    99.009901m X 14 = 1386.13861m
    99.009901m X 9 = 891.089109m

    Once again, volumes of the top parts are trapezoidal prisms, but given it's a trapezoidal prism on both sides, times by two.

    V = LH(A + B)/2
    = 9801.9802 X 891.089109 (1287.12871 + 1584.15842)/2
    = 1.25395394e10m^3

    Volume of the bottom segments as rectangles, assuming they're as thick as the ones the blue mugann is comprised of.

    V = lhw
    = 1386.13861 X 19801.9802 X 693.069307
    = 1.90235669e10 X 2
    = 38047133800m^3

    Not going to bother with the antannae on top. Now we have the volume of each component block, how many blocks?

    99.009901m X 59 = 5841.58416m

    The blue one has 18 rectangular blocks, while there are 18 trapezoidal blocks, so that can stay the same. Meanwhile the pink one has at least 11 to the middle of rectangular blocks, while there are 14 to the middle trapezoidal blocks on the top. That should cover half the blue trapezoidal blocks, so we'll times that by 2; as well as a quarter of the purple rectangular blocks, so we'll times that by 4; and a quarter of one of two layers of the purple trapezoidal blocks, or an eighth, so we'll times that by 8. First the blue mugann...

    V = 5.92652051e10 X 18
    = 1066773691800m^3

    V = 5.45083426e9 X 18
    = 98115016680 X 2
    = 196230033360m^3

    V = 1066773691800 + 196230033360
    = 1263003725160m^3

    ...Then the purple mugann.

    V = 38047133800 X 11
    = 418518471800 X 4
    = 1674073887200m^3

    V = 1.25395394e10 X 14
    = 175553551600 X 8
    = 1404428412800m^3

    V = 1674073887200 + 1404428412800
    = 3078502300000m^3

    The component parts of the giant muganns are dense enough to smash apart grapearls by crashing into them...

    ...so they would be pretty dense. We'll use aluminium for our low end (which weighs 2600kg/m^3) and steel for a high end (which weighs 7850kg/m^3). Once again we'll start with the blue mugann...

    (Low end)
    M = 1263003725160 X 2600kg
    = 3.28380969e15kg

    (High end)
    M = 1263003725160 X 7850kg
    = 9.91457924e15kg

    ...then have the purple one...

    (Low end)
    M = 3078502300000 X 2600kg
    = 8.00410598e15kg

    (High end)
    M = 3078502300000 X 7850kg
    = 2.41662431e16kg

    ...and finally, we'll do the final mugann, that's both of the giant muganns combined together.

    (Low end)
    M = 3.28380969e15kg + 8.00410598e15kg
    = 1.12879157e16kg

    (High end)
    M = 9.91457924e15kg + 2.41662431e16kg
    = 3.40808223e16kg

    To finish off, let's get the total height of the giant muganns.

    99.009901m X 378 = 37425.7426m (37.4257426km)
    99.009901m X 322 = 31881.1881m (31.8811881km)

    Final Drill states the giant muganns are several dozen kilometers in size...

    (Box on the upper right page)
    ...so this is pretty consistent with that. To finish off, let's also get the size of the final mugann.

    90 pixels = 5841.58416m
    1 pixel = 5841.58416m/90 = 64.9064907m
    64.9064907m X 849 = 55105.6106m (55.1056106km)

    Final Results
    Giant Blue Mugann's mass (low end) = 3.28380969e15kg
    Giant Blue Mugann's mass (high end) = 9.91457924e15kg
    Giant Purple Mugann's mass (low end) = 8.00410598e15kg
    Giant Purple Mugann's mass (high end) = 2.41662431e16kg
    Final Mugann mass (low end) = 1.12879157e16kg
    Final Mugann's mass (high end) = 3.40808223e16kg
    Giant Blue Mugann height = 37.426km
    Giant Purple Mugann height = 31.881km
    Final Mugann's length = 55.106km

  6. Sayrune moves underwater at incredible speeds. Scaling Sayrune from Gurren Lagann. From my previous calc, Kamina is 184cm tall.

    52 pixels = 184cm (1.84m)
    1 pixel = 1.84m/52 = 0.0353846154m
    0.0353846154m X 544 = 19.2492308m
    0.0353846154m X 298 = 10.5446154m
    0.0353846154m X 39 = 1.38m

    Next, we scale Gurren Lagann's head to Sayrune.

    87 pixels = 1.38m
    1 pixel = 1.38m/87 = 0.015862069m
    0.015862069m X 1598 = 25.3475863m
    1598 + 112 + 97 + 692 + 244 + 1223 + 225 = 4191 pixels
    0.015862069m X 4191 = 66.4779312m

    Not sure if the tail would be visible above water or not, so we'll go with a low end of the main body and a high end of the full length.
    Spoiler:


    Timeframe is 4 frames.

    T = 1s/24
    = 41.6666667ms X 4
    = 0.166666667s

    (Low end)
    28 pixels = 25.3475863m
    1 pixel = 25.3475863m/28 = 0.905270939m
    0.905270939m X 442 = 400.129755m

    T = 400.129755m/0.166666667s
    = 2400.77853/340.29
    = Mach 7.05509574

    (High end)
    28 pixels = 66.4779312m
    1 pixel = 66.4779312m/28 = 2.37421183m
    2.37421183m X 442 = 1049.40163m

    T = 1049.40163m/0.166666667s
    = 6296.40977/340.29
    = Mach 18.5030702

    Final Results
    Sayrune's total length = 66.478m
    Sayrune's underwater speed (low end) = Mach 7.055
    Sayrune's underwater speed (high end) = Mach 18.503

  7. General Adiane (in Sayrune) sends a giant tidal wave crashing into Dai-Gurren. Unfortunately, as all the old calcs with Gurren Lagann's size in them have crashed, we're going to need to rescale. Kamina is 184cm tall.

    52 pixels = 184cm (1.84m)
    1 pixel = 1.84m/52 = 0.0353846154m
    0.0353846154m X 544 = 19.2492308m
    0.0353846154m X 298 = 10.5446154m

    Now scaling Gurren Lagann to Dai-Gunzan/Dai-Gurren...

    142 pixels = 19.2492308m
    1 pixel = 19.2492308m/142 = 0.135557963m
    0.135557963m X 2162 = 293.076316m

    At last we can get the height of the wave.

    470 pixels = 293.076316m
    1 pixel = 293.076316m/470 = 0.62356663m
    0.62356663m X 381 = 237.578886m
    0.62356663m X 2076 = 1294.52432m

    Next we need the distance it travelled and the width of the area it covered.

    257 pixels = 237.578886m
    1 pixel = 237.578886m/257 = 0.924431463m
    0.924431463m X 2880 = 2662.36261m
    = 2*atan(257/(1612/tan(70/2)))
    = 0.150793492 rad
    = 8.63983066966117619 degrees

    When we enter this into the angscaler, we get a distance of 1572.5m of the wave to Dai-Gurren. To add the minimum distance it travelled after passing Dai-Gurren...

    L = 1572.5m + 1294.52432m
    = 2867.02432m

    With length, height and width, we can add all of those together for our volume, and from volume, our mass. Volume as a rectangular prism.

    V = lhw
    = 237.578886 X 2662.36261 X 2867.02432
    = 1.8134535e9m^3

    Water weighs 1000kg/m^3.

    M = 1.8134535e9 X 1000kg
    = 1813453500000kg

    So that's all the dimensions required for size, all we need now is the speed. How fast did the wave traverse the screen?
    Spoiler:



    Timeframe is 23 frames.

    T = 1s/24
    = 41.6666667ms X 23
    = 0.958333334s

    T = 1294.52432m/0.958333334s
    = 1350.80799m/s

    With everything we need, let's get our kinetic energy!

    KE = (0.5)mv^2
    = (0.5) X 1813453500000 X 1350.80799^2
    = 1.65448818e18 joules
    = 395.43216539196941994 megatons

    Final Results
    Gurren Lagann height = 19.249m
    Dai-Gurren length = 293.076m
    Sayrune creates a giant tidal wave = 395.432 megatons
  8. Spoiler:


    Heistotron ship grows big enough to contain the Earth and many other planets, several of which are much bigger than the Earth. The diameter of the Earth is 12756.2km.

    125 pixels = 12756.2km
    1 pixel = 12756.2km/125 = 102.0496km
    102.0496km X 2871 = 292984.402km

    Now to the very next frame, there are two potential points we can scale from, so we'll go for a low end and a high end.

    Next onto the size of the ship.

    (Low end)
    326 pixels = 292984.402km
    1 pixel = 292984.402km/326 = 898.72516km
    898.72516km X 903 = 811548.819km
    898.72516km X 1320 = 1186317.21km

    (High end)
    192 pixels = 292984.402km
    1 pixel = 292984.402km/192 = 1525.96043km
    1525.96043km X 903 = 1377942.27km
    1525.96043km X 1320 = 2014267.77km

    Final Results
    Heistotrons ships width (low end) = 811548.819km
    Heistotrons ships width (high end) = 1377942.27km
    Heistotrons ships height (low end) = 1186317.21km
    Heistotrons ships height (high end) = 2014267.77km

  9. Ricks spaceship tows the Earth away from Heistotrons collapsing ship. The diameter of the Earth is 12756.2km.

    = 2*atan(438/(493/tan(70/2)))
    = 0.796879139 rad
    = 45.6578114468321345 degrees

    If we enter these values into the trusty anscaler, then we can determine that the Earth is currently 15151km away.

    The timeframe is 3 seconds and 1 frame.

    T = 1s/24
    = 41.6666667ms + 3s
    = 3.04166667s

    = 2*atan(621/(493/tan(70/2)))
    = 1.07617595 rad
    = 61.660339948634871 degrees

    The Earth is now 10687km away. Next we determine how far the Earth moved in the timeframe given.

    D = 15151km - 10687km
    = 4464km

    T = 4464km/3.04166667s
    = 1467616.44m/s

    The Earth has a mass of 5.9736 X 10^24kg (or 5.9736e24kg).

    KE = (0.5)mv^2
    = (0.5) X 5.9736e24 X 1467616.44 ^2
    = 6.43326259e36 joules
    = 1.5375866610898663112 ninatons

    Final Results
    Rick's spaceship tows the Earth = 1.538 ninatons
  10. A continuation from a previous blog of mine, where I posted the evidence that Gurren Lagann's cosmology is not only a universe, but a vast macrocosmos of every possible multiverse along an infinite chain of universes. For more on the scale of the macrocosmos and feats, please see there. However, there are several major points that people use to downplay Gurren Lagann; the Spiral Nemesis threatening the universe, how can the Anti-Spiral create a multiverse if they where afraid of the destruction of a universe and Tengen Toppa Gurren Lagann being hurt by a Big Bang level attack. I will debunk all of these in this blog, as well as describe the nature of the cosmology and the scale of the feats in the series.

    First off, the Spiral Nemesis. This is used as one of the key points to claim the Anti-Spiral isn't multiversal. However, let's have a closer look;

    Please note the terminology used by the Anti-Spiral during this sequence;
    This universe. The thing about that is the Anti-Spiral are very explicitly in a different universe to the main one; the one Simon and Team Super Galaxy Dai-Gurren originate from and the Anti-Spiral's pocket universe.

    So going from the show alone, we already have the Anti-Spiral fighting to prevent the Spiral Nemesis in multiple universes. Said Anti-Spiral dimension exists beyond "the" multiverse as a whole.
    https://www.gurren-lagann.net/tv/news/index.html
    Indeed, there are actually several universes Team Super Galaxy Dai-Gurren come from. When asked how Rossiu found LordGenome's head, Kazuki Nakashima begins by saying how there's a different version of how this happened in the DVD commentary and the novelization, and finishes by saying that as there are different versions that are prefered, as Gurren Lagann is the story of a multiverse, the version you, the viewer, prefers, can be the right one.

    (Relevant text)

    Though a lot of the above is from a machine translation, the following sentence;
    I got someone who speaks Japanese to translate. So, there are different parallel universes, even outside the Anti-Spiral Labyrinth. In the movies, we have a shot of the macrocosmos at the start of the first movie...

    ...and this same macrocosmos when Team Dai-Gurren is escaping "the" multiverse.

    Note please that LordGenome ponders what the Universe is with a shot of the multiverse, this will be important later. In relation to the first gif posted above;

    (Relevant text)

    So the macrocosmos, or "the" multiverse is infinite, and exists naturally. As for how this relates to the Anti-Spiral, by manipulating probability, dimensions and the fabric of space-time the Anti-Spiral set up the Multiversal Labyrinth from the pre-existing multiverses, where Universe branches infinitely into infinite more universes, and those into infinite more universes, and so on forever.

    (Relevant text)


    (Relevant text)

    As said above, the Anti-Spiral do this by controlling the multiple dimensions.

    (Relevant text is in the black box on the right).
    Now we'll leave the Labyrinth for a bit and go back to explain all this, and the basis on how Gurren Lagann's cosmology works. One of the most important descriptions of Gurren Lagann's cosmology comes from episode 23, when we are introduced to the Quantum Universe Theory.

    This sets up some very important frames of how the cosmos works in Gurren Lagann. LordGenomes states what we call the universe, which is very important phrasing, "what we call the universe", not just "the universe," implying directly the cosmos is more than just one universe. Infact, he goes on to explain that these laws also apply in a pocket universe, as well as the 11 dimensional universes.

    Though the movie gives an abridged version of this speech, it is in a way even better, as its said whilst travelling between universes.

    As for the laws in question, he says that the Universe is constructed on ambiguity, and only becomes fixed when observed. This is alluded to through the Ashtanga's attacks, where they can perform Schrodinger Warps to attack along the time axis through multiple dimensions, existing everywhere and nowhere at once in local space-time (for more on the Schrodinger Warp and the Maelstrom Vortex Cannon, see here).


    Then the Anti-Spiral throws the humans into the Labyrinth, a causal trap in which they are trapped in between dimensions, forced to observe all possible universes simultaneously as they are created instant to instant.

    The universes are created instant to instant as they are perceived. This is in line with what LordGenome said earlier about the Universe existing in a state of uncertainty, and becoming a fixed reality when observed.

    The Anti-Spiral soon after follows up with this;

    On top of everything already said, the multiverse is very explicitly real, and the reason that Team Super Galaxy Dai-Gurren are in the bridge of Super Galaxy Dai-Gurren is firstly because they are trapped in extra-dimensional space (as said above), and secondly because their awareness is forced to perceive the different possibilities.

    There is no evidence of any kind that the multiverse is an illusion, and there is evidence from every source to the direct contrary.

    With all that out of the way, we can clearly see the context of the term "universe" being interchangable with "cosmos," or "everything." Ergo, it is not contradictory that the Anti-Spiral would be able to control the multiverse, or that they would be afraid of the Spiral Nemesis.

    Simon escapes the Labyrinth by merging together infinite alternate versions of himself together.


    Simon not only merges with all iterations from every possible universe, but every possible multiverse.

    (The relevant text)

    This says that Simon expands through space to every possible multiverse that his friends where trapped in.
    After escaping the Multiversal Labyrinth, Simon creates the galaxy-sized Tengen Toppa Gurren Lagann, which creates the Super Spiral Space inside it.
    https://www.japanator.com/the-secrets-of-gurren-lagann-answered--6714.phtml
    The Super Spiral Space is composed of every possible Gurren Lagann from the macrocosmos.

    (From the above posted page)

    During the series, there are infinite Simons, infinite Gurren Laganns, but during the final battle, there is only one Simon in one Gurren Lagann against one Anti-Spiral.

    Backing up all of the above, in an interview about how the time travel works in Batman Ninja, Nakashima says that thanks to the multiverse, rather than travelling back to the same timeline, Batman travels to another timeline. He then goes on to describe the multiverse and the changing perception of time, from 4 dimensions to 11. The interviewer then asks about the quantum cosmology mentioned in Gurren Lagann. To this, Nakashima says at the time of writing Gurren Lagann he was reading up on astrophysics, and how universes become real when observed, and he sent this idea to Gainax. This not only backs up further that Gurren Lagann is a multiverse, but also that the multiverse in Gurren Lagann is based off real theoretical quantum physics.
    https://mediag.bunka.go.jp/article/article-15013/
    Last, but not least, there is the description of the Quantum Universe Theory from the Gurren Lagann glossary in Final Drill.

    (Relevant text)

    This connects the Quantum Universe Theory, which entails infinite branching multiverses, back to the Big Bang.

    The Anti-Spiral throws an attack equivalent to the Big Bang at Tengen Toppa Gurren Lagann. Which they withstand for several minutes.

    On another note like this, though most theories of the Big Bang state the Big Bang created the universe, there are some that entail that it created a multiverse.

    So in conclusion, Gurren Lagann having multiversal feats, and even feats beyond multiversal, are not contradictory as previously believed, but perfectly consistent with what has been set up in both the series and the supplimentary materials.

    To reiterate on my argument...
    • The Universe (which is interchangable with multiverse, cosmos or macrocosmos) exists in a state of quantum uncertainty, with all possibilities existing in a schrodinger state until observed
    • Observing reality fixes it in place along the timeline
    • Time exists across at least 11 dimensional universes
    • A possibility that isn't observed in one universe becomes observed in another; this is "the" Multiverse
    • The macrocosmos branches infinitely into every possible multiverse along the infinite chain
    • All of these possibilities where created by the Big Bang
    • The Anti-Spiral's penultimate attack is on par with the Big Bang
    • The Anti-Spiral's pocket universe exists beyond the multiverse, where they fight to stop the Spiral Nemesis from destroying everything
    • The Anti-Spiral transcend space, time and gravity, and can control physics and probability
    • The Anti-Spiral did not create the multiverse, but by controlling probability and dimensions they were able to set up the Labyrinth
    • Simon broke free of causality by merging every possible version of himself from every possible multiverse
    • Tengen Toppa Gurren Lagann is the Super Spiral Space, which was created by merging all possible Gurren Lagann's together
  11. Something that's been around for a while now, but I feel gets somewhat overlooked. Super Galaxy Gurren Lagann is stated to generate energy comparable to a microcosmos.

    Later, Leeron comments that it's as if a galaxy is about to be born inside Super Galaxy Gurren Lagann.

    Super Galaxy Gurren Lagann has power comparable to a galaxy being born. If the above isn't enough evidence, Final Drill outright confirms it;

    (The relevant part)

    Super Galaxy Gurren Lagann can generate power enough to create a galaxy. Given that a lot of transformations are done through mass-energy (giga drills, regeneration, the Death Spiral Abyss), this should be likewise too. We'll use a low end of the Lesser Magellanic Cloud, a mid end of the Milky Way and a high end of IC 1101. The Lesser Magellanic Cloud has a mass of approximately 3,000,000,000 solar masses, the Milky Way has a mass of roughly 1,500,000,000,000 solar masses and IC 1101 has a mass of more than 100,000,000,000,000 solar masses. One solar mass is 1.989 X 10^30kg (or 1.98900e30kg).

    (Low end)
    M = 3,000,000,000 X 1.98900e30kg
    = 5.96700e39kg

    E = mc^2
    = 5.96700e39 X 299792458^2
    = 5.36287215e56/10^44
    = 5.36287215 TERAFOE

    (Mid end)
    M = 1,500,000,000,000 X 1.98900e30
    = 2.9835e42kg

    E = mc^2
    = 2.9835e42 X 299792458^2
    = 2.68143608e59 /10^44
    = 2.68143608 PETAFOE

    (High end)

    M = 100,000,000,000,000 X 1.98900e30kg
    = 1.98900e44kg

    E = mc^2
    = 1.98900e44 X 299792458^2
    = 1.78762405e61/10^44
    = 1.78762405 EXOFOE

    Final Results
    Super Galaxy Gurren Lagann's engine power (low end) = 5.363 TERAFOE
    Super Galaxy Gurren Lagann's engine power (mid end) = 2.681 PETAFOE
    Super Galaxy Gurren Lagann's engine power (high end) = 1.788 EXOFOE


    Consistent with the power that Super Galaxy Gurren Lagann absorbed from the Spiral Death Field and Kittan's sacrifice, and still well below the Maelstrom Mega Vortex Cannon.

  12. Skywell-27, a satalite laser powered by a fragment of the Vault Key, fires upon Promethia, causing a colossal explosion. Assuming Promethia is Earth-like is size. Earth has a diameter of 12,742km.

    866 pixels = 12,742km
    1 pixel = 12,742km/866 = 14.7136259km
    14.7136259km X 80 = 1177.09007km
    1177.09007km/2 = 588.545035km

    Now, entering those values into the nuke calculator and messing around, we get our match with the radius for widespread destruction at 616500 megatons, or 616.5 gigatons. This is with one fragment of the Vault Key too, which in total is comprised of three parts.

    E = 616500 X 3
    = 1849500 megatons
    = 1.8495 teratons

    Now let's get the speed of the laser.
    = 2*atan(866/(1080/tan(70/2)))
    = 0.726170303 rad
    = 41.6064935697393921 degrees

    Enter that through the angscaler and we have a distance of 16,769km. Next we get our timeframe.

    Spoiler:


    Timeframe is 5 frames.
    T = 1s/24
    = 41.6666667ms
    = 0.208333333s

    T = 16769km/0.208333333s
    = 80491200.1/299792458 X 100
    = 26.8489743% C

    Final Results
    Skywell-27s firepower = 616.5 gigatons
    Vault Key's power = 1.85 teratons
    Skywell-27 laser speed = 26.849% C


    Though no one reacts to the laser, this backs up that lasers in Borderlands are legitimately lasers, and other showings of reacting to lasers are relativistic to lightspeed. On top of Skywell-27 being very explicitly weaker than the Helios, the creatures of the Vault are the power of the Vault, this would scale to the Rampager and back to the Vault Hunters and Maya, which is consistent with other feats in previous installments.

  13. Shirou becomes Ginrou through an unknown necromantic ritual, where he absorbs the blood of thousands of his brethren. This causes a huge explosion of blood. We can scale the size of the bloodburst from the size of the pit. First the get the pits depth. The average length of a horse is 8 feet, or 2.4m.
    Spoiler:





    1158 + 578 + 1282 = 3018 pixels
    1111 pixels = 2.4m
    1 pixel = 2.4m/1111 = 0.00216021602m
    0.00216021602m X 3018 = 6.51953195m

    Now we can finally get to scaling the dimensions of the blood burst.
    Spoiler:


    217 pixels = 6.51953195m
    1 pixel = 6.51953195m/217 = 0.030043926m

    0.030043926m X 2520 = 75.7106935m
    0.030043926m X 1173 = 35.2415252m

    Now for the timeframe of the expansion of the blood bulb.
    Spoiler:


    The timeframe is 2 seconds and 11 frames.

    T = 1s/24
    = 41.6666667ms X 11
    = 0.458333334s + 2s
    = 2.45833333s

    T = 35.2415252m/2.45833333s
    = 14.3355357m/s

    Finally, for our mass. This is the easiest part, as we're outright given the number of bodies in the pit. The average person has 1.2 to 1.5 gallons of blood, or an average of 1.35 gallons.
    https://www.livescience.com/32213-how-much-blood-is-in-the-human-body.html
    We also have the number of fellow beastmen who's blood got absorbed by Ginrou; 2000.
    Spoiler:



    1 gallon is equivalent to 3.7854kg.

    M = 1.35 X 2000
    = 2700 X 3.7854kg
    = 10220.58kg

    KE = (0.5)mv^2
    = (0.5) X 10220.58 X 14.3355357^2
    = 1050203.35 joules

    Let's also add the GPE. First, we have to find the centre of gravity for the hemisphere.

    CG = 3 X r/8
    = 3 X 35.2415252/8
    = 13.2155719m

    E = 13.2155719 X 9.807 X 10220.58
    = 1324639.43 joules

    Now, to add the two together...

    E = 1050203.35 + 1324639.43
    = 2374842.78 joules

    Final Results
    Ginrou's blood bubble = >2374842.78 joules


    That's it? I'm honestly surprised at how low this is, but given there's an explosion afterwards, the final result would ultimately be even higher.
  14. Calc request for a friend elsewhere.

    Tanjiro splits a boulder in half with his sword. This calc is also on VBW, but given my friend wants me to try again with different scaling as the VBW calc has the boulder too small, so I may as well do so. Tanjiro is 165cm tall.

    407 + 251 = 658 pixels
    658 pixels = 165cm
    1 pixel = 165cm/658 = 0.250759878cm
    0.250759878cm X 116 = 29.0881458cm

    100 pixels = 29.0881458cm
    1 pixel = 29.0881458cm/100 = 0.290881458cm
    0.290881458cm X 883 = 256.848327cm (2.56848327m)
    256.848327cm/2 = 128.424163cm

    Next we need the area cut.

    A = πr^2
    = π X 128.424163^2
    = 51813.5514cm^2 (5.18135514m^2)

    Next for the MPa. The MPa of medium strength rock is between 40 MPa to 80 MPa, or an average of 60 MPa (or 60000000 N/m^2).

    Now the energy to change that from tensile force to sheer force;
    https://en.wikipedia.org/wiki/Shear_force
    F = 60000000 X 5.18135514 X 0.6
    = 186528785 N

    To change that from newtons to joules, we times that by our diameter.

    E = 186528785 X 2.56848327
    = 479096064 joules
    = 0.114506707457 tons of TNT

    Final Results
    Tanjiro cuts a boulder in half = 0.115 tons of TNT

  15. Yggdrasil's propulsion power forcibly increased the Earth's orbital speed. The gauge constantly gets higher, but the highest speed we get is 3122m/s. This will be more or less straightforward. The Earth weighs The Earth has a mass of 5.9736e24kg.



    KE = (0.5)mv^2
    = (0.5) X 5.9736e24 X 3122^2
    = 2.91119931e31 joules
    = 6.9579333413001904773 zettatons

    Final Results
    Yggdrasil's core increases the Earth's orbital speed = 6.958 zettaons
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