1. img
    Enter in the Alley Banner Contest!
    Deadline for entries is December 15th.
    Dismiss Notice
  2. Welcome to the forums! Take a second to look at our Beginner's Guide. It contains the information necessary for you to have an easier experience here.

    Thanks and have fun. -NF staff
    Dismiss Notice
Color
Background color
Background image
Border Color
Font Type
Font Size
  1. The High Epic Regalia uses her water powers to flood Manhattan, raising the water around Manhattan around 100 feet, which she also sustains. 100 feet is 30.48m (half of which is 15.24m), and Manhattan has a surface area of 59.1km^2, or 5.91e+7m.

    V = 5.91e+7 X 30.48
    = 1801368000m^3

    Weight of water is 1000kg/m^3.

    M = 1801368000 X 1000
    = 1801368000000kg

    We'll get our energy with GPE.

    E = 15.24 X 9.807 X 1801368000000
    = 2.69230083e14 joules
    = 64.3475341778202647 kilotons

    Final Results
    Regalia floods Manhattan = 64.348 kilotons
  2. Calc request for @Kaaant .

    16:40

    A Darkside artifact moves the celestial bodies of Endor. Now, there are two ways in which we'll be doing this. Endor has a diameter of 4,900km, so the moons would be smaller than that. For the larger of the two bodies, we'll be using Earth's Moon Luna, which has a mass of 7.34767309e22kg and a diameter of 3474.8km. For the smaller of the two, we'll be using Saturns moon Dione, which has a diameter of 396km and a mass of 10^20kg.
    Spoiler:


    Timeframe is 2.98 seconds.

    212 pixels = 396km
    1 pixel = 396km/212 = 1.86792453km
    1.86792453km X 242 = 452.037736km

    377 pixels = 3474.8km
    1 pixel = 3474.8km/377 = 9.21697613km
    9.21697613km X 330 = 3041.60212km

    T = 452.037736km/2.98s
    = 151690.515m/s

    KE = (0.5)mv^2
    = (0.5) X 1.0e20 X 151690.515^2
    = 1.15050062e30 joules

    T = 3041.60212km/2.98s
    = 1020671.85m/s

    KE = (0.5)mv^2
    = (0.5) X 7.34767309e22 X 1020671.85^2
    = 3.82729646e34 joules

    Now, we add those up for our final yield.

    E = 1.15050062e30 + 3.82729646e34
    = 3.82741151e34 joules
    = 9.1477330544933082024 yottatons

    That's really impressive, but a thought's come to mind that might make this even more impressive. Endor doesn't have any moons because it is a moon, and would instead have a plant it orbits, and other moons that orbit around said planet, and it appears similar in size to the larger of the celestial bodies in the above video...
    https://starwars.fandom.com/wiki/Endor_(planet)/Legends

    The planet of Endor is a gas giant with a diameter of 148,000km (or 148,000,000m). Jupiter has a diameter of 142,984km (or 142,984,000m) and a mass of 1.9e27kg. Now we use square law to determine the planet Endor's second mass.

    M2 = (H2/H1)^3*M1
    = (148,000,000/142,984,000)^3*1.9e27
    = 2.10705766e27kg

    We don't know much about the other moons of Endor, other than the Sistermoon (of which we still know nothing really), so for the smaller celestial body we'll go with the dimensions of the Moon.

    212 pixels = 3474.8km
    1 pixel = 3474.8km/212 = 16.390566km
    16.390566km X 242 = 3966.51697 kilokmters

    T = 3966.51697km/2.98s
    = 1331045.96m/s

    KE = (0.5)mv^2
    = (0.5) X 7.34767309e22 X 1331045.96^2
    = 6.50887503e34 joules

    377 pixels = 148,000km
    1 pixel = 148,000km/377 = 392.572944km
    392.572944km X 330 = 129549.072km

    T = 129549.072km/2.98s
    = 43472843m/s

    That's more than fast enough to be reletavistic, so entering that through the relativistic kinetic energy calculator gets us a yield of 2.023E+42 joules! Adding that together with the above...

    E = 6.50887503e34 + 2.023E+42
    = 2.02300007e42 joules
    = 483.5086293690252304 tenatons

    I'm pretty sure that's higher than what the Death Star was calced at...

    Final Results
    Darkside Ewok artefact moves celestial bodies (low end) = 9.148 yottatons
    Darkside Ewok artefact moves celestial bodies (high end) = 483.509 tenatons
  3. Calc request for @Veggie and @Claudio Swiss .

    A bunch of novice Green Lanterns survive a supernova. In order to go supernova, a star needs to have at least 8 solar masses. Red Giants at their highest weigh 8 solar masses, and have a diameter of at least 100,000,000.

    = 2*atan(184/(666/tan(70/2)))
    = 0.260327296 rad
    = 14.9156553528899174 degrees

    Enter this into the angscaler, and we have a distance from the Sun to the Green Lanterns as 381960000km (or 381960000000m) away. Looking at ChaosTheory123's Ood Bnar calc for reference. The average surface area of a man is 1.9m^2.

    A = 4πr^2
    = 4 Xπ X 381960000000^2
    = 1.83335106e24m^2

    A = 1.9/1.83335106e24
    = 1.03635362e-24m^2

    The energy of a supernova is 10^44 joules.

    E = 10^44 X 1.03635362e-24
    = 1.03635362e20 joules
    = 24.769445984703629904 gigatons

    Final Results
    Green Lanterns survive a supernova = 24.769 gigatons

    Not as impressive as the supernova itself, I'm afraid.

  4. 41:50

    Chevalier Renald performs a blatantly superhuman jump. The average height of a man is 5 feet 9 inches, or 1.7526m.

    37 pixels = 1.7526m
    1 pixel = 1.7526m/37 = 0.0473675676m
    Spoiler:


    Timeframe is 0.09 seconds.
    0.0473675676m X 172 = 8.14722163m

    T = 8.14722163m/0.09s
    = 90.5246848m/s

    Final Results
    Chevalier Renald's jump = 90.525m/s


    Not as much as I thought it would be, but still blatantly superhuman and pretty impressive.

  5. 55:29

    54:49
    Spoiler:


    A dragon summons a storm on a mostly clear blue day. Keep in mind this is not a legendary super powerful dragon, or even a named dragon. This is just a generic nameless dragon.
    https://forums.elderscrollsonline.com/en/discussion/493609/pts-patch-notes-v5-2-0
    Given it's a storm cloud, and storms are created by cumulonibi, we'll go with the height of a cumulonimbus, which on average is 12,000m. Distance to the horizon from the viewpoint of the average height is 4.7km, or 4700m. Volume as a cylinder.

    V = πr^2h
    = π X 4700^2 X 12000
    = 8.32773381e11m^2

    Density of a cumulus cloud is around 0.5 grams per m^3.

    M = 8.32773381e11 X 0.5
    = 416386690500g
    = 416386690.5kg

    Condensation of water vapour to liquid is 2260 joules per gram.

    E = 416386690500 X 2260
    = 9.41033921e14 joules

    That's impressive, but we can also get the kinetic energy, as we can clearly see the clouds moving in from the horizon.
    Spoiler:


    1.22 seconds.

    T = 4700m/1.22s
    = 3852.45902m/s

    KE = (0.5)mv^2
    = (0.5) X 416386690.5 X 3852.45902^2
    = 3.08988915e15 joules

    Now to add both together for our final results.

    E = 9.41033921e14 + 3.08988915e15
    = 4.03092307e15 joules
    = 963.4137356596557993 kilotons

    Final Results
    Generic Dragon Storm Call = 963.414 kilotons


    Scales to Durnahviir, Odahviing and every dragon ever, as well as Dovahkiin, the Dragon Priests, Olaf One-Eye, Reman's Dragonguard and a ton of other characters.
  6. In season the season 3 the scope really goes up, namely with the introduction of Horde Prime and his fleets. So let's get us some calcs. Also because this is on Netflix and I couldn't find any other versions of this scene, I couldn't really make any gifs I'm afraid, though still images should work.
    Spoiler:






    1. First planetary bombardment
    Horde Primes fleets bombs a planet and creates some considerable explosions with super fast lasers.
    Spoiler:




    Timeframe is 1 second (though in actuality it would be even less, at it travels across the screen in only part of a second). First off, to find the radius of the planet, assuming it's Earth-sized (which has a radius of 6378.1km, or a diameter of 12,742km).

    R = (h/2) + c^2/(8h)
    = (292/2) + 1506^2/(8 X 292)
    = 1116.90582

    6378.1km = 1116.90582 pixels
    1 pixel = 6378.1km/1116.90582 = 5.71050834km
    5.71050834km X 2100 = 11992.0675km

    T = 11992.0675km/1s
    = 11992067.5/340.29
    = Mach 35240.7285

    And keep in mind that would be a low end, and I was unable to calculate or pause from fractions of a second.

    5.71050834km X 474 = 2706.78095km
    2706.78095km/2 = 1353.39047km

    Enter that through the nuke calculator using the above radius of 1353.39047km and playing around and find that for the widespread destruction airburst we get a result of 7710100 megatons, or 7.710100 teratons. Going for a high end of fireball radius, we get 548490000 megatons, or 548.490000 teratons.

    2. Second planetary bombardment and giant ships
    Similar to the first, but this time we have a much, much bigger ship. Once again assuming an Earth-like size for the planet...
    Spoiler:



    542 pixels = 12,742km
    1 pixel = 12,742km/542 = 23.5092251km
    23.5092251km X 90 = 2115.83026km
    23.5092251km X 51 = 1198.97048km
    2115.83026km - 1198.97048km = 916.85978km
    23.5092251km X 710 = 16691.5498km
    23.5092251km X 100 = 2350.92251km
    2350.92251km/2 = 1175.46125km
    23.5092251km X 2613 = 61429.6052km
    23.5092251km X 2013 = 47324.0701km
    23.5092251km X 1086 = 25531.0185km
    23.5092251km X 726 = 17067.6974km

    First off for the explosion. Once again messing around with the nuke calculator for a radius of 1175.46125km, we get a low end of 5029000 megatons and a high end of 385290000 megatons, or 5.029000 teratons and 385.290000 teratons respectively.

    Next for the speed of the lasers (remember again that this was a low end, and the lasers flew this distance in a fraction of a second.

    T = 16691.5498km/1s
    = 16691549.8/340.29
    = >Mach 49050.9559

    Let's also get the cruising speed of the ship.

    T = 916.85978km/1s
    = 916859.78/340.29
    = Mach 2694.34829

    Final Results
    Ships shoots planet = >Mach 35240.726
    Bombardment explosion on first planet (low end) = 7.710 teratons
    Bombardment explosion on first planet (low end) = 548.49 teratons
    Giant ship length = 61429.605km
    Bombardment explosion on second planet (low end) = 5.029 teratons
    Bombardment explosion on second planet (high end) = 385.29 teratons
    Giant ship shoots second planet = >Mach 49050.956
    Giant ship cruising speed = Mach 2694.348


    There's also the kinetic energy the giant ship would generate, but unfortunately we can't see the other side of the ship, and thus can't scale its full dimensions.
  7. There's a great number of feats in the the Steven Universe movie. Now...where to begin?
    Spoiler:
    1. Dimensions of Spinel's injector
    Spinel's injector is important to many of these feats & calcs, so we're going to need its size and mass. Scaling the size of the injector. A commercial door should be at least 80 inches tall, or 2.03200m.

    8 pixels = 2.03200m
    1 pixel = 2.03200m/8 = 0.254m
    0.254m X 11 = 2.79400m
    0.254m X 88 = 22.35200m
    22.35200m/2 = 11.17600m
    11.17600m - 2.79400m = 8.38200m
    0.254m X 158 = 40.13200m
    40.13200m - 2.79400m = 37.33800m
    0.254m X 135 = 34.29m
    34.29m/2 = 17.14500m
    17.14500m - 2.79400m = 14.35100m
    0.254m X 36 = 9.14400m
    0.254m X 170 = 43.18m
    43.18m/2 = 21.59m
    21.59m - 2.79400m = 18.79600m
    0.254m X 69 = 17.52600m
    17.52600m - 2.79400m = 14.73200m
    0.254m X 36 = 9.14400m
    0.254m X 130 = 33.02m
    33.02m/2 = 16.51m

    0.254m X 490 = 124.46m
    0.254m X 142 = 36.06800m
    36.06800m/2 = 18.03400m
    0.254m X 111 = 28.19400m
    28.19400m/2 = 14.09700m
    0.254m X 28 = 7.11200m
    0.254m X 16 = 4.06400m
    0.254m X 108 = 27.43200m
    27.43200m/2 = 13.71600m
    0.254m X 17 = 4.31800m

    0.254m X 18 = 4.57200m
    0.254m X 104 = 26.41600m
    26.41600m/2 = 13.20800m
    0.254m X 125 = 31.75m
    31.75m/2 = 15.87500m
    0.254m X 182 = 46.22800m
    46.22800m/2 = 23.11400m
    0.254m X 132 = 33.52800m
    0.254m X 147 = 37.33800m
    37.33800m/2 = 18.66900m
    0.254m X 27 = 6.85800m

    Despite all that, scaling should be pretty easy, as each part is a conical frustrum. First for the glass part and its interior...

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (11.17600^2 + 11.17600 X 17.14500 + 17.14500^2) X 40.13200
    = 25655.5467m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) π (8.38200^2 + 8.38200 X 14.35100 + 14.35100^2) X 37.33800
    = 15503.2229m^3

    V = 25655.5467 - 15503.2229
    = 10152.3238m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (11.17600^2 + 11.17600 X 21.59 + 21.59^2) X 17.52600
    = 15275.7392m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (8.38200^2 + 8.38200 X 18.79600 + 18.79600^2) X 14.73200
    = 8964.74466m^3

    V = 15275.7392 - 8964.74466
    = 6310.99454m^3

    V = 10152.3238 + 6310.99454
    = 16463.3183m^3

    V = 14343.1178 + 7264.53446
    = 17623.4234m^3

    Next for the lower machine parts...
    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (16.51^2 + 16.51 X 21.59 + 21.59^2) X 9.14400
    = 10486.7775m^3

    Now for the upper machine parts...
    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (14.09700^2 + 14.09700 X 18.03400 + 18.03400^2) X 7.11200
    = 5795.59624m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (13.71600^2 + 13.71600 X 14.09700 + 14.09700^2) X 4.06400
    = 2469.2577m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (14.09700^2 + 14.09700 X 21.59 + 21.59^2) X 4.31800
    = 4382.56261m^3

    V = 10486.7775 + 5795.59624 + 2469.2577 + 4382.56261
    = 23134.194m^3

    And last of all for the giant gem on the top.
    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) π (13.20800^2 + 13.20800 X 15.87500 + 15.87500^2) X 4.57200
    = 3045.72157m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (15.87500^2 + 15.87500 X 23.11400 + 23.11400^2) X 33.52800
    = 40489.6176m^3

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (18.66900^2 + 18.66900 X 23.11400 + 23.11400^2) X 6.85800
    = 9438.91054m^3
    = 9438910540cm^3

    Next for the mass. Given that the giant injector is Spinel's and the gem is pink, I'm going to assume the gem is a giant spinel. Spinel has a specific gravity of 3.65/cm^3. For a brief description fo what specific gravity means...
    https://www.gemselect.com/gem-info/specific-gravity.php
    M = 9438910540 X 3.65
    = 34452023471g
    = 34452023.471kg

    Next up for the transparent part. Glass weighs 2579kg/m^3.

    M = 16463.3183 X 2579
    = 42458897.9kg

    As for any machine parts, I'll be using the light ship mass of container vessel 2700TEU is 102.56kg/m^3. I'm pretty sure that's a huge low ball, but it's the best I have at the moment.

    M = 23134.194 X 102.56
    = 2372642.94kg

    At last, lets get our total mass for when it's empty.

    M = 34452023.471 + 42458897.9 + 2372642.94
    = 79283564.3kg

    Next for its total mass when full. Not sure what exactly the poisonous goop is, but it should be safe to assume a weight of water (1000kg/m^3).

    M = 17623.4234 X 1000
    = 17623423.4kg

    M = 79283564.3 + 17623423.4
    = 96906987.7kg
    = 96906.9877 tons

    Now all of that is finally out of the way, let's get to the feats!

    2. Spinel punches Steven into the injector

    1:45

    Spinel enlarges her fist so its mass alone pushes back the clouds, and punches Steven into her gem injector hard enough to break the ground beneath it and pushes up the toxic gunk and create a dust cloud.
    Spoiler:





    Timeframe for pushing down the injector is 0.06 seconds, while the timeframe of her fist coming down is 0.21 seconds.

    267 pixels = 124.46m
    1 pixels = 124.46m/267 = 0.466142322m
    0.466142322m X 171 = 79.7103371m
    0.466142322m X 105 = 48.9449438m
    0.466142322m X 120 = 55.9370786m
    55.9370786m - 48.9449438m = 6.9921348m

    T = 6.9921348m/0.06s
    = 116.53558m/s

    After all of that, let's get our kinetic energy for moving the injector.

    KE = (0.5)mv^2
    = (0.5) X 17623423.4 X 116.53558^2
    = 1.19667816e11 joules
    = 28.6012944550669 tons of TNT

    Let's also get the speed, shall we?

    T = 79.7103371m/0.21s
    = 379.573034/340.29
    = Mach 1.11543987

    3. Steven lifts Spinels injector

    38:04

    Steven, who's lost control over his powers, briefly lifts Spinels injector. Steven is 16, by this point, and the average height of a 16 year old boy is 5 feet 7 inches, or 1.7018m (though I've a feeling Steven's a bit shorter than that, it's the best we have to go with for now).
    Spoiler:



    Timeframe is 1.21 seconds.

    171 - 162 = 9 pixels
    102 + 43 = 145 pixels = 1.7018m
    1 pixel = 1.7018m/145 = 0.0117365517m
    0.0117365517m X 9 = 0.105628965m

    T = 0.105628965m/1.21s
    = 0.0872966653m/s

    Right before this, Peridot notes that 15.4% of the injector's contents have been released.
    https://steven-universe.fandom.com/wiki/Steven_Universe:_The_Movie/Transcript
    M = 17623423.4 X 15.3%
    = 17623423.4 - 2714007.2
    = 14909416.2 + 79283564.3
    = 94192980.5kg

    Let's get GPE and KE.

    KE = (0.5)mv^2
    = (0.5) X 94192980.5 X 0.0872966653^2
    = 358908.589 joules

    E = 0.105628965 X 9.807 X 94192980.5
    = 97574815.5 joules

    E = 97574815.5 + 358908.589
    = 97933724.1 joules
    = 0.02340672182122 tons of TNT

    4. Spinel's injector explodes

    0:46

    Spinel's injector explodes, and Steven's shield tanks it at point blank just fine.
    Spoiler:


    Timeframe is 0.27 seconds.

    79 pixels = 46.22800m
    1 pixel = 46.22800m/79 = 0.585164557m
    0.585164557m X 242 = 141.609823m
    141.609823m/2 = 70.8049115m
    0.585164557m X 258 = 150.972456m
    150.972456m/2 = 75.486228m
    0.585164557m X 124 = 72.5604051m
    72.5604051m/2 = 36.2802025m
    0.585164557m X 50 = 29.2582279m

    T = 75.486228m/0.27s
    = 279.578622m/s

    Volume of the top part as an ellipsoid and the bottom part as a cylinder.

    V = 4/3πabc
    = 4/3 X π X 70.8049115 X 70.8049115 X 75.486228
    = 1585196.49m^3

    V = πr^2h
    = π X 36.2802025^2 X 29.2582279
    = 120986.607m^3

    V = 1585196.49 + 120986.607
    = 1706183.1m^3

    Weight of a dust cloud/air is 1.003kg/m^3.

    M = 1706183.1 X 1.003
    = 1711301.65kg

    Finally, for our energy.

    KE = (0.5)mv^2
    = (0.5) X 1711301.65 X 279.578622^2
    = 6.68812672e10 joules
    = 15.985006500956 tons of TNT


    Final Results
    Spinel's Injector height = 124.46m
    Spinel's injector mass (empty) = 79283564 kg
    Spinel's injector mass (full) = 96906988kg
    Spinel punches Steven (energy) = 28.601 tons of TNT
    Spinel punches Steven (speed) = Mach 1.115
    Steven lifts Spinel's injector = 0.023 tons of TNT
    Spinel's injector explodes = 15.985 tons of TNT

    Not the greatest feats gems have demonstrated in terms of strength, speed and lifting, but it's consistent so it's nice. Keep in mind that Spinel is the equivalent of a Jester with no known combat training.
  8. Mr Wednesday tells Shadow to think of snow, which he does, and this creates snow. Shadow imagines that the snow will cover Chicargo, and that there will be 12 inches of it, so this should be relatively straight forward. Chicargo covers an area of 606.1km^2, or 6.061e+8m^2. 12 inches is 30.48cm, or 0.3048m.

    V = 6.061e+8 X 0.3048
    = 184739280m^3

    Newly fallen snow weighs between 70kg to 150kg per m^3 (or an average of 110kg), while snowpacks range from 200kg to 300kg per m^3 (or an average of 250kg).
    https://www.islandnet.com/~see/weather/almanac/arc2007/alm07feb.htm
    (Low end)

    M = 184739280 X 110
    = 20321320800kg

    (High end)

    M = 184739280 X 250
    = 46184820000kg

    This scene if I recall correctly took place before Christas and Winter, so is likely at some point in Autumn, the temperatures of Autumn being variable, and an average will be gathered below (from the temperatures in celcius).

    T = −18 + 21 + 21 + 22 + 24 + 32 + 34 + 37 + 38
    = 211/9
    = 23.4444444

    Specific heat of air between 0 and 40 degrees celsius is 1.005 kilojoules. We can also add the heat fusion of oxygen, which is is 13800 joules/kg.

    (Low end)
    E = 23.4444444 X 1.005 X 20321320800
    = 4.78804186e11 kilojoules
    = 4.78804186e14 joules

    E = 20321320800 X 13800
    = 2.80434227e14 joules

    E = 4.78804186e14 + 2.80434227e14
    = 7.59238413e14 joules
    = 181.462335803059261 kilotons

    (High end)
    E = 23.4444444 X 1.005 X 46184820000
    = 1.08819133e12 kilojoules
    = 1.08819133e15 joules

    E = 46184820000 X 13800
    = 6.37350516e14 joules

    E = 1.08819133e15 + 6.37350516e14
    = 1.72554185e15 joules
    = 412.4144000956022751 kilotons

    Final Results
    Shadow thinks of snow (low end) = 181.462 kilotons
    Shadow thinks of snow (high end) = 412.414 kilotons




  9. The detonation of the Klaxosaur Bomb causes an explosion seen all the way back on Earth. Strelizia True Apus is noted to be so far from Earth that there are no recognisable stars, and the sky and perspective is completely different (there are also noticably more stars in the sky than in space in the Solar System).
    Spoiler:


    The light is clearly visible in the middle of the day and from across the Universe, which would mean if'd have to be at least comparable to the luminousity of the Sun, with the apparent magnitude of the Sun being -26.74. The furthest star visible to the naked eye is Casopiea, 16,308 lightyears away (or 1.54282297e20m).
    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(1.54282297e20))^2)
    (146000000000/(1.54282297e20))^2) = 8.9551635e-19
    -26.74 - -26.73 = 8.9551635e-19/((L/3.846*10^26)
    -0.01 = -2.5Log(8.9551635e-19/((L/3.846*10^26))
    -0.01/-2.5 = (8.9551635e-19/((L/3.846*10^26))
    10^(0.004) = (8.9551635e-19/((L/3.846*10^26))
    1.00925289 = (8.9551635e-19/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 9.46317256e-10
    3.89975317e27/8.9551635e-19 = 4.12097861e36 joules

    The light lasts three days.

    T = 60 X 60 X 24 X 3
    = 259200s

    The light lasts 3 days.

    E = 4.35475374e45 X 259200
    = 1.12875217e51/10^44
    = 11.2875217 MEGAFOE

    Final Results
    Klaxosaur Bomb = 11.288 MEGAFOE
  10. (Episode 23)

    Strelizia True Apus spams a ton of beams real fast. More or less straight forward. Previously I calced Strelizia Apus' arm protectors to be 85840.8839m long.

    144 pixels = 85840.8839m
    1 pixel = 85840.8839m/144 = 596.117249m
    596.117249m X 1732 = 1032475.08m
    Spoiler:



    Timeframe is 1 frame.

    T = 1s/24
    = 41.6666667ms
    = 1032475.08m/41.6666667ms
    = 24779401.9/340.29
    = Mach 72818.4839

    Final Results
    Strelizia True Apus' beam spam = Mach 72818.484

  11. 2:07
    Spoiler:



    Homer Simpson accidentally causes a test simulation to melt into the ground, which he quite literally shakes off a few seconds later. Also of note...
    https://www.simpsonsarchive.com/episodes/1F02.html
    There wasn't anything nuclear at all in the truck, so it's possible that Homer himself caused this, somehow. Homer Simpson is 5'11" feet tall, or 180.34cm.

    1586 pixels = 180.34cm
    1 pixel = 180.34cm/1586 = 0.11370744cm
    0.11370744cm X 492 = 55.9440605cm

    230 pixels = 55.9440605cm
    1 pixel = 55.9440605cm/230 = 0.243235046cm
    0.243235046cm X 184 = 44.7552485cm

    63 pixels = 44.7552485cm
    1 pixel = 44.7552485cm/63 = 0.71040077cm
    0.71040077cm X 464 = 329.625957cm
    0.71040077cm X 1317 = 935.597814cm

    1077 pixels = 935.597814cm
    1 pixel = 935.597814cm/1077 = 0.868707348cm
    0.868707348cm X 258 = 224.126496m
    0.868707348cm X 335 = 291.016962cm

    And on top of that, given we can no longer see the inspection van, we can add its height too as it would have sunk below that.

    H = 329.625957 + 224.126496m
    = 553.752453cm

    Volume of the area as a rectangular prism.

    V = lhw
    = 935.597814 X 291.016962 X 553.752453
    = 150772857cm^3

    Energy to melt rock is 4350 joules per cm^3.

    E = 150772857 X 4350
    = 655861927950 joules
    = 156.754762894359 tons of TNT

    Final Results
    Homer fails inspection = 156.755 tons of TNT
  12. (Episode 21)

    Chlorophytum blasts open the way, melting a heap of rubble in the way. However, this leaves her depowered and even turns Ikuno's hair white, so this should be the absolute maximum output of Chlorophytum and most other non-Strelizia mechs (outside the Nine Models and the Space Franxx). Previously I calced Strelizia to be 54.969m tall.

    550 pixels = 54.969m
    1 pixel = 54.969m/550 = 0.0999436364m
    0.0999436364m X 50 = 4.99718182m

    Scaling from Strelizia to Delpinium to the corridor.

    364 pixels = 4.99718182m
    1 pixel = 4.99718182m/364 = 0.0137285215m
    0.0137285215m X 564 = 7.74288613m

    173 pixels = 7.74288613m
    1 pixel = 7.74288613m/173 = 0.0447565672m
    0.0447565672m X 2662 = 119.141982m

    Now to scaling the dimensions of the attack.

    1199 pixels = 119.141982m
    1 pixel = 119.141982m/1199 = 0.0993677915m
    0.0993677915m X 941 = 93.5050918m
    93.5050918m/2 = 46.7525459m

    = 2*atan(941/(1612/tan(70/2)))
    = 0.539683688 rad
    = 30.9215975945318178 degrees

    Enter that through the angscaler and the closer end of the melted rubble is 169.03m away.

    = 2*atan(430/(1612/tan(70/2)))
    = 0.251446322 rad
    = 14.4068130247232382 degrees

    The hole at the further end of the tunnel is 369.91m away. Now we can get the total length of the melted metal.

    L = 369.91m - 169.03m
    = 200.88m

    Volume of the tunnel as a cylinder (obviously).

    V = πr^2h
    = π X 46.7525459^2 X 200.88
    = 1379421.86m^3
    = 1379421860000cm^3

    Energy to melt steel is 7309.87 joules/cm^3.

    E = 1379421860000 X 7309.87
    = 1.00833945e16 joules
    = 2.4099891252390057694 megatons

    Final Results
    Chlorophytum blasts opens a path = 2.41 megatons
  13. (Episode 24)

    Stelitzia rams Hringhorni through the VIRM fleets and into the VIRM home planet at incredible speeds. Thankfully, we already have the dimensions for Strelizia Apus sorted, but now we need Hringhorni's dimensions. This should be much easier than Strelizia Apus's dimensions. Strelizia Apus' arm protectors are 85840.8839m long, and those on Strelizia True Apus should be a similar length.

    505 pixels = 85840.8839m
    1 pixel = 85840.8839m/505 = 169.981948m
    169.981948m X 2166 = 368180.899m
    169.981948m X 123 = 20907.7796m

    36 pixels = 20907.7796m
    1 pixel = 20907.7796m/36 = 580.771656m
    580.771656m X 1096 = 636525.735m
    580.771656m X 276 = 160292.977m

    It's not a perfect triangle, but given there's also other pyramidal parts sticking out, I figures it'd even out.

    503 pixels = 160292.977m
    1 pixel = 160292.977m/503 = 318.673911m
    318.673911m X 92 = 29317.9998m

    With all that done, let's get our volume by adding all three triangular parts together as triangular pyramids. To get that though, we need the area of the triangle first.

    A = hbb/2
    = 636525.735 X 160292.977/2
    = 5.10153025e10m^2

    V = 1/3AH
    = 1/3 X 5.10153025e10 X 29317.9998
    = 4.98555543e14 X 3
    = 1.49566663e15m^3

    Now for the shaft.

    812 pixels = 636525.735
    1 pixel = 636525.735/812 = 783.898688m
    783.898688m X 319 = 250063.681m
    783.898688m X 32 = 25084.758m
    25084.758m/2 = 12542.379m

    Volume as a cylinder.

    V = πr^2h
    = π X 12542.379^2 X 250063.681
    = 1.23583455e14m^3

    There are other bits too, but...eh. Let's get our total volume.

    V = 1.49566663e15 + 1.23583455e14
    = 1.61925008e15m^3

    Hringhorni is made out of Klaxosaur cores, which are composed of some form of weird goo, so we'll go with the mass of water, that being 1000kg/m^3.

    M = 1.61925008e15 X 1000
    = 1.61925008e18kg

    As previously caclulated, Strelizia Apus weighs 7.2176079e18kg, and Strelizia True Apus should weigh the same.

    M = 7.2176079e18 + 1.61925008e18
    = 8.83685798e18kg

    Now all that's left is the easy, fun part!

    43 pixels = 368180.899m
    1 pixel = 368180.899m/43 = 8562.34649m
    8562.34649m X 1349 = 11550605.4m
    Spoiler:


    Timeframe is 3 seconds.

    852 pixels = 11550605.4m
    1 pixel = 11550605.4m/852 = 13557.0486m
    13557.0486m X 695 = 9422148.78m

    T = 9422148.78m/3s
    = 3140716.26/340.29
    = Mach 9229.52852

    At these velocities, we can just start to apply relativistic kinetic energy, so we enter the above values into the relativistic kinetic energy calculator and get a result of 4.359E+31 joules, or 10.418260038240916288 zettatons.

    Final Results
    Strelizia True Apus rams the VIRM planet (speed) = Mach 9229.529
    Strelizia True Apus rams the VIRM planet (energy) = 10.418 zettatons
  14. Strelizia Apus is one absolutely colossal mecha, and given there are a few calcs I have in mind for it, I'll scale it's size and mass here. Machine scaling is never easy, and in the case of Strelizia Apus & True Apus this is very much so.
    Spoiler:
    Strelizia Apus was formed from Star Entity, which we can scale from Plantation 13. Plantations have a height of 1200m.

    Star Entity's crushes Plantation 13 between its index and middle finger.

    181 pixels = 1200m
    1 pixel = 1200m/181 = 6.62983425m
    6.62983425m X 358 = 2373.48066m

    That's the easy part done, now to scale the dimensions of Strelizia Apus, starting with all the pointy armour...

    6 pixels = 2373.48066m
    1 pixel = 2373.48066m/6 = 395.58011m
    395.58011m X 74 = 29272.9281m
    395.58011m X 126 = 49843.0939m
    395.58011m X 135 = 53403.3148m
    395.58011m X 91 = 35997.79m
    35997.79m/2 = 17998.895m
    395.58011m X 147 = 58150.2762m
    395.58011m X 70 =
    58150.2762m + 27690.6077m = 85840.8839m

    395.58011m X 9 = 3560.22099m
    395.58011m X 154 = 60919.3369m
    395.58011m X 119 = 47074.0331m
    395.58011m X 371 = 146760.221m
    395.58011m X 207 = 81885.0828m
    81885.0828m/2 = 40942.5414m
    395.58011m X 667 = 263851.933m
    395.58011m X 102 = 40349.1712m
    395.58011m X 117 = 46282.8729m
    46282.8729m/2 = 23141.4365m

    395.58011m X 201 = 79511.6021m
    395.58011m X 74 = 29272.9281m
    29272.9281m/2 = 14636.4641m
    395.58011m X 130 = 51425.4143m
    51425.4143m/2 = 25712.7071m
    395.58011m X 198 = 78324.8618m
    395.58011m X 169 = 66853.0386m
    66853.0386m/2 = 33426.5193m
    395.58011m X 352 = 139244.199m

    Shall we begin? Volume of her knee protectors and leg protectors as triangles added together.

    A = hbb/2
    = 29272.9281 X 49843.0939/2
    = 729526652m^2

    Then we times that by the depth to get the volume, and times it by two for both knees.

    V = 729526652 X 3560.22099
    = 2.5972761e12 X 2
    = 5.1945522e12m^3

    A = hbb/2
    = 29272.9281m^2

    V = 29272.9281 X 53403.3148/2
    = 781635697 X 3560.22099
    = 2.78279581e12 X 2
    = 5.56559162e12m^3

    Next, for the interior parts, as two pyramids, with the above volumes subtracted.

    V = 1/3AH
    = 1/3 X 729526652 X 29272.9281
    = 7.11846041e12 X 2
    = 1.42369208e13 - 5.1945522e12
    = 9.0423686e12m^3

    V = 1/3AH
    = 1/3 X 781635697 X 29272.9281
    = 7.62692185e12 X 2
    = 1.52538437e13 - 5.56559162e12
    = 9.68825208e12m^3

    V = 9.0423686e12 + 9.68825208e12
    = 1.87306207e13m^3

    In order to get the surface area of a cone I entered the values (17998.895m in radius and 58150.2762m high) into a calculator and got 4460000000m^2.

    V = 4460000000 X 3560.22099
    = 1.58785856e13 X 2
    = 3.17571712e13m^3

    Interior part as a cone (with the above subtracted, and again times by two for both of them).

    V = πr^2h/3
    = π X 17998.895^2 X 58150.2762/3
    = 1.97275016e13 X 2
    = 3.94550032e13 - 3.17571712e13
    = 7.697832e12m^3

    Volume of her leg protectors as triangles. Note of the upper two triangles she has two on each leg, which gives us a total of four.

    A = hbb/2
    = 60919.3369 X 47074.0331/2
    = 1.43385944e9 X 4
    = 5735437760m^2

    V = 5735437760 X 3560.22099
    = 2.04194259e13m^3

    Now for the lower leg triangles.

    A = hbb/2
    = 146760.221 X 60919.3369
    = 8.94053535e9 X 4
    = 35762141400m^2

    V = 35762141400 X 3560.22099
    = 1.27321126e14m^3

    The interior parts as triangular pyramids.

    V = 1/3AH
    = 1/3 X 8.94053535e9 X 60919.3369
    = 1.81550495e14 X 2
    = 3.6310099e14 - 1.27321126e14
    = 2.35779864e14m^3

    For the huge thing on the back we'll use a cone for the back end, which for the surface area we'll once again enter the values (a radius of 40942.5414m and 263851.933m long) through a calcuator, which reveals a surface area of 39600000000m^2.

    V = 39600000000 X 3560.22099
    = 1.40984751e14m^3

    For the interior parts, we'll use a cone (subtracting the above, of course).

    V = πr^2h/3
    = π X 40942.5414^2 X 263851.933/3
    = 4.63167942e14 - 1.40984751e14
    = 3.22183191e14m^3

    For the front end, we'll use a frustrated conical frustrum. Using this calculator here, we can determine it has a total surface area of 15827400000m^2.

    V = 15827400000 X 3560.22099
    = 5.63490417e13m^3

    Next, of course, its interior dimensions.

    V = (1/3)π(r^2+rR+R^2)h
    = (1/3) X π X (23141.4365^2 + 23141.4365 X 40942.5414 + 40942.5414^2) X 40349.1712
    = 1.33491102e14 - 5.63490417e13
    = 7.71420603e13m^3

    Now for the volume of the back legs as two cylinders and a cone. First segment...

    A = 2πrh + 2πr^2
    = 2 X π X 14636.4641 X 79511.6021 + 2 X π X 14636.4641^2
    = 8.65819662e9m^2

    V = 8.65819662e9 X 3560.22099
    = 3.08250933e13m^3

    V = πr^2h
    = π X 14636.4641^2 X 79511.6021
    = 5.35121895e13 - 3.08250933e13
    = 2.26870962e13m^3

    Second segment...

    A = 2πrh + 2πr^2
    = 2 X π X 25712.7071 X 78324.8618 + 2 X π X 25712.7071^2
    = 1.68080707e10m^2

    V = 1.68080707e10 X 3560.22099
    = 5.98404461e13m^3

    V = πr^2h
    = π X 25712.7071^2 X 78324.8618
    = 1.62684102e14m^3

    V = 1.62684102e14 - 5.98404461e13
    = 1.02843656e14m^3

    Third segment, as a cone. Once again using the calculator (for a radius of 33426.5193m and a length of 139244.199m) we get a surface of area 18500000000m^2.

    V = 18500000000 X 3560.22099
    = 6.58640883e13m^3

    V = πr^2h/3
    = π X 33426.5193^2 X 139244.199/3
    = 1.62925117e14m^3

    V = 1.62925117e14 - 6.58640883e13
    = 9.70610287e13m^3

    Now to add the exterior and interior parts together.

    V = 3.08250933e13 + 5.98404461e13 + 6.58640883e13
    = 1.56529628e14m^3

    V = 2.26870962e13 + 1.02843656e14 + 9.70610287e13
    = 2.22591781e14 X 2
    = 4.45183562e14m^3

    Last but not least, we need the values of the humanoid part of Stelitzia Apus.

    315 + 195 + 329 = 839
    395.58011m X 839 = 331891.712m = 331.891712km

    To find the surface area of her body, we'll scale up from a female body using square-law. Zero-Two is 170cm (or 1.7m) and the average mass of a 16 year old girl is 53.5kg.

    M2 = (H2/H1)^3*M1
    = (331891.712/1.7)^3*53.5
    = 3.98103724e17kg

    Entering the heigh and mass into this calculator, we get a variable number of surface areas, so let's get an average (ignoring the Biyd and Schlich formula's, as both are outliers on both end of the scale).

    A = 16217846544.78 + 17874819076.91 + 18581529949.17 + 18728961353.28 + 22526536559.03 + 27694900835.94
    = 1.21624594e11/8
    = 15203074250m^2

    V = 15203074250 X 3560.22099
    = 5.41263041e13m^3

    For our volume for the interior, we'll be using this forumla...
    The average density of the human body (from the above link) is 1010 kg/m^3.

    V = 3.98103724e17/1010
    = 3.94162103e14m^3

    V = 1.43796025e15 - 5.41263041e13
    = 1.38383395e15m^3

    At last, we can add everything together for our mass. First for the exterior...

    V = 5.1945522e12 + 5.56559162e12 + 3.17571712e13 + 2.04194259e13 + 1.27321126e14 + 1.40984751e14 + 5.63490417e13 + 4.45183562e14 + 5.41263041e13
    = 886901525720000m^3

    ...then for the interior.

    V = 1.87306207e13 + 7.697832e12 + 2.35779864e14 + 3.22183191e14 + 7.71420603e13 + 4.45183562e14 + 1.38383395e15
    = 2490551080000000m^3

    For our exterior armour, we'll steel, which weighs 7850kg/m^3 (usually I go with titanium, but given the interior part below seems a lot lighter than it should I think steel is a good choice).

    M = 886901525720000 X 7850
    = 6.96217698e18kg

    Now for the mechanical unseen interior, which is somewhat harder. The light ship mass of container vessel 2700TEU is 102.56kg/m^3 (or 0.10256g/cm^3). I've a feeling this is a colossal low end, but it's the best I've got for now, so I'll take it.

    M = 2490551080000000 X 102.56
    = 2.55430919e17kg

    Finally, to add both together for our final mass.

    M = 6.96217698e18 + 2.55430919e17
    = 7.2176079e18kg
    = 7217607900000000 tons


    Final Results
    Strelizia Apus' size = 331.891712km
    Strelizia Apus' mass = 7217607900000000 tons

    I'm not sure if the scaling is entirely accurate, but given there'd be a lot more unseen machinery (such as under the back part where we can see some engines) it would be even greater in mass, though that's the best I can do with what I've got. Strelizia True Apus would be equal in size and mass.
  15. (Episode 22)


    Spoiler:





    Zero-Two's mind's connected to Strelitzia Apus, which is in Mars orbit, and cuts on her appear whenever she's attacked by VIRM ships. Lot's of scaling, so let's get to calcing!
    Spoiler:
    The distance from Earth to Mars at their closest is 54600000km, or 54600000000m. Mars at it's furtherst is 401000000km away, or 401000000000m. The average distance to Mars from Earth is 225000000km, or 225000000000m, so we'll use those as our low end, mid end and high end.
    https://www.space.com/24701-how-long-does-it-take-to-get-to-mars.html
    Given the light is bright enough to visibly light up the Earth even through dark clouds during the day, then the apparent magnitude should be comparable to that of the Sun, that being −26.74 (though really it's likely even higher given it shone through the clouds easier than the sunlight did).
    (Low end)
    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(54600000000))^2)

    Breaking this down bit by bit...

    (146000000000/(54600000000))^2) = 7.15023682
    -26.74 - -26.73 = 7.15023682/((L/3.846*10^26)
    -0.01 = -2.5Log(7.15023682/((L/3.846*10^26))
    -0.01/-2.5 = (7.15023682/((L/3.846*10^26))
    10^(0.004) = (7.15023682/((L/3.846*10^26))
    1.00925289 = (7.15023682/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 7.15023682
    3.89975317e27/7.15023682 = 5.45401959e26 joules

    We'll hold onto that for now, let's do our mid and high ends.

    (Mid end)

    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(225000000000))^2)

    (146000000000/(225000000000))^2) = 0.42105679
    -26.74 - -26.73 = 0.42105679/((L/3.846*10^26)
    -0.01 = -2.5Log(0.42105679/((L/3.846*10^26))
    -0.01/-2.5 = (0.42105679/((L/3.846*10^26))
    10^(0.004) = (0.42105679/((L/3.846*10^26))
    1.00925289 = (0.42105679/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 0.42105679
    3.89975317e27/0.42105679 = 9.26182231e27 joules

    (High end)

    -26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(401000000000))^2)

    (146000000000/(401000000000))^2) = 0.132561365
    -26.74 - -26.73 = 0.132561365/((L/3.846*10^26)
    -0.01 = -2.5Log(0.132561365/((L/3.846*10^26))
    -0.01/-2.5 = (0.132561365/((L/3.846*10^26))
    10^(0.004) = (0.132561365/((L/3.846*10^26))
    1.00925289 = (0.132561365/((L/3.846*10^26))
    1.00925289 X (3.864*10e26) = 0.132561365
    3.89975317e27/0.132561365 = 2.94184748e28 joules

    For our final step, we'll get the timeframe to determine how long the light shone for.
    Spoiler:



    3 seconds.

    (Low end)
    E = 5.45401959e26 X 3
    = 1.63620588e27 joules
    = 391.0625908221797431 petatons

    (Mid end)
    E = 9.26182231e27 X 3
    = 2.77854669e28 joules
    = 6.6408859703632888341 exotons

    (High end)
    E = 2.94184748e28 X 3
    = 8.82554244e28 joules
    = 21.093552676864244859 exotons

    And on another note, given that Hiro doesn't wait around for minutes for the flashes to appear in the sky and they appear instantly, the VIRM explosions/attacks would be FTL.
    Spoiler:


    4 seconds.

    (Low end)
    T = 54600000000m/4s
    = 13650000000/299792458
    = 45.531499 C

    (Mid end)
    T = 225000000000m/4s
    = 56250000000/299792458
    = 187.629804 C

    (High end)
    T = 4s
    = 401000000000/299792458
    = 1337.59202 C


    Final Results
    VIRM ships attack Strelitzia Apus (low end) = 391.063 petatons
    VIRM ships attack Strelitzia Apus (mid end) = 6.641 exotons
    VIRM ships attack Strelitzia Apus (high end) = 21.094 exotons
    VIRM explosions (low end) = 45.531 C
    VIRM explosions (mid end) = 187.63 C
    VIRM explosions (high end) = 1337.592 C
Loading...