Was re-watching the Sonic Rainboom, and noticed how it generated winds at Pinkie Pie's house. This is a tad different from the previous method, this one is more along the lines of kinetic energy.
Spoiler: Assumptions Made
Because the Rainboom is in the shape of a circle, I will assume the air pushed is in the shape of a cylindrical sector, with a length equal to my original calc of 965.6064 km.
The Rainboom began moving clouds at 00.19.55 seconds in this video and the sky is at it's brightest at 00.24.48 seconds which means 4.93 seconds.
The Storm at Pinkie Pie's house is 20 km in radius, same as the horizon on a clear day. Watching the video again shows that the sky was near-completely cleared by Rainboom, yet the Storm returns the next day, covering the horizon, presumably the same size as it's predecessor. I've also asked a few knowledgeable people on the subject, and they say the the entire sky covered with clouds to the horizon won't alter visibility unless there are things like mist or fog obscuring the horizon.
The height of the air affected is equal to the height of the clouds (I mean, there's no way it couldn't if it was affecting clouds, and the air at ground level). They look pretty thick, so I guess nimbostratus clouds?
All the air between Pinkie Pie's house, and the epicenter of the Rainboom was pushed (would not make sense for it to affect only the air at Pinkie Pie's house, while somehow not touching the air between the two points.
First things first: I have the height and radius of the cylinder right? Well since this is a cylindrical sector calculator, I need to find the angle of the cylinder in degrees. I don't know the angle, what I do know is google can convert radians to degrees. I've been asking around, and it turns out I can find the rads by dividing the length of the arc of the sector by the radius of the circle. if the radius of the storm is 20 km, and goes out behind Pinkie for that same length, then that gives me an Arc length of 40 kilometers.
40000 / 965606.4 = 0.04142474614 rads
Converted to degrees = 2.373463121228736
When inserting the information into the cylindrical sector calculator, I get a volume of 38624255991559.18 meters cubed
Air has an average density of 1.225 kg/m3 (I have been informed that being 2 kilometers high will not change the density very much).
38624255991559.18 * 1.225 = 4.7314714e+13 kilograms
As noted in the assumptions section, I am assuming that the Rainboom began at 00.19.55 seconds, as that is when it interacts with the clouds. 40000 meters in 4.93 seconds is 8113.59026 m/s.
0.5 * 4.7314714e+13 * 8113.59026^2 = 1.55737202e21 joules or 372.220846 Gigatons
But we aren't done yet. This was only a small portion of the Rainboom. Shiba once did a surface area calc for the Rainboom that went something like this: ((2*pi*R)/7000 I do have a method of my own where I divide the surface area of the sector by the surface area of the entire Rainboom as a cylinder, but I'm not sure how accurate that would be, so I'll give out 2 ends for this based on both methods.
Spoiler: High End
((2*pi*965606.4)/7000 = 866.726277857
866.726277857 * 372.220846 GT = 322613.588394 Gigatons
Spoiler: Low End
The cylindrical sector calculator gives me a surface area of 42566681591.542 square meters
Surface Area of a cylinder is 2*pi*r*h+2*pi*r^2 2*π*965606.4*2000+2*π*965606.4^2 = 5.8705493e+12 square meters
5.8705493e+12 / 42566681591.542 = 137.914187353
372.220846 * 137.914187353 = 51334.5354919 Gigatons
I've brought up this calculation a few times, but I don't think it ever got much discussion over here. Maybe it'll get more attention if I bring it over here. Long story short, this calculates a scene where Celestia moves the Sun, or rather copy-pastes the calculation of a friend to Narutoforums. You can check out the OG Calc here if you want. All credits go to Darkanine.
The feat happens in "Lesson Zero".
Celestia basically moves the Sun.
The diameter of the Sun is 140 pixels (According to Dark, he messed up the scaling, which is why the picture says 142 instead of 140) It starts moving at 3.135
From 3.135 to 4.874 the Sun moved 50 pixels
4.874 - 3.135 = 1.739s
The Sun has a diameter of 1391400037.21 meters
140 / 50 = 2.8
1391400037.21 / 2.8 = 496928584.718 meters
496928584.718 m / 1.739s = 285755368 m/s
Relativistic Energy seems like a good idea
The Suns mass is 1.989e30 kg, gonna plug that in with the speed
4.089E+47 joules or 4.089 KiloFoe
I'm going to calculate the blast size of the Sonic Rainboom. I talked with a few trusty-worthy people on calculations, asking if it would be appropriate to use the size of an explosion's blast ring as it's air blast radius and they were cool with it, so here I am now. The blastwave of said explosion was big enough that it travelled all the way to the Rock Farm.
The episode: "Over a Barrel" shows the Mane 6 riding a train to Appleloosa. They began riding at an unknown time, but I do know for certain it was at least in the afternoon when the scene started. Later on we see it cut to nighttime, then morning where they are attacked by the buffalo. Afterwords, they finally arrive in Appleloosa at 2:00 PM according to the clocktower, with it's hands between the 1 and 3 pm mark. When we first see the train it appears to be in the afternoon, and they've definitely been riding for some time before we first see it since they're in the desert. So here's the timeframe: The sky when the train first appears in the episode is the same color as it is when they arrive at 2:00 PM the next day. So I'll assume it's roughly 2:00 PM when we see the train at the start of the episode. This is a 24 hour time-frame.
For those wondering about the relevance of Appleloosa, that's because of the official Map of Equestria, which depicts the Rock Farm as slightly farther than Appleloosa. This means that however far Appleloosa is, I can apply it to the Rock Farm which the blast wave of The Sonic Rainboom passed over.
Took me a lot of work, but I finally found a post saying that early steam trains would typically travel at speeds of 25 mph. This translates to 40.2336 km/h. Suitable considering that's the average gallop for equines, and considering they are pulling the thing with no signs of being slowed by it.
40.2336 x 24 = 965.6064 km
Plugging this into StarDestroyer.net to get a value of 52.5 Teratons. Dividing by 2 because the explosion is non-nuclear, and we end up with 26.25 Teratons. Holy hell! Country level high tiers. What a world.
Two big famous monsters in My Little Pony that no one has calced yet (at least as far as I can tell). This is gonna be fun. Here's how this is gonna work: I'm going to find the length of the Ursa Minor's head, and it's snout. I will compare the length of it's snout to that of a Kodiak bear, and then use the square cube law to cube the size difference, and multiply by a Kodiak's average weight. I'll do the same to find the weight of the Ursa Major.
Height on hind legs = 753px = 3m
Nose width = 18px = 0.0717131474 meters
Weight = 450 kg
First, to find the size of the Minor, I need something to compare it to, like a pony. Luckily I can do exactly that.
First off: The height of ponies. https://derpicdn.net/img/2014/1/31/539446/large.png This is a size chart with Cheese Sandwich and other ponies in front of it. The taller ponies are around 4 ft tall (they seem to use the imperial system) from the very base of their ears. I'm going to use the smaller pony as the height of a mare. Now while it's true the smaller pony is probably a stallion, but the tips of this small stallions ears reach the base of the ears of a normal stallion next to him. Whenever we see a mare and stallion side by side, the mare's ear tips also reach the base of the stallions ears, so I think this is a safe assumption.
I started from where the ear meets the head and went from there. The smaller pony was difficult since their head was obscured by their mane but I found a rough estimate.
251 / 241 = 1.04149378
Left-hand pony is 4 ft
4 / 1.04149378 = 3.84063745021 ft or 1.170626294824008 meters
Twilight stands at 70 pixels, but I need to take into account that she is standing at an angle. Accounting for the angle, the height becomes 80. The snout is 48 pixels, and the head is 242 pixels.
242 / 80 = 3.025
1.170626294824008 * 3.025 = 3.541 meters for the Minor's head height (this will be important for the Ursa Major scaling)
80 / 48 = 1.66666667
1.170626294824008 / 1.66666667 = 0.702375775 meters
0.702375775 / 0.0717131474 = 9.79423998
Applying square cube law: 9.79423998^3 * 450 = 422790.029 Kilograms or Class K
Scales to Twilight for lifting the thing. I could establish the newtons needed to lift it against gravity, but I'm a lazy boi.
Now for the Major calc (shutting up now). We've established a head height of 3.541 meters for the Ursa Minor, now we'll find out how big the snout of it's mother is in comparison. Ursa Major's nose is 45 pixels and the Ursa Minor's head is 34 pixels.
45 / 34 = 1.32352941
1.32352941 * 3.541 = 4.686 meters
Dividing this by the Kodiak's snout. 4.686 / 0.0717131474 = 65.34
Applying square cube law: 65.34^3 = 278957
450 * 278957 = 125530650 kg or Class M
Talk about massive. How the hell is something so heavy even alive? Scales to Rockhoof for tossing the thing and anyone remotely comparable to him (Lol, Rarity lifted more weight in clouds than this fraud). I could again, get something based on how high he tossed it, but I'm too lazy (plus I don't know any good time-frames or speeds).
Feat happens at 2:19 and ends at 2:21 in which Rarity makes a massive storm all over Ponyville, well half of one that is. To find the size of the storm I'm going to try and find a size for Ponyville, and use that for my radius since the clouds go far behind Rarity as well. v
Size of Ponyville
Right, so the original method had been discarded as it was lowballing Rainbow's true speed. So I have to re-do the calc. Instead I'll be taking a timeframe based on Fluttershy, Twilight, and Spike walking from an unspecified location in Ponyville to Twilight's Library. It was afternoon when they began walking, and into Sundown by the time they got there. I've been told that 3 to 6 hours is a good assumption, so I'll be using these timeframes and a horses walking speed, which averages at 6.4 km/h according to this site.
Volume, Mass and Energy
3 * 6.4 = 19.2 km. Times that by 2 and you get 38.4 km for 6 hours. Since the clouds extended far behind Rarity, these will be used for my radius. The storm spread from Rarity to it's maximum in 2 seconds, so I'll cut the radius in half for my speed.
Like previously the area is 19200^2 * Pi = 1.15811672e9 m2 Multiplying by 0.5 due to the checkerboard pattern, granting an area of 579058360 m2
579058360 * 8000 = 4.63246688e12 m3. Multiplying by 1.003 to get 4.64636428e12 kg
0.5 * 4.64636428e12 * 9600^2 = 51.172195506.7 Gigatons
0.5 * 38400^2 * Pi = 2316233430 m2 * 8000 = 1.85298674e13 m3 * 1.003 = 1.8585457e13 kg
0.5 * 1.8585457e13 * 19200^2 = 818.755122 Gigatons