Now Jack flew from Lima, Peru to France in seconds. Jack's tracking signal vanished from Lima at 5:13 and reappeared on Paris at 5:14 (yes I counted the frame as well). So it took him

The distance between two points is 6371 miles.

Flying Speed = 6371/1 =

Speed of sound = 343 meter/sec

Jack Flying Speed = Mach 30130.57

Final Tally

Jack Flying Speed =

This year Tou conquered Han. This will be Shin's first campaign as Qin6. He will serve as the deputy of Tou.

Shin will serve as a deputy to OuSen and finally slay Houken in this war.

This year Shin will fight against Wei. His opponent will be GaiMou.

This will be Shin's first campaign in Chu. Here he will face a pure instinctual GG like Duke Hyou. It will be someone we haven't seen yet. Someone who has an instinct level either 100 or close. This campaign will test Shin's capability as an instinctual Great General.

This is his legendary historical war. Here he will lose. I don't want to discuss this further.

What we know from manga so far,Shi Ba Shou is the lord of Seika City. He does not wish to engage in battle, except for his city, Seika which is close to Yan's border.

In 229BC, Qin attacked Zhao. Great General RiBoku and and General ShiBaShou were tasked to defend against the attack. Qin bribed a minister who was liked by the King of Zhao, with gold to spread news of RiBoku and ShiBaShou plans to rebel. The king of Zhao sent Zhao Cong and Qi general Yan Ju to replace RiBoku. RiBoku refused but was captured by Zhao men and later executed while ShiBaShou was stripped off his duties. (General) Zhao Cong and the Qi general, Yan Ju, was tasked to replace them. Zhao Cong was defeated and Yan Ju fled.

ShiBaShou will be the Great General of Dai. By that time I doubt there will be any renowned Great General in China. Shin will be the one to take him out while OuHon deals with the remnants of Yan. This will also be the first war since he will lose his lieutenants in Chu & his first solo campaign against a Zhao 3 Great Heavens. This win will make up for his loss in Chu.

So here, both Shin and OuHon was involved in this campaign. So far we know about 3 Qi Generals. They are GanMo, KanShu and DenKaku. Among them GanMo was supposed to be the Commander-in-chief of Qi Army in the Coalition Army.

OuHon, Shin and KyouKai each takes out a General.

Why two Chu invasion? First, I want to see Shin face off against a true instinctual type. And Chu is a land of mystery so why not an instinctual general from there?

Second, as Chu is a superstate I want Shin to have some success against them before his colossal failure later.]]>

https://[Blocked Domain]/Manga/One-Piece/One-Piece---874?id=376731

All right, had some free time on my hand. And this was already scaled and ready so I thought why not post the most impressive feat of this pathetic excuse of an emperor.

First, we need the island size. I already scaled it before. I took the mid end.

Whole Cake Island Diameter [Mid End] =

Now we need the size of one of WCI's blocks that's beside the huge towers.

Whole Cake Castle diameter = 491 pixel

Block's Height = 103 pixel =

Now Meme slash entered from one part and exited from other. For the lack of better method I will use the width as the length that the slash crossed.

Block's Height = 260 pixel = 1506.92847 meter

Block's Width = 117 pixel =

Lets now scale the hole it made and how much water it raised,

Block's Height = 45 pixel = 1506.92847 meter

Hole diameter = 8 pixel =

Water width = (100+36+69)/3 or 68.3333 pixel =

Water Height = (44+61+54+44+26)/5 or 45.8 pixel=

Assuming the block was 80% solid and cylinder shaped,

Hole's Volume = pi*r^2*h = pi*(267.8983/2)^2*678.11781 =

It looks like Meme's attack pulverized it. But it's also true that everything in WCI is made from food ingredient. I am going to play it safe and use

Rock Destruction,

Volume of Water = pi*r^2*h = pi*(2288.28762/2)^2*1533.71831

Volume of Water =

Density of sea water is

Water Weight =

PE of Water = mgh = 6458871768596.08110*9.8*(1533.71831/2)

PE of Water,

Total DC =

Total DC =

So that was impressive.

Final Tally

Big Mom's Elbaf Spear =

- Shin

- Kyou kai

Since we don't know if Kyokai has other 2k, 1k, 300 man commander in her unit or not this isn't a proper breakdown of the unit.

- Shin

- Kyou kai

- Kakubi
- En

- Suugen

- Ryuu Sen
- Chu Tetsu

- Naki
- Gakurai
- DenYuu

- Hai Rou
- Den Ei
- Kyo Gai
- Ryuu Yuu

Can't account for rest 800 soldiers. But there are many units aside from these. So they can be used to fill those numbers.]]>

Feat -- 05:10

To dig 2 miles in underground Lexcorp used laser to destroy boulders along the way.

Human = 301.8447 pixel = 1.7 meter

Hole diameter = 743 pixel = 4.184 meter

Hole Thickness = 143 pixel = 0.8053 meter

Modeling it as cylinder.

Hole Volume, pi*r^2*h =

Fragmentation value

Laser DC = 88611368.07582 Joules =

To beat Doomsday Superman holds him & goes straight to space. Then body slams him in the ground. It took him 300 frames to reach that level. The video is 23.96 FPS.

Timeframe =

Since except for space we don’t know how far he went I will use 2 different ways to calc the distance he traveled.

First [Low End] for space we will use Kramline line which is 100 km above see surface.

Superman’s Speed = (100*1000/12.5808) = 7986.6666 meter/second

Superman’s Speed

For the next distance calc I am going to use angsizing. First I am going to calc the distance to earth from our pov & then to superman. Subtracting the distance we will get how far Superman traveled.

Panel Height = 1080 pixel

Superman = 36.6196 pixel = 1.8796 meter

Height H = 175.5733 pixel

Width W = 1967.40488 pixel

So, R = (H/2)+(W^2/8H) = 2843.53097 pixel = 6371 km

So, W = 1967.40488 pixel = 4408.01828 km

First distance from our POV to Superman,

object degree size = 2.720117530808

Using angular calculator I get Distance =

Again for distance from our POV to Earth,

object degree size = 2*atan(1967.40488 /(1080/tan(70/2)))

object degree size = 103.8087520

Using angular calculator I get Distance =

This is actually a low estimate cause Superman goes farther than that. But because of lack of earth shot from his final distance I am using this one.

Distance from Superman to Earth = 1727.8604 km

Superman’s Speed

Superman’s Speed

Now, let’s calc the DC of Superman’s Body Slam. First we need the height of Doomsday.

Superman = 500.8732 pixel = 1.8796 meter

Doomsday = 644.4261 pixel = 2.4183 meter

Doomsday = 11.3137 pixel = 2.4183 meter

Crater Diameter = 1393 pixel = 297.7534 meter

Crater Depth = 397 pixel = 84.8586 meter

Modeling the crater as half ellipsoid,

Crater Volume, .5*(4/3)*pi*(d/2)^2*r =

Pulverization value

Superman’s Body slam = 842989899822042.67655 Joules

Superman’s Body slam =

Final Tally

Lexcorp Laser DC =

Superman's Speed =

Superman’s Body slam =

https://en.wikipedia.org/wiki/Midwestern_United_States

Total area pi*r^2 =

Radius r, =

Inputting the value in Nuclear Weapon Effects Calculator we get yield. Thanks to @Shiba Miyuki for the results.

Supergirl survived it point blank & was only knocked out for few minutes. There wasn't any visible injury.

Supernova Energy [Low End] =

Supernova Energy [Mid End] =

Supernova Energy [High End] =

This is pretty straight forward calc. Lufasu makes a big crater by punching Aries into the ground.

Lufasu = 19.2093 pixel = 1.7 m

Aries length = 508 pixel = 44.9572 m

Again,

Aries length = 57.1401 pixel = 44.9572 m

Crater diameter = 898 px = 706.5358 m

Crater depth = 397 px = 312.3549 m

Crater volume = .5*(4/3)*pi*abc

Crater volume = .5*(4/3)*pi*312.3549*(706.5358/2)^2 m^3

Crater volume =

Fragmentation value (8 j/cc) =

Violent Fragmentation (69 j/cc) =

Pulverization value (214.34 j/c) =

Lufasu punches,

Low end =

Mid end =

High End =

Big Meme apparently has the power to create a storm. When she learns that Luffy beat Cracker she went into a fit of rage & created a thunderstorm.

From the looks of it I think it's a Single-Cell thunderstorm. Single-cell thunderstorms typically last 20–30 minutes. But here it looks it lasted close to a day. Here we see the rain started at 2 pm. This is all after Luffy met with Sanji & fought the enraged army so probably 30 minutes earlier but lets just go with it as is. The marriage was next day. We learn from here that weeding was supposed to be at 10 am. The rain stopped at least 4 hours and 30 minutes before marriage started (including the time SH took to reach Bege's castle) so at 5:30 am at least.

So, our time frame is 2 pm to 5:30 am or 15 hours & 30 minutes.

First , we need the whole area the storm covered. From the scan below we can see from our POV the storm. Since it was created in Whole cake island lets assume it's ground Zero & distance from our POV to the island is the radius. I am going to calc the distance using angular formula.

Island Diameter = 548 pixel = 7183.5134 meter

Cloud Base height = 200 pixel = 2621.7202 meter

Cloud height = 143 pixel = meter

Panel Height = 505 pixel

object degree size = 2*atan(548/(505/tan(70/2)))

object degree size =

Now, putting object degree size & WC Island size in angular calculator we will find the distance.

http://www.1728.org/angsize.htm

Distance, r =

So area covered = pi*(4.7271e+3)^2 =

Now, since we don't have a time frame & her creation didn't look like she gathered clouds at all I am not going to calc it using KE instead I am going to try a different method.

We need rainfall rate. Light rain is typically 2- 4 mm/hr & moderate rain is typically 5-9 mm/hr. For the sake of low end lets use 3 mm/hr. (Link)

Now, we need the amount of water fell during the rain.

1 mm of rainfall equals 1 liter of water over an area of one square meter. (Link)

Total number of millimeters that fell = (3*15.5) or 46.5 mm

Rate in terms of liters/meter^2 = 46.5 liter/meter^2

Total Water Fell = (46.5*70200378.24743

So, now we need dew point temperatures cause that's the temperature water vapor has to cool down to form water droplets.

dewpoint = surface temperature - (4.4*cloud base/1000)

dewpoint = 20 - (4.4*2621.7202/1000)

dewpoint =

Now, we need the temperature to calc the energy to cool down water vapor.

Height from surface to mid point of cloud = 2621.7202+(1874.5299/2) =

So, temperature at 3558.9852 meter cools down (6/10000*3558.98521) or

I am going to calc the latent energy needed to condense this huge mass.

The latent heat of condensation = 2.5 * 10^6 Joules/kg

Latent Energy,

Latent Energy,

Total Energy = Q1+Q2 =

Big Meme's Storm =

All discussion related to this calc goes here.]]>

First I will scale one of the Germa ship. I will use @God Movement Thousand Sunny calc for it.

Thousand Sunny Width = 89.8943 pixel = 26.2 meter

Germa 66 ship width = 488.0368 pixel =

Now I will use this to scale the diameter of the lower level of Whole Cake Castle. All the Germa ships should be of same size. But I doubt Oda used scale here so I will scale four ships & use the average.

Germa 66 ship width = (78+74+76+74)/4 or 75.5 pixel = 142.2398 meter.

Whole Cake Castle lower level diameter = 652 pixel =

TBH the design & size of WCI is pretty inconsistent. But one thing we are sure of is that Germa 66 was situated just behind Whole Cake Castle. I am going to scale the lower level diameter to scale the whole island. Also I am going to use two different scan & use average.

Whole Cake Castle lower level diameter = 52 pixel = 1228.3497 meter

Whole Cake Castle top level diameter = 17 pixel =

Whole Cake Castle diameter = 387 pixel =

Again, with different scan,

Whole Cake Castle lower level diameter = 129 pixel = 1228.3497 meter

Whole Cake Castle top level diameter = 26 pixel =

Whole Cake Castle diameter = 491 pixel =

So, almost half from what we got from the first scan.

Let's try again then,

Whole Cake Castle lower level diameter = 79 pixel = 1228.3497 meter

Whole Cake Castle top level diameter = 33 pixel =

Whole Cake Castle diameter = 462 pixel =

Now, we are getting somewhere. Lets try again,

Whole Cake Castle lower level diameter = 54 pixel = 1228.3497 meter

Whole Cake Castle diameter = 432 pixel =

Now, some can object to the last scaling due to the castle falling down. But I think it falling down has any effect here since we are scaling via diameter. As such we can scale it with no problem.

Nonetheless , I think I will go with the mid end or the value of third scan for island diameter. For top level diameter lets use the average which is (513.1081+247.5743+401.5758)/3 or

If there is any mistake, kindly point it out & I will try to correct it.

Castle Top Level Diameter [Average] =

Whole Cake Island Diameter [Mid End] =

The calc is pretty simple. Nothing more than few scalling at best.

Earth diameter = 1777 pixel = 12,756 km

Explosion diameter = 1245 pixel = 8937.09622 km

Explosion radius = D/2 =

Since there is no visible destruction & the explosion was in space it's hard to gauge the DC of the blast. I am going to use nuke calculator for DC,

It's pretty hard to find accurate radius in the calculator so I am going to use the closest I can find ,

Fireball radius (minimum) = 4472.2 kilometres =

DC of Macrocosm Canon =

First I am going to scale the Dragon's eye length from one of the nearest galaxy to it. I see two. One around its teeth & one a bit above its eye. I will their average size.

Average Galaxy size = (12.7279 + 22.80350) / 2 = 17.7657 pixel = 110,000 light-years

Dragon Eye Length = 500.22494 pixel =

Now,I am going to use the eye to scale the whole body. Dragons whole body is curved so it may not be the most accurate scaling mind you. Nonetheless , I will try my best.

Dragon Eye Length = 26 pixel = 3097243.401763 light-years

Dragon Length = 1537.778600 =

The scaling looks like a cluster fuck. I know. Not my best work. Anyone is welcome to rescale to more accurately.

Super Shenron Size =

http://[Blocked Domain]/manga/k_the_first/c002/13.html

You can see the diameter is already given in the link. That saves me the trouble of scaling it. For depth since it happened in Kanto region I tried to find the average elevation but I failed. But in the wikipedia page of Kanto plain which is the largest plain in Japan located in Kanto region I found this,

Volume = pi*r^2*h

Volume = 3.1416*(50*1000)^2*100 =

Now,we don't know whether it was fragmented or pulverized. So I am going to use both value here.

Fragmentation 8 j/cc

Damocles Down =

Damocles Down =

Pulverization 214 j/cc

Damocles Down =

Damocles Down =

Now unlike in anime version we don't have stated crater size. And this is a problem cause anime version being canon & all now I have to scale the crater.

First I am going to use the map below to scale an island named Sado & use it later to scale the crater. Lets get to it then,

43 pixel = 200 km = 200000 meter

Sado = 13 pixel = 60465.11627 meter

Sado = 34.0587 pixel = 60465.11627 meter

Kagutsu Crater Diameter = 13 pixel = 23079.12025 meter

Much smaller than manga version. Anyway, we already figured out depth when we did manga version. So,

Volume = pi*r^2*h

Volume = 3.1416*(23079.12025)^2*100 =

Now,same as manga version we don't know whether it was fragmented or pulverized. So again I am going to use both value here.

Fragmentation 8 j/cc

Damocles Down =

Damocles Down =

Pulverization 214 j/cc

Damocles Down =

Damocles Down =

Damocles Down [Low End] =

Damocles Down [High End] =

Damocles Down [Low End] =

Damocles Down [High End] =

Now,I ain't going to calc the kinetic energy here rather the work done by Melissa to lift it up.

First we need the weight. According to General Lane it weighted one million tons.So I ain't going to bother calcing it anymore .

1 US tons = 907.185 kg

10,00,000 tons =

Now that we have that out of the way now we need distance. Melliasa said she would lift it up to space.

Distance = 100 km = 100*1000 =

Great. Now we need time. She started lifting it at 32:51 & released it at 33:38 so 48 seconds more or less.Now,

Acceleration a = 2s/t^2 = (2*1,00,000)/48^2

Acceleration a =

Now ,

F = 907184740*86.8055 =

Lets calc the work done by Supergirl,

W = 78748675347.2222*1,00,000 Joules

W =

W =

Not bad.

Supergirl lifts Fort Rozz =

In the middle of his fight against Rabo he noticed that debris were falling on top of Hiyori. So he rushed there before the debris fell on her.

First I am going to need the distance he covered. We can see the shrine like things in the image. Now they vary in size but the difference isn't too much. I have scaled one that is more common around the area & will apply it to the largest one for low end.

Yato = 192 pixel = 1.7 meter

Bridge width = 437.2928 pixel =

Again, Bridge width = 126 pixel = 3.8718 meter

Shrine Width = 178 pixel =

Now that we have got it lets scale the distance. First I need the length up to his knee. You will understand why soon.

Yato = 609 pixel = 1.7 meter

Knee height = 172 pixel =

From the image posted below first I am going to calc the distance to knee & then the shrine by angsizing. To get the real distance from Yato to Shrine I will subtract the distance to knee from the total distance to shrine.

Panel Height = 720 pixel

Knee height = 347.1397 pixel = 0.4801 meter

Shrine Width = 56 pixel = 5.469775 meter

Shrine Base = 38 pixel =

Why base? Cause we need the distance to ground.

Formula :

object degree size = 37.30905520535

Putting object degree size & knee length in angular size calculator I get distance =

Again ,

object degree size = 2*atan(38/(720/tan(70/2)))

object degree size = 4.2328504187

Putting object degree size & shrine base width in angular size calculator I get distance =

Distance crossed = 50.218-0.71105 =

Now that we have got our distance Yato needed to move lets calc the distance debris were supposed to fall before Yato reached there. First I am going to need the length of Hiyori's arm. I will use 1.5 meter for her height. She is 16 year old girl. So it seems reasonable.

Hiyori = 439 pixel = 1.5 meter

Arm length = 164 pixel =

Again, Hiyori's arm length = 213.40015 pixel = 0.560364 meter

Distance debris need to fell = 181 pixel =

Now we need to find free fall speed.

T = sqrt(2d/g)

g = 9.8 m/s^2

d = 0.4752 meters

Free Fall Time =

Yato's Speed =

I am not going to explain why Gods wanted to kill him just know they did. They formed a pcification ring and dropped heavenly bomb to kill him. Lets get to it,

Random God = 10 pixel = 1.7 meter

Pacification Ring = 1111 pixel =

Pacification Ring = 1019 pixel = 188.87 meter

Judgement Ball = 16 pixel =

Now I am going to use Judgement ball to scale the explosion. There shouldn't be any problem since the scene doesn't change at all.

Judgement Ball = 14 pixel = 2.9655 meter

Blast Diameter= 605 pixel =

The blast formed a crater but because of up down view we can't scale its depth. So I will be using 1/4D for depth.

Crater Depth =

Crater Volume = .5*(4/3*pi*r^2*d) unit^3

Crater Volume =

I am going to use two value to determine dc. One for low end & one for high.

Low End [67 j/cc] = 18459578808054.657779 joules

Low End [67 j/cc] =

High End [214 j/cc] =58960445745129.80245 joules

High End [214 j/cc] =

Yato cut the second judgement ball in half before it hit the ground. Take that as you will.

Yato's Speed =

Gods Judgement =

Anyway in the latest Supergirl episode Olson took Supergirl to Fortress of Solitude. As many of you know to enter there you need a key. The key was stated by Olson to weigh millions of tons.

I am going to take Olson's comment as face value. He hanged around with Superman so Clarke must have told him that at some point.

1 US tons = 907.185 kg

10,00,000 tons =

I am going to calculate Potential Energy to lift the key. For that I need height she lifted it up.

Going by the image posted she lifted it up at least to her shoulder height.

Melissa Benoist = 1593 pixel = 1.73 meter

Height to Shoulder = 1353 pixel =

Now,lets get to to work.

Here, Potential Energy = 1.4693596986817326*907184740*9.8 joules

Potential Energy =

Potential Energy =

Not that impressive when you put a number beside it,is it?

Melissa Benoist lifts the key =