16:40

A Darkside artifact moves the celestial bodies of Endor. Now, there are two ways in which we'll be doing this. Endor has a diameter of 4,900km, so the moons would be smaller than that. For the larger of the two bodies, we'll be using Earth's Moon Luna, which has a mass of 7.34767309e22kg and a diameter of 3474.8km. For the smaller of the two, we'll be using Saturns moon Dione, which has a diameter of 396km and a mass of 10^20kg.

Timeframe is 2.98 seconds.

212 pixels = 396km

1 pixel = 396km/212 = 1.86792453km

1.86792453km X 242 = 452.037736km

377 pixels = 3474.8km

1 pixel = 3474.8km/377 = 9.21697613km

9.21697613km X 330 = 3041.60212km

T = 452.037736km/2.98s

= 151690.515m/s

KE = (0.5)mv^2

= (0.5) X 1.0e20 X 151690.515^2

= 1.15050062e30 joules

T = 3041.60212km/2.98s

= 1020671.85m/s

KE = (0.5)mv^2

= (0.5) X 7.34767309e22 X 1020671.85^2

= 3.82729646e34 joules

Now, we add those up for our final yield.

E = 1.15050062e30 + 3.82729646e34

= 3.82741151e34 joules

= 9.1477330544933082024 yottatons

That's really impressive, but a thought's come to mind that might make this even more impressive. Endor doesn't have any moons because it is a moon, and would instead have a plant it orbits, and other moons that orbit around said planet, and it appears similar in size to the larger of the celestial bodies in the above video...

https://starwars.fandom.com/wiki/Endor_(planet)/Legends

The planet of Endor is a gas giant with a diameter of 148,000km (or 148,000,000m). Jupiter has a diameter of 142,984km (or 142,984,000m) and a mass of 1.9e27kg. Now we use square law to determine the planet Endor's second mass.

M2 = (H2/H1)^3*M1

= (148,000,000/142,984,000)^3*1.9e27

= 2.10705766e27kg

We don't know much about the other moons of Endor, other than the Sistermoon (of which we still know nothing really), so for the smaller celestial body we'll go with the dimensions of the Moon.

212 pixels = 3474.8km

1 pixel = 3474.8km/212 = 16.390566km

16.390566km X 242 = 3966.51697 kilokmters

T = 3966.51697km/2.98s

= 1331045.96m/s

KE = (0.5)mv^2

= (0.5) X 7.34767309e22 X 1331045.96^2

= 6.50887503e34 joules

377 pixels = 148,000km

1 pixel = 148,000km/377 = 392.572944km

392.572944km X 330 = 129549.072km

T = 129549.072km/2.98s

= 43472843m/s

That's more than fast enough to be reletavistic, so entering that through the relativistic kinetic energy calculator gets us a yield of 2.023E+42 joules! Adding that together with the above...

E = 6.50887503e34 + 2.023E+42

= 2.02300007e42 joules

= 483.5086293690252304 tenatons

I'm pretty sure that's higher than what the Death Star was calced at...

Darkside Ewok artefact moves celestial bodies (low end) = 9.148 yottatons

A bunch of novice Green Lanterns survive a supernova. In order to go supernova, a star needs to have at least 8 solar masses. Red Giants at their highest weigh 8 solar masses, and have a diameter of at least 100,000,000.

= 0.260327296 rad

= 14.9156553528899174 degrees

Enter this into the angscaler, and we have a distance from the Sun to the Green Lanterns as 381960000km (or 381960000000m) away. Looking at ChaosTheory123's Ood Bnar calc for reference. The average surface area of a man is 1.9m^2.

A = 4πr^2

= 4 Xπ X 381960000000^2

= 1.83335106e24m^2

A = 1.9/1.83335106e24

= 1.03635362e-24m^2

The energy of a supernova is 10^44 joules.

E = 10^44 X 1.03635362e-24

= 1.03635362e20 joules

= 24.769445984703629904 gigatons

Final Results

Green Lanterns survive a supernova = 24.769 gigatons

Not as impressive as the supernova itself, I'm afraid.]]>

Chevalier Renald performs a blatantly superhuman jump. The average height of a man is 5 feet 9 inches, or 1.7526m.

37 pixels = 1.7526m

1 pixel = 1.7526m/37 = 0.0473675676m

Timeframe is 0.09 seconds.

0.0473675676m X 172 = 8.14722163m

T = 8.14722163m/0.09s

= 90.5246848m/s

Chevalier Renald's jump = 90.525m/s

Not as much as I thought it would be, but still blatantly superhuman and pretty impressive.]]>

54:49

A dragon summons a storm on a mostly clear blue day. Keep in mind this is not a legendary super powerful dragon, or even a named dragon. This is just a generic

https://forums.elderscrollsonline.com/en/discussion/493609/pts-patch-notes-v5-2-0

V = πr^2h

= π X 4700^2 X 12000

= 8.32773381e11m^2

Density of a cumulus cloud is around 0.5 grams per m^3.

M = 8.32773381e11 X 0.5

= 416386690500g

= 416386690.5kg

Condensation of water vapour to liquid is 2260 joules per gram.

E = 416386690500 X 2260

= 9.41033921e14 joules

That's impressive, but we can also get the kinetic energy, as we can clearly see the clouds moving in from the horizon.

1.22 seconds.

T = 4700m/1.22s

= 3852.45902m/s

KE = (0.5)mv^2

= (0.5) X 416386690.5 X 3852.45902^2

= 3.08988915e15 joules

Now to add both together for our final results.

E = 9.41033921e14 + 3.08988915e15

= 4.03092307e15 joules

= 963.4137356596557993 kilotons

Generic Dragon Storm Call = 963.414 kilotons

Scales to Durnahviir, Odahviing and every dragon ever, as well as Dovahkiin, the Dragon Priests, Olaf One-Eye, Reman's Dragonguard and a ton of other characters.]]>

Horde Primes fleets bombs a planet and creates some considerable explosions with super fast lasers.

Timeframe is 1 second (though in actuality it would be even less, at it travels across the screen in only part of a second). First off, to find the radius of the planet, assuming it's Earth-sized (which has a radius of 6378.1km, or a diameter of 12,742km).

R = (h/2) + c^2/(8h)

= (292/2) + 1506^2/(8 X 292)

= 1116.90582

6378.1km = 1116.90582 pixels

1 pixel = 6378.1km/1116.90582 = 5.71050834km

5.71050834km X 2100 = 11992.0675km

T = 11992.0675km/1s

= 11992067.5/340.29

= Mach 35240.7285

And keep in mind that would be a low end, and I was unable to calculate or pause from fractions of a second.

5.71050834km X 474 = 2706.78095km

2706.78095km/2 = 1353.39047km

Enter that through the nuke calculator using the above radius of 1353.39047km and playing around and find that for the widespread destruction airburst we get a result of 7710100 megatons, or 7.710100 teratons. Going for a high end of fireball radius, we get 548490000 megatons, or 548.490000 teratons.

Similar to the first, but this time we have a much,

542 pixels = 12,742km

1 pixel = 12,742km/542 = 23.5092251km

23.5092251km X 90 = 2115.83026km

23.5092251km X 51 = 1198.97048km

2115.83026km - 1198.97048km = 916.85978km

23.5092251km X 710 = 16691.5498km

23.5092251km X 100 = 2350.92251km

2350.92251km/2 = 1175.46125km

23.5092251km X 2613 = 61429.6052km

23.5092251km X 2013 = 47324.0701km

23.5092251km X 1086 = 25531.0185km

23.5092251km X 726 = 17067.6974km

First off for the explosion. Once again messing around with the nuke calculator for a radius of 1175.46125km, we get a low end of 5029000 megatons and a high end of 385290000 megatons, or 5.029000 teratons and 385.290000 teratons respectively.

Next for the speed of the lasers (remember again that this was a low end, and the lasers flew this distance in a fraction of a second.

T = 16691.5498km/1s

= 16691549.8/340.29

= >Mach 49050.9559

Let's also get the cruising speed of the ship.

T = 916.85978km/1s

= 916859.78/340.29

= Mach 2694.34829

Ships shoots planet = >Mach 35240.726

Bombardment explosion on first planet (low end) = 7.710 teratons

Bombardment explosion on first planet (low end) = 548.49 teratons

Giant ship length = 61429.605km

Bombardment explosion on second planet (low end) = 5.029 teratons

Bombardment explosion on second planet (high end) = 385.29 teratons

Giant ship shoots second planet = >Mach 49050.956

Giant ship cruising speed = Mach 2694.348

There's also the kinetic energy the giant ship would generate, but unfortunately we can't see the other side of the ship, and thus can't scale its full dimensions.]]>

Spinel's Injector height = 124.46m

Spinel's injector mass (empty) = 79283564 kg

Spinel's injector mass (full) = 96906988kg

Spinel punches Steven (energy) = 28.601 tons of TNT

Spinel punches Steven (speed) = Mach 1.115

Steven lifts Spinel's injector = 0.023 tons of TNT

Spinel's injector explodes = 15.985 tons of TNT

Not the greatest feats gems have demonstrated in terms of strength, speed and lifting, but it's consistent so it's nice. Keep in mind that Spinel is the equivalent of a Jester with no known combat training.]]>

V = 6.061e+8 X 0.3048

= 184739280m^3

Newly fallen snow weighs between 70kg to 150kg per m^3 (or an average of 110kg), while snowpacks range from 200kg to 300kg per m^3 (or an average of 250kg).

https://www.islandnet.com/~see/weather/almanac/arc2007/alm07feb.htm

M = 184739280 X 110

= 20321320800kg

(High end)

M = 184739280 X 250

= 46184820000kg

This scene if I recall correctly took place before Christas and Winter, so is likely at some point in Autumn, the temperatures of Autumn being variable, and an average will be gathered below (from the temperatures in celcius).

T = −18 + 21 + 21 + 22 + 24 + 32 + 34 + 37 + 38

= 211/9

= 23.4444444

Specific heat of air between 0 and 40 degrees celsius is 1.005 kilojoules. We can also add the heat fusion of oxygen, which is is 13800 joules/kg.

(Low end)

E = 23.4444444 X 1.005 X 20321320800

= 4.78804186e11 kilojoules

= 4.78804186e14 joules

E = 20321320800 X 13800

= 2.80434227e14 joules

E = 4.78804186e14 + 2.80434227e14

= 7.59238413e14 joules

= 181.462335803059261 kilotons

(High end)

E = 23.4444444 X 1.005 X 46184820000

= 1.08819133e12 kilojoules

= 1.08819133e15 joules

E = 46184820000 X 13800

= 6.37350516e14 joules

E = 1.08819133e15 + 6.37350516e14

= 1.72554185e15 joules

= 412.4144000956022751 kilotons

Shadow thinks of snow (low end) = 181.462 kilotons

Shadow thinks of snow (high end) = 412.414 kilotons

The detonation of the Klaxosaur Bomb causes an explosion seen all the way back on Earth. Strelizia True Apus is noted to be so far from Earth that there are no recognisable stars, and the sky and perspective is completely different (there are also noticably more stars in the sky than in space in the Solar System).

The light is clearly visible in the middle of the day and from across the Universe, which would mean if'd have to be at least comparable to the luminousity of the Sun, with the apparent magnitude of the Sun being -26.74. The furthest star visible to the naked eye is Casopiea, 16,308 lightyears away (or 1.54282297e20m).

-26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(1.54282297e20))^2)

(146000000000/(1.54282297e20))^2) = 8.9551635e-19

-26.74 - -26.73 = 8.9551635e-19/((L/3.846*10^26)

-0.01 = -2.5Log(8.9551635e-19/((L/3.846*10^26))

-0.01/-2.5 = (8.9551635e-19/((L/3.846*10^26))

10^(0.004) = (8.9551635e-19/((L/3.846*10^26))

1.00925289 = (8.9551635e-19/((L/3.846*10^26))

1.00925289 X (3.864*10e26) = 9.46317256e-10

3.89975317e27/8.9551635e-19 = 4.12097861e36 joules

The light lasts three days.

T = 60 X 60 X 24 X 3

= 259200s

The light lasts 3 days.

E = 4.35475374e45 X 259200

= 1.12875217e51/10^44

= 11.2875217 MEGAFOE

Final Results

Klaxosaur Bomb = 11.288 MEGAFOE

Strelizia True Apus spams a ton of beams real fast. More or less straight forward. Previously I calced Strelizia Apus' arm protectors to be 85840.8839m long.

144 pixels = 85840.8839m

1 pixel = 85840.8839m/144 = 596.117249m

596.117249m X 1732 = 1032475.08m

Timeframe is 1 frame.

T = 1s/24

= 41.6666667ms

= 1032475.08m/41.6666667ms

= 24779401.9/340.29

= Mach 72818.4839

Strelizia True Apus' beam spam = Mach 72818.484

Homer Simpson accidentally causes a test simulation to melt into the ground, which he quite literally shakes off a few seconds later. Also of note...

https://www.simpsonsarchive.com/episodes/1F02.html

1586 pixels = 180.34cm

1 pixel = 180.34cm/1586 = 0.11370744cm

0.11370744cm X 492 = 55.9440605cm

230 pixels = 55.9440605cm

1 pixel = 55.9440605cm/230 = 0.243235046cm

0.243235046cm X 184 = 44.7552485cm

63 pixels = 44.7552485cm

1 pixel = 44.7552485cm/63 = 0.71040077cm

0.71040077cm X 464 = 329.625957cm

0.71040077cm X 1317 = 935.597814cm

1077 pixels = 935.597814cm

1 pixel = 935.597814cm/1077 = 0.868707348cm

0.868707348cm X 258 = 224.126496m

0.868707348cm X 335 = 291.016962cm

And on top of that, given we can no longer see the inspection van, we can add its height too as it would have sunk below that.

H = 329.625957 + 224.126496m

= 553.752453cm

Volume of the area as a rectangular prism.

V = lhw

= 935.597814 X 291.016962 X 553.752453

= 150772857cm^3

Energy to melt rock is 4350 joules per cm^3.

E = 150772857 X 4350

= 655861927950 joules

= 156.754762894359 tons of TNT

Homer fails inspection = 156.755 tons of TNT

Chlorophytum blasts open the way, melting a heap of rubble in the way. However, this leaves her depowered and even turns Ikuno's hair white, so this should be the absolute maximum output of Chlorophytum and most other non-Strelizia mechs (outside the Nine Models and the Space Franxx). Previously I calced Strelizia to be 54.969m tall.

550 pixels = 54.969m

1 pixel = 54.969m/550 = 0.0999436364m

0.0999436364m X 50 = 4.99718182m

Scaling from Strelizia to Delpinium to the corridor.

364 pixels = 4.99718182m

1 pixel = 4.99718182m/364 = 0.0137285215m

0.0137285215m X 564 = 7.74288613m

173 pixels = 7.74288613m

1 pixel = 7.74288613m/173 = 0.0447565672m

0.0447565672m X 2662 = 119.141982m

Now to scaling the dimensions of the attack.

1199 pixels = 119.141982m

1 pixel = 119.141982m/1199 = 0.0993677915m

0.0993677915m X 941 = 93.5050918m

93.5050918m/2 = 46.7525459m

= 0.539683688 rad

= 30.9215975945318178 degrees

Enter that through the angscaler and the closer end of the melted rubble is 169.03m away.

= 0.251446322 rad

= 14.4068130247232382 degrees

The hole at the further end of the tunnel is 369.91m away. Now we can get the total length of the melted metal.

L = 369.91m - 169.03m

= 200.88m

Volume of the tunnel as a cylinder (obviously).

V = πr^2h

= π X 46.7525459^2 X 200.88

= 1379421.86m^3

= 1379421860000cm^3

Energy to melt steel is 7309.87 joules/cm^3.

E = 1379421860000 X 7309.87

= 1.00833945e16 joules

= 2.4099891252390057694 megatons

Chlorophytum blasts opens a path = 2.41 megatons

Stelitzia rams Hringhorni through the VIRM fleets and into the VIRM home planet at incredible speeds. Thankfully, we already have the dimensions for Strelizia Apus sorted, but now we need Hringhorni's dimensions. This should be much easier than Strelizia Apus's dimensions. Strelizia Apus' arm protectors are 85840.8839m long, and those on Strelizia True Apus should be a similar length.

505 pixels = 85840.8839m

1 pixel = 85840.8839m/505 = 169.981948m

169.981948m X 2166 = 368180.899m

169.981948m X 123 = 20907.7796m

36 pixels = 20907.7796m

1 pixel = 20907.7796m/36 = 580.771656m

580.771656m X 1096 = 636525.735m

580.771656m X 276 = 160292.977m

It's not a perfect triangle, but given there's also other pyramidal parts sticking out, I figures it'd even out.

503 pixels = 160292.977m

1 pixel = 160292.977m/503 = 318.673911m

318.673911m X 92 = 29317.9998m

With all that done, let's get our volume by adding all three triangular parts together as triangular pyramids. To get that though, we need the area of the triangle first.

A = hbb/2

= 636525.735 X 160292.977/2

= 5.10153025e10m^2

V = 1/3AH

= 1/3 X 5.10153025e10 X 29317.9998

= 4.98555543e14 X 3

= 1.49566663e15m^3

Now for the shaft.

812 pixels = 636525.735

1 pixel = 636525.735/812 = 783.898688m

783.898688m X 319 = 250063.681m

783.898688m X 32 = 25084.758m

25084.758m/2 = 12542.379m

Volume as a cylinder.

V = πr^2h

= π X 12542.379^2 X 250063.681

= 1.23583455e14m^3

There are other bits too, but...eh. Let's get our total volume.

V = 1.49566663e15 + 1.23583455e14

= 1.61925008e15m^3

Hringhorni is made out of Klaxosaur cores, which are composed of some form of weird goo, so we'll go with the mass of water, that being 1000kg/m^3.

M = 1.61925008e15 X 1000

= 1.61925008e18kg

As previously caclulated, Strelizia Apus weighs 7.2176079e18kg, and Strelizia True Apus should weigh the same.

M = 7.2176079e18 + 1.61925008e18

= 8.83685798e18kg

Now all that's left is the easy, fun part!

43 pixels = 368180.899m

1 pixel = 368180.899m/43 = 8562.34649m

8562.34649m X 1349 = 11550605.4m

Timeframe is 3 seconds.

852 pixels = 11550605.4m

1 pixel = 11550605.4m/852 = 13557.0486m

13557.0486m X 695 = 9422148.78m

T = 9422148.78m/3s

= 3140716.26/340.29

= Mach 9229.52852

At these velocities, we can just start to apply relativistic kinetic energy, so we enter the above values into the relativistic kinetic energy calculator and get a result of 4.359E+31 joules, or 10.418260038240916288 zettatons.

Strelizia True Apus rams the VIRM planet (speed) = Mach 9229.529

Strelizia True Apus rams the VIRM planet (energy) = 10.418 zettatons

Strelizia Apus' size = 331.891712km

Strelizia Apus' mass = 7217607900000000 tons

I'm not sure if the scaling is entirely accurate, but given there'd be a lot more unseen machinery (such as under the back part where we can see some engines) it would be even greater in mass, though that's the best I can do with what I've got. Strelizia True Apus would be equal in size and mass.]]>

Zero-Two's mind's connected to Strelitzia Apus, which is in Mars orbit, and cuts on her appear whenever she's attacked by VIRM ships. Lot's of scaling, so let's get to calcing!

VIRM ships attack Strelitzia Apus (low end) = 391.063 petatons

VIRM ships attack Strelitzia Apus (mid end) = 6.641 exotons

VIRM ships attack Strelitzia Apus (high end) = 21.094 exotons

VIRM explosions (low end) = 45.531 C

VIRM explosions (mid end) = 187.63 C

VIRM explosions (high end) = 1337.592 C

Streliztia gets rammed by a Gutenburg class Klaxosaur with enough force to create a colossal dust cloud that dwarves the nearby plantations. Plantations have a height of 1200m.

That makes our job a lot easier. Now, to scaling!

509 pixels = 1200m

1 pixel = 1200m/509 = 2.35756385m

2.35756385m X 639 = 1506.4833m

1506.4833m/2 = 753.24165m

2.35756385m X 1459 = 3439.68566m

3439.68566m/2 = 1719.84283m

2.35756385m X 1590 = 3748.52652m

3748.52652m/2 = 1874.26326m

2.35756385m X 375 = 884.086444m

884.086444m/2 = 442.043222m

Volume of both parts as ellipsoids.

V = 4/3πabc

= 4/3 X π X 753.24165 X 1719.84283 X 753.24165

= 4.08738947e9m^3

V = 4/3πabc

= 4/3 X π X 1874.26326 X 442.043222 X 442.043222

= 1.53408235e9m^3

V = 4.08738947e9 + 1.53408235e9

= 5621471820m^3

Weight of a dust cloud/air is 1.003kg/m^3.

M = 5621471820 X 1.003

= 5.63833624e9kg

Next for our timeframe.

2 seconds and 17 frames.

T = 1s/24

= 41.6666667ms X 17

= 0.708333334s + 2s

= 2.70833333s

T = 3748.52652m/2.70833333s

= 1384.07133m/s

Now for the final step, to get our kinetic energy.

KE = (0.5)mv^2

= (0.5) X 5.63833624e9 X 1384.07133^2

= 5.40054913e15 joules

= 1.290762220363288693 megatons

Gutenburg-class Klaxosaur rams Strelitzia = 1.291 megatons